两个 SQL 查询中的值之间的差异

Question

我在获取来自两个不同 sql 查询的值之间的实际差异时遇到问题。例如：

查询 1：

SELECT x from db1 where date = 'mm-dd-yy'

查询 2:

SELECT x from db1 where date = 'mm1-dd1-yy'

每次查询returns 10 个不同的值。我想要一个查询 returns 两个查询中值之间的实际差异（来自 Q1 的 Value1 - 来自 Q2 的 Value1，对于 value2 类似等等）尝试了 EXCEPT 但这不起作用。有什么建议吗？

Answer 1

试试这样的东西：

Select  x-x2 from
(
(SELECT c1,(case when date = 'mm1-dd1-yy' then c11 end)as x2,x from kdue)
)as y
where date = 'mm1-dd1-yy'

Answer 2

如果我理解正确的话，请看下面的方法是否适合你。

select value1_From_QRY1-value1_From_QRY2 from (
   select row_cnt,sum(val1) as value1_From_QRY1,sum(va2) as value1_From_QRY2 from 
    (SELECT ROWNUM as row_cnt,x as val1 ,0 as val2 from db1 where date = 'mm-dd-yy' 
     union all
    SELECT ,ROWNUM ,0,x from db1 where date = 'mm1-dd1-yy')
   group by row_cnt)

Answer 3

SELECT A.x1- B.x2 AS Difference FROM

(

(SELECT c, x1 from db1 where date = 'mm-dd-yy') AS A

JOIN

(SELECT c, x2 from db1 where date = 'mm1-dd1-yy') AS B

ON B.c = A.c

ORDER BY A.c, B.c

两个 SQL 查询中的值之间的差异

Difference between values in two SQL queries

sql-server

difference