PHP综合对象差异函数

Question

有谁知道 php 函数可以接受两个对象并 return 将一整套差异作为一个对象返回？

我将使用 json 编码数据作为我要完成的示例：

对象 A：

{
    "Name":"Original",
    "Id": 5,
    "Data":{
        "Value1": 1,
        "Value2": [
            5, 7, 8, 10
        ],
        "Value3": {
            "Exists": true
        }
    }
}

对象 B：

{
    "Name":"ThisNameChanged",
    "Id": 5,
    "Data":{
        "Value1": 7,
        "Value2": [
            5, 8, 9
        ],
        "Value3": {
            "Exists": true
        }
    }
}

会 return:

{
    "Name":"ThisNameChanged",
    "Data":{
        "Value2": {
            "1": 8,
            "2": 9
        }
    }
}

如果不存在这样的函数（我猜很有可能），我该如何编写一个函数来执行此操作？谁能提供一个例子或功能？

Answer 1

这是您要求的函数的一些简单示例，

但还不够完美，仅供大家深思：

function objDiff ($obj1, $obj2) {
        $diff=array();
    $obj1Arr = (array)$obj1;
    $obj2Arr = (array)$obj2;

    foreach ($obj1Arr as $key=>$val) {

        if (!(isset($obj2Arr[$key]) && $obj2Arr[$key]===$val  )) {
            if (gettype($val)=='object') {

                if (isset($obj2Arr[$key])) {
                    if (gettype($obj2Arr[$key])=='object') {
                        $subDiff = objDiff($val,$obj2Arr[$key]);
                        $diff[$key]=$subDiff;
                    } else {
                        $diff[$key]=array($val,$obj2Arr[$key]);
                    }
                } else {
                    $diff[$key]=array($val,$obj2Arr[$key]);
                }
            } else {
                $diff[$key]=array($val,(isset($obj2Arr[$key]))?$obj2Arr[$key]:null);
            }
        }
    }
    return $diff;
}

使用此数据：

$obj1 = new stdClass();
    $obj1->test1 = 1;
    $obj1->test2 = 2;
       $subObj = new stdClass();
    $subObj->test1 = 1;
    $subObj->test2 = 2;
    $obj1->test3 = $subObj;
        $obj2 = new stdClass();
    $obj2->test1 = 3;
    $obj2->test2 = 4;
    $subObj = new stdClass();
    $subObj->test1 = 3;
    $subObj->test2 = 2;
    $obj2->test3 = $subObj;

 print_r(objDiff($obj1,$obj2) );

它returns:

Array
(
    [test1] => Array
        (
            [0] => 1
            [1] => 3
        )

    [test2] => Array
        (
            [0] => 2
            [1] => 4
        )

    [test3] => Array
        (
            [test1] => Array
                (
                    [0] => 1
                    [1] => 3
                )

        )

)

Answer 2

感谢 Kim Alexander，我能够编写代码来完成我想要做的事情。

function objDiff($obj1, $obj2, $diff = null) {
    if (is_null($diff))
        $diff = new stdClass;

    $obj1Arr = (array)$obj1;
    $obj2Arr = (array)$obj2;

    foreach($obj1Arr as $key => $val) {
        if (isset($obj2Arr[$key]))
        {
            if ($obj2Arr[$key] != $val)
            {
                if (is_object($obj2Arr[$key]) && is_object($val))
                    $diff->$key = objDiff($val, $obj2Arr[$key]);
                else
                    $diff->$key = $obj2Arr[$key];
            }
        }
    }
    return $diff;
}

PHP综合对象差异函数

PHP Comprehensive Object Difference Function

php

object

recursion

comparison