FPDF error: Unsupported image type: image/jpeg

Question

if(isset($_POST['sumit']))
  { 

   $con = mysqli_connect("localhost","root","","school");
       if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  } 

 $sname=$_POST['sname'];
  $category=$_POST['category'];
 $sadd=$_POST['sadd'];
 $file_name=$_FILES['file']['name'];
  $temp_name=$_FILES['file']['tmp_name'];
  $file_size = $_FILES['file']['size'];
 $file_type = $_FILES['file']['type'];

   $target_path  =  "Newfolder1";
$sql="SELECT * FROM imagetable WHERE   sname='$sname' and sadd='$sadd'and category='$category' and file='$target_path'";
 $result1 = mysqli_query($con, $sql);
  if(!mysqli_query($con, $sql)){
                die( "Could not execute sql: $sql"); 
                 }
$row = mysqli_fetch_row($result1);
$file=$row[0];


  $pdf=new fpdf();
$pdf->ADDPage();
$pdf->setfont('Arial','B', 16);

$pdf->Image($file,150,25,50,20,$file_type);


$pdf->Cell(0,10,'id',0,1);
$pdf->Cell(0,10,'sadd',0,1);
$pdf->Cell(0,10,'category',0,1);
$pdf->Cell(0,10,'sname',0,1);

$pdf->Output();}

这是给我图像类型，但所有这些都是通过数据库完成的我的图像类型是在数据库中定义的，但我不知道。我收到了错误。如果有人能找出错误，请回复

Answer 1

$pdf->Image("image/$user-signature.png" ,100, 213,-300);

这种格式适合我。尝试删除 $file 并在 $filetype

周围加上引号

Answer 2

问题是，您在 $file_type 变量（如 image/png 或 image/jpeg）中指定 MIME 类型，并在 Image() 方法中使用它。您应该只指定图像格式。可能的值为（不区分大小写）：JPG、JPEG、PNG 和 GIF。

所以先获取图片格式，像这样：

$image_format = strtolower(pathinfo($_FILES['file']['name'], PATHINFO_EXTENSION));

然后像这样调用 Image() 方法：

$pdf->Image($file,150,25,50,20,$image_format);

已编辑：

像这样更改您的 INSERT 查询，

$image_path = $target_path . DIRECTORY_SEPARATOR . $file_name;
if(move_uploaded_file($temp_name, $image_path)) { 
    $qry="INSERT INTO imagetable (file, sname, category, sadd, type,size, content ) values ('".$image_path."','".$sname."','".$category."','".$sadd."', '".$file_type."','".$file_size."', '".$Content."')"; 
    mysqli_query($con,$qry) or die("error in $qry == ----> ".mysqli_error()); 
}

并像这样更改您的 SELECT 语句，

// your code    

$target_path = "Newfolder1" . DIRECTORY_SEPARATOR . $file_name;
$sql="SELECT * FROM imagetable WHERE   sname='$sname' and sadd='$sadd'and category='$category' and file='$target_path'";

// your code

FPDF error: Unsupported image type: image/jpeg

FPDF error: Unsupported image type: image/jpeg

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