如何从 os.system() 获取输出？

Question

我想从 os.system("nslookup google.com") 获得输出，但在打印时我总是得到 0。为什么会这样，我该如何解决？ (Python 3, Mac)

(看了How to store the return value of os.system that it has printed to stdout in python? - 但是没看懂~我是新手python)

Answer 1

使用subprocess:

import subprocess
print(subprocess.check_output(['nslookup', 'google.com']))

如果 return 代码不为零，它将引发 CalledProcessError 异常：

try:
    print(subprocess.check_output(['nslookup', 'google.com']))
except subprocess.CalledProcessError as err:
    print(err)

os.system only returns the exit code of the command. Here 0 means success. Any other number stands for an operating-system-dependent error. The output goes to stdout of this process. subprocess 打算取代 os.system.

subprocess.check_output is a convenience wrapper around subprocess.Popen 可简化您的用例。

如何从 os.system() 获取输出？

How to get the output from os.system()?

python

subprocess

os.system