在函数c++中调用函数
calling a function in a function c++
我好像想不通。我想做的是声明三个函数。接受用户输入值 "balance" 的一种。另一个显示菜单。我想在 "main" 函数中调用这些函数,并希望从函数 "balanceAcquired" 中输入 "balance"。
我是 C++ 的新手,所以我的代码可能草率,但我遇到的错误是
error C4716: 'balanceAcquire': 必须 return 一个值
error C4716: 'menu' : 必须 return 一个值
错误 c4700:使用了未初始化的局部变量 'balance'
// check book balancing program
//header files
#include <iostream>
#include <iomanip>
#include <cmath>
#include <cstdio>
using namespace std;
int balanceAcquire(){
float balance; // balance entered by user
// acquire balance
cout << "check book balancing program \n\n";
cout << "Enter the beginning balance: ";
cin >> balance;
}
int menu(){
//menu
cout << "Commands: \n"; // commands
cout << "C - process a check\n"; // process a check
cout << "D - process a deposit\n"; // process a deposit
cout << "E - End the program\n"; // end the program
}
int main(){
// define variables
const float fee = .25; // fee for transaction
float check, // check amount
deposit, // deposit amount
balance; // balance amount
char choice; // user entered choice
float serviceCharges = 0; // service charges amount tally
// initiate program
balanceAcquire();
menu();
cout << "Enter transaction type: " << endl; // ask for a choice
cin >> choice; // choice type
switch (choice) {
case 'c':
cout << "Enter transaction amount: " << endl;
cin >> check;
cout << "Processing check for" << check << endl;
balance -= check;
cout << "Balance: " << setprecision(2) << balance << endl;
cout << "Service charge: $.25 for a check" << endl;
serviceCharges += fee;
cout << "Total service charges: " << serviceCharges << "\n\n";
break;
case 'd':
cout << "Enter transaction amount: " << endl;
cin >> deposit;
cout << "Processing deposit for" << deposit << endl;
balance += deposit;
cout << "Balance: " << setprecision(2) << balance << endl;
cout << "Total service charges: " << serviceCharges << "\n\n";
break;
case 'e':
cout << "Processing end of month" << endl;
balance -= serviceCharges;
cout << "Final Balance: $" << balance << endl;
break;
}
}
除其他外,我尝试以这种方式写出来的全部目的是这样我可以 return 到 "menu" 允许用户 select 更多存款或支票输入并在最后收到最终余额减去交易费用。
编辑 1:格式化
跟着错误走就行了。
error C4716: 'balanceAcquire': must return a value
int balanceAcquire() {
*** <== declared to return int, no return in body
error C4716: 'menu' : must return a value
int menu() {
*** <== declared to return int, no return in body
error c4700: uninitialized local variable 'balance' used
在您的主函数中,您的代码如下所示:
float balance;
// [ snip ]
balance -= check;
balance += deposit;
balance -= serviceCharges;
这是未定义的行为,您必须在读取之前将 balance
初始化为某个值。可能您想将其分配给 balanceAcquire()
的 return 值,他们应该 return a float
:
balance = balanceAcquire();
通过阅读您的代码,我得出的结论是您没有掌握函数调用的工作原理。一言以蔽之:
函数体只能与其签名中存在的内容以及全局状态进行交互。他们不会从调用者那里隐式继承任何东西。
比如你想让balanceAcquire()
影响"outside",即main()
,你需要自己接管。
第一种方式:
int balanceAcquire() {
float b;
//...
cin >> b;
return b;
}
函数returns值。在外部,您可以通过使用函数调用表达式作为值来取回它:
int main() {
float balance;
//...
balance = balanceAcquire();
// balance is set.
}
第二种方式:
void balanceAcquire(float &b) {
//...
cin >> b;
}
函数returns什么都没有(因此void
),但是通过引用(&
)传入b
,这意味着它可以直接访问来自外部的变量。
int main() {
float balance;
//...
balanceAcquire(balance);
// balance is set.
