PHP PDO 将数组转换为不同的格式
PHP PDO Convert array to different format
我正在尝试使用未弃用的技术和 php pdo:
转换通过以下代码获得的数组
$stm = $conn->prepare("SELECT * FROM mysqltable");
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
print_r($results);
要使用的 fusioncharts 需要以下格式
[
{
label: "CJ Anderson",
value: "25"
},
{
label: "Imran Tahir",
value: "25"
},
...
...
]
原数组如下：
Array (
[0] => Array (
[Id] => 6
[Number] => 1234567890
[Visits] => 1
[Name] => John
)
[1] => Array (
[Id] => 7
[Number] => 1236549871
[Visits] => 9
[Name] => Jerry
)
[2] => Array (
[Id] => 8
[Number] => 2147483647
[Visits] => 3
[Name] => Jane
)
)
如有任何帮助，我们将不胜感激。
编辑：
正如我在下面评论的那样。如果您手动输入数据，我有一个完整的 php 文件。但是，当我将 $jsonEncodedData 放入时，我无法让它工作。想法？
<html>
<head>
<title>FusionCharts XT - Column 2D Chart - Data from a database</title>
<link rel="stylesheet" type="text/css" href="css/style.css" />
<!-- You need to include the following JS file to render the chart.
When you make your own charts, make sure that the path to this JS file is correct.
Else, you will get JavaScript errors. -->
<script src="fusioncharts/js/fusioncharts.js"></script>
</head>
<body>
<?php
try {
# MySQL with PDO_MYSQL
$mysql_host = 'host';
$mysql_database = 'table';
$mysql_username = 'user';
$mysql_password = 'pass';
$conn = new PDO("mysql:host=$mysql_host; dbname=$mysql_database", $mysql_username, $mysql_password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$conn->exec("SET CHARACTER SET utf8"); // Sets encoding UTF-8
}
catch(PDOException $e) {
echo $e->getMessage();
}
// Form the SQL query that returns the top 10 most populous countries
// Execute the query, or else return the error message.
$stm = $conn->prepare("SELECT Name, Visits FROM mysqltable"); //WHERE Area :SelArea");
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
include("fusioncharts.php");
$jsnarray = array();
foreach($results as $k => $v){
$jsnarray[] = array('label' => $results[$k]['Name'], 'value' => $results[$k]['Visits']);
};
$jsonEncodedData=json_encode($jsnarray);
new FusionCharts("type of chart",
"unique chart id",
"width of chart",
"height of chart",
"div id to render the chart",
"type of data",
"actual data");
$columnChart = new FusionCharts(
"column2d",
"ex1" ,
"600",
"400",
"chart-1",
"json",
'{
"chart":
{
"caption":"Harry\'s SuperMart",
"subCaption":"Top 5 stores in last month by revenue",
"numberPrefix":"$",
"theme":"ocean"
},
"data": //$jsonEncodedData}'); <---I tried to insert this after "data":but no results unlike if you put raw data**
[
{
"label":"Bakersfield Central",
"value":"880000"
},
{
"label":"Garden Groove harbour",
"value":"730000"
},
{
"label":"Los Angeles Topanga",
"value":"590000"
},
{
"label":"Compton-Rancho Dom",
"value":"520000"
},
{
"label":"Daly City Serramonte",
"value":"330000"
}
]
}');
// Render the chart
$columnChart->render();
?>
<div id="chart-1"><!-- Fusion Charts will render here--></div>
</body>
</html>
==============编辑 12/28/15==========
尝试了以下代码但没有结果，我的问题是我们不应该按照他们的要求以“}”结尾：
$columnChart = new FusionCharts(
"column2d",
"ex1" ,
"600",
"400",
"chart-1",
"json",
'{
"chart":
{
"caption":"Harry\'s SuperMart",
"subCaption":"Top 5 stores in last month by revenue",
"numberPrefix":"$",
"theme":"ocean"
},
"data": ' . $jsonEncodedData);
//}';
// Render the chart
print_r($columnChart);
$columnChart->render();
?>
<div id="chart-1"><!-- Fusion Charts will render here--></div>
</body>
</html>
我想 post "manual" 方法和“fetch 方法”之间的数组差异（在此编辑的上方）。
获取：
FusionCharts Object ( [constructorOptions:FusionCharts:private] => Array ( >[type] => column2d [id] => ex1 [width] => 600 [height] => 400 [renderAt] => >chart-1 [dataFormat] => json [dataSource] => { "chart": { >"caption":"Harry's SuperMart", "subCaption":"Top 5 stores in last month by >revenue", "numberPrefix":"$", "theme":"ocean" }, "data": >[{"label":"John","value":"125"},{"label":"Jerry","value":"125"},{"label":"Jane","value":"125"}] ) [constructorTemplate:FusionCharts:private] => >[renderTemplate:FusionCharts:private] => )
使用手动方法（有效）：
FusionCharts Object ( [constructorOptions:FusionCharts:private] => Array ( >[type] => column2d [id] => ex1 [width] => 600 [height] => 400 [renderAt] => >chart-1 [dataFormat] => json [dataSource] => { "chart": { >"caption":"Harry's SuperMart", "subCaption":"Top 5 stores in last month by >revenue", "numberPrefix":"$", "theme":"ocean" }, "data": [ { >"label":"Bakersfield Central", "value":"880000" }, { "label":"Garden Groove >harbour", "value":"730000" }, { "label":"Los Angeles Topanga", >"value":"590000" }, { "label":"Compton-Rancho Dom", "value":"520000" }, { >"label":"Daly City Serramonte", "value":"330000" } ] } ) >[constructorTemplate:FusionCharts:private] => >[renderTemplate:FusionCharts:private] => )
我立即看到两个不同之处，手册在 "data" 和结束 } 参数周围插入空格。
有一种自动（并且更简单）的方法可以做到这一点：
$stm = $conn->prepare('SELECT Name AS label, Visits AS value FROM mysqltable;');
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
$jsonEncodedData = json_encode($results);
echo $jsonEncodedData;
输出（本地测试）：
[{"label":"Foo","value":"5"},{"label":"Bar","value":"15"}]
这样你就可以像这样使用它了:
$columnChart = new FusionCharts('...
...
"data": ' . $jsonEncodedData . '}');
注意最后的. '}'
编辑前：
你可以这样做：
// This part is just for running purposes
$foo = array (
0 => Array (
'Id' => 6,
'Number' => 1234567890,
'Visits' => 1,
'Name' => 'John'
),
1 => array (
'Id' => 7,
'Number' => 1236549871,
'Visits' => 9,
'Name' => 'Jerry'
),
2 => array (
'Id' => 8,
'Number' => 2147483647,
'Visits' => "3", // Example to output quoted
'Name' => 'Jane'
)
);
$bar = array();
foreach($foo as $k => $v){
$bar[] = array('label' => $foo[$k]['Name'], 'value' => $foo[$k]['Visits']);
}
echo json_encode($bar);
输出：
[{"label":"John","value":1},{"label":"Jerry","value":9},{"label":"Jane","value":"3"}]
在一行中与你的（来自问题）进行比较：
[{label: "CJ Anderson",value: "25"},{label: "Imran Tahir",value: "25"},...]
注：我假设value由Visit表示，label由Name表示。
详细了解 json_encode。
作为总结，这是解决问题的部分，包括 FirstOne 的 foreach 语句：
$stm = $conn->prepare("SELECT Name, Visits FROM mysqltable"); //WHERE Area :SelArea");
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
include("fusioncharts.php");
$jsnarray = array();
foreach($results as $k => $v){
$jsnarray[] = array('label' => $results[$k]['Name'], 'value' => $results[$k]['Visits']);
};
$jsonEncodedData=json_encode($jsnarray);
//print_r($jsonEncodedData);
new FusionCharts("type of chart",
"unique chart id",
"width of chart",
"height of chart",
"div id to render the chart",
"type of data",
"actual data");
$columnChart = new FusionCharts(
"column2d",
"ex1" ,
"600",
"400",
"chart-1",
"json",
'{
"chart":
{
"caption":"Harry\'s SuperMart",
"subCaption":"Top 5 stores in last month by revenue",
"numberPrefix":"$",
"theme":"ocean"
},
"data": ' . $jsonEncodedData . '}');
// Render the chart
print_r($columnChart);
$columnChart->render();
?>
<div id="chart-1"><!-- Fusion Charts will render here--></div>
</body>
</html>
感谢大家帮忙解决问题
我正在尝试使用未弃用的技术和 php pdo:
转换通过以下代码获得的数组$stm = $conn->prepare("SELECT * FROM mysqltable");
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
print_r($results);
要使用的 fusioncharts 需要以下格式
[
{
label: "CJ Anderson",
value: "25"
},
{
label: "Imran Tahir",
value: "25"
},
...