}
我好像想不通。我想做的是声明三个函数。接受用户输入值 "balance" 的一种。另一个显示菜单。我想在 "main" 函数中调用这些函数,并希望从函数 "balanceAcquired" 中输入 "balance"。
我是 C++ 的新手,所以我的代码可能草率,但我遇到的错误是
error C4716: 'balanceAcquire': 必须 return 一个值
error C4716: 'menu' : 必须 return 一个值
错误 c4700:使用了未初始化的局部变量 'balance'
// check book balancing program
//header files
#include <iostream>
#include <iomanip>
#include <cmath>
#include <cstdio>
using namespace std;
int balanceAcquire(){
float balance; // balance entered by user
// acquire balance
cout << "check book balancing program \n\n";
cout << "Enter the beginning balance: ";
cin >> balance;
}
int menu(){
//menu
cout << "Commands: \n"; // commands
cout << "C - process a check\n"; // process a check
cout << "D - process a deposit\n"; // process a deposit
cout << "E - End the program\n"; // end the program
}
int main(){
// define variables
const float fee = .25; // fee for transaction
float check, // check amount
deposit, // deposit amount
balance; // balance amount
char choice; // user entered choice
float serviceCharges = 0; // service charges amount tally
// initiate program
balanceAcquire();
menu();
cout << "Enter transaction type: " << endl; // ask for a choice
cin >> choice; // choice type
switch (choice) {
case 'c':
cout << "Enter transaction amount: " << endl;
cin >> check;
cout << "Processing check for" << check << endl;
balance -= check;
cout << "Balance: " << setprecision(2) << balance << endl;
cout << "Service charge: $.25 for a check" << endl;
serviceCharges += fee;
cout << "Total service charges: " << serviceCharges << "\n\n";
break;
case 'd':
cout << "Enter transaction amount: " << endl;
cin >> deposit;
cout << "Processing deposit for" << deposit << endl;
balance += deposit;
cout << "Balance: " << setprecision(2) << balance << endl;
cout << "Total service charges: " << serviceCharges << "\n\n";
break;
case 'e':
cout << "Processing end of month" << endl;
balance -= serviceCharges;
cout << "Final Balance: $" << balance << endl;
break;
}
}
除其他外,我尝试以这种方式写出来的全部目的是这样我可以 return 到 "menu" 允许用户 select 更多存款或支票输入并在最后收到最终余额减去交易费用。
编辑 1:格式化
跟着错误走就行了。
error C4716: 'balanceAcquire': must return a value
int balanceAcquire() {
*** <== declared to return int, no return in body
error C4716: 'menu' : must return a value
int menu() {
*** <== declared to return int, no return in body
error c4700: uninitialized local variable 'balance' used
在您的主函数中,您的代码如下所示:
float balance;
// [ snip ]
balance -= check;
balance += deposit;
balance -= serviceCharges;
这是未定义的行为,您必须在读取之前将 balance
初始化为某个值。可能您想将其分配给 balanceAcquire()
的 return 值,他们应该 return a float
:
balance = balanceAcquire();
通过阅读您的代码,我得出的结论是您没有掌握函数调用的工作原理。一言以蔽之:
函数体只能与其签名中存在的内容以及全局状态进行交互。他们不会从调用者那里隐式继承任何东西。
比如你想让balanceAcquire()
影响"outside",即main()
,你需要自己接管。
第一种方式:
int balanceAcquire() {
float b;
//...
cin >> b;
return b;
}
函数returns值。在外部,您可以通过使用函数调用表达式作为值来取回它:
int main() {
float balance;
//...
balance = balanceAcquire();
// balance is set.
}
第二种方式:
void balanceAcquire(float &b) {
//...
cin >> b;
}
函数returns什么都没有(因此void
),但是通过引用(&
)传入b
,这意味着它可以直接访问来自外部的变量。
int main() {
float balance;
//...
balanceAcquire(balance);
// balance is set.
}