...
]
原数组如下：
Array (
[0] => Array (
[Id] => 6
[Number] => 1234567890
[Visits] => 1
[Name] => John
)
[1] => Array (
[Id] => 7
[Number] => 1236549871
[Visits] => 9
[Name] => Jerry
)
[2] => Array (
[Id] => 8
[Number] => 2147483647
[Visits] => 3
[Name] => Jane
)
)
如有任何帮助，我们将不胜感激。
编辑： 正如我在下面评论的那样。如果您手动输入数据，我有一个完整的 php 文件。但是，当我将 $jsonEncodedData 放入时，我无法让它工作。想法？
<html>
<head>
<title>FusionCharts XT - Column 2D Chart - Data from a database</title>
<link rel="stylesheet" type="text/css" href="css/style.css" />
<!-- You need to include the following JS file to render the chart.
When you make your own charts, make sure that the path to this JS file is correct.
Else, you will get JavaScript errors. -->
<script src="fusioncharts/js/fusioncharts.js"></script>
</head>
<body>
<?php
try {
# MySQL with PDO_MYSQL
$mysql_host = 'host';
$mysql_database = 'table';
$mysql_username = 'user';
$mysql_password = 'pass';
$conn = new PDO("mysql:host=$mysql_host; dbname=$mysql_database", $mysql_username, $mysql_password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$conn->exec("SET CHARACTER SET utf8"); // Sets encoding UTF-8
}
catch(PDOException $e) {
echo $e->getMessage();
}
// Form the SQL query that returns the top 10 most populous countries
// Execute the query, or else return the error message.
$stm = $conn->prepare("SELECT Name, Visits FROM mysqltable"); //WHERE Area :SelArea");
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
include("fusioncharts.php");
$jsnarray = array();
foreach($results as $k => $v){
$jsnarray[] = array('label' => $results[$k]['Name'], 'value' => $results[$k]['Visits']);
};
$jsonEncodedData=json_encode($jsnarray);
new FusionCharts("type of chart",
"unique chart id",
"width of chart",
"height of chart",
"div id to render the chart",
"type of data",
"actual data");
$columnChart = new FusionCharts(
"column2d",
"ex1" ,
"600",
"400",
"chart-1",
"json",
'{
"chart":
{
"caption":"Harry\'s SuperMart",
"subCaption":"Top 5 stores in last month by revenue",
"numberPrefix":"$",
"theme":"ocean"
},
"data": //$jsonEncodedData}'); <---I tried to insert this after "data":but no results unlike if you put raw data**
[
{
"label":"Bakersfield Central",
"value":"880000"
},
{
"label":"Garden Groove harbour",
"value":"730000"
},
{
"label":"Los Angeles Topanga",
"value":"590000"
},
{
"label":"Compton-Rancho Dom",
"value":"520000"
},
{
"label":"Daly City Serramonte",
"value":"330000"
}
]
}');
// Render the chart
$columnChart->render();
?>
<div id="chart-1"><!-- Fusion Charts will render here--></div>
</body>
</html>
==============编辑 12/28/15==========
尝试了以下代码但没有结果，我的问题是我们不应该按照他们的要求以“}”结尾：
$columnChart = new FusionCharts(
"column2d",
"ex1" ,
"600",
"400",
"chart-1",
"json",
'{
"chart":
{
"caption":"Harry\'s SuperMart",
"subCaption":"Top 5 stores in last month by revenue",
"numberPrefix":"$",
"theme":"ocean"
},
"data": ' . $jsonEncodedData);
//}';
// Render the chart
print_r($columnChart);
$columnChart->render();
?>
<div id="chart-1"><!-- Fusion Charts will render here--></div>
</body>
</html>
我想 post "manual" 方法和“fetch 方法”之间的数组差异（在此编辑的上方）。
获取：
FusionCharts Object ( [constructorOptions:FusionCharts:private] => Array ( >[type] => column2d [id] => ex1 [width] => 600 [height] => 400 [renderAt] => >chart-1 [dataFormat] => json [dataSource] => { "chart": { >"caption":"Harry's SuperMart", "subCaption":"Top 5 stores in last month by >revenue", "numberPrefix":"$", "theme":"ocean" }, "data": >[{"label":"John","value":"125"},{"label":"Jerry","value":"125"},{"label":"Jane","value":"125"}] ) [constructorTemplate:FusionCharts:private] => >[renderTemplate:FusionCharts:private] => )
使用手动方法（有效）：
FusionCharts Object ( [constructorOptions:FusionCharts:private] => Array ( >[type] => column2d [id] => ex1 [width] => 600 [height] => 400 [renderAt] => >chart-1 [dataFormat] => json [dataSource] => { "chart": { >"caption":"Harry's SuperMart", "subCaption":"Top 5 stores in last month by >revenue", "numberPrefix":"$", "theme":"ocean" }, "data": [ { >"label":"Bakersfield Central", "value":"880000" }, { "label":"Garden Groove >harbour", "value":"730000" }, { "label":"Los Angeles Topanga", >"value":"590000" }, { "label":"Compton-Rancho Dom", "value":"520000" }, { >"label":"Daly City Serramonte", "value":"330000" } ] } ) >[constructorTemplate:FusionCharts:private] => >[renderTemplate:FusionCharts:private] => )
我立即看到两个不同之处，手册在 "data" 和结束 } 参数周围插入空格。
有一种自动（并且更简单）的方法可以做到这一点：
$stm = $conn->prepare('SELECT Name AS label, Visits AS value FROM mysqltable;');
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
$jsonEncodedData = json_encode($results);
echo $jsonEncodedData;
输出（本地测试）：
[{"label":"Foo","value":"5"},{"label":"Bar","value":"15"}]
这样你就可以像这样使用它了:
$columnChart = new FusionCharts('...
...
"data": ' . $jsonEncodedData . '}');
注意最后的. '}'
编辑前：
你可以这样做：
// This part is just for running purposes
$foo = array (
0 => Array (
'Id' => 6,
'Number' => 1234567890,
'Visits' => 1,
'Name' => 'John'
),
1 => array (
'Id' => 7,
'Number' => 1236549871,
'Visits' => 9,
'Name' => 'Jerry'
),
2 => array (
'Id' => 8,
'Number' => 2147483647,
'Visits' => "3", // Example to output quoted
'Name' => 'Jane'
)
);
$bar = array();
foreach($foo as $k => $v){
$bar[] = array('label' => $foo[$k]['Name'], 'value' => $foo[$k]['Visits']);
}
echo json_encode($bar);
输出：
[{"label":"John","value":1},{"label":"Jerry","value":9},{"label":"Jane","value":"3"}]
在一行中与你的（来自问题）进行比较：
[{label: "CJ Anderson",value: "25"},{label: "Imran Tahir",value: "25"},...]
注：我假设value由Visit表示，label由Name表示。
详细了解 json_encode。
作为总结，这是解决问题的部分，包括 FirstOne 的 foreach 语句：
$stm = $conn->prepare("SELECT Name, Visits FROM mysqltable"); //WHERE Area :SelArea");
$stm->execute();
$results = $stm->fetchAll(PDO::FETCH_ASSOC);
include("fusioncharts.php");
$jsnarray = array();
foreach($results as $k => $v){
$jsnarray[] = array('label' => $results[$k]['Name'], 'value' => $results[$k]['Visits']);
};
$jsonEncodedData=json_encode($jsnarray);
//print_r($jsonEncodedData);
new FusionCharts("type of chart",
"unique chart id",
"width of chart",
"height of chart",
"div id to render the chart",
"type of data",
"actual data");
$columnChart = new FusionCharts(
"column2d",
"ex1" ,
"600",
"400",
"chart-1",
"json",
'{
"chart":
{
"caption":"Harry\'s SuperMart",
"subCaption":"Top 5 stores in last month by revenue",
"numberPrefix":"$",
"theme":"ocean"
},
"data": ' . $jsonEncodedData . '}');
// Render the chart
print_r($columnChart);
$columnChart->render();
?>
<div id="chart-1"><!-- Fusion Charts will render here--></div>
</body>
</html>
感谢大家帮忙解决问题