在 Pivot 中执行操作
Performing operations in a Pivot
我正在尝试实现 PIVOT
,但我无法在其中执行基本操作。
当前 table:
week_no username days pick_count duration
------------------------------------------------
Week 50 Beck W Wednesday 227 7978
Week 50 Beck W Friday 320 7481
Week 50 Beck W Friday 282 5718
Week 50 Cockram D Thursday 165 10478
Week 50 Cowell P Thursday 145 14403
Week 50 Cowell P Thursday 159 7450
Week 50 Cowell P Friday 217 13101
...
预期结果:
week_no username monday tuesday wednesday thursday friday saturday sunday
--------------------------------------------------------------------------
Week 50 Beck W NULL NULL 102 NULL 164 NULL NULL
Week 50 Cockram D NULL NULL NULL 56 NULL NULL NULL
Week 50 Cowell P NULL NULL NULL 50 59 NULL NULL
...
预期结果应计算如下:pick_count * 3600 / duration
。那是我在计算时遇到问题的计算。当PIVOT
像这样时
SELECT
*
FROM
(
SELECT
week_no,
username,
days,
pick_count,
duration
FROM
table
) AS src
PIVOT
(
SUM(pick_count) * 3600 / SUM(duration) FOR days IN (monday, tuesday, wednesday, thursday, friday, saturday, sunday)
) AS pvt
我得到 Incorrect syntax near '*'
。
PIVOT
不是很灵活。
您可以只使用旧式交叉表方法。
SELECT week_no,
username,
SUM(CASE WHEN days = 'monday' then pick_count end) * 3600
/ SUM(CASE WHEN days = 'monday' then duration end) as monday,
SUM(CASE WHEN days = 'tuesday' then pick_count end) * 3600
/ SUM(CASE WHEN days = 'tuesday' then duration end) as tuesday
/*TODO: Add other five days*/
FROM YourTable
GROUP BY week_no,
username
我终于找到了我要找的东西。事实上,我需要做的就是计算 SELECT
而不是 PIVOT
.
中的计算
SELECT
*
FROM
(
SELECT
week_no,
username,
days,
SUM(pick_count) * 3600 / SUM(duration) AS pick_rate
FROM
table
GROUP BY
week_no,
username,
days
) AS src
PIVOT
(
MAX(pick_rate) FOR days IN (monday, tuesday, wednesday, thursday, friday, saturday, sunday)
) AS pvt
我正在尝试实现 PIVOT
,但我无法在其中执行基本操作。
当前 table:
week_no username days pick_count duration
------------------------------------------------
Week 50 Beck W Wednesday 227 7978
Week 50 Beck W Friday 320 7481
Week 50 Beck W Friday 282 5718
Week 50 Cockram D Thursday 165 10478
Week 50 Cowell P Thursday 145 14403
Week 50 Cowell P Thursday 159 7450
Week 50 Cowell P Friday 217 13101
...
预期结果:
week_no username monday tuesday wednesday thursday friday saturday sunday
--------------------------------------------------------------------------
Week 50 Beck W NULL NULL 102 NULL 164 NULL NULL
Week 50 Cockram D NULL NULL NULL 56 NULL NULL NULL
Week 50 Cowell P NULL NULL NULL 50 59 NULL NULL
...
预期结果应计算如下:pick_count * 3600 / duration
。那是我在计算时遇到问题的计算。当PIVOT
像这样时
SELECT
*
FROM
(
SELECT
week_no,
username,
days,
pick_count,
duration
FROM
table
) AS src
PIVOT
(
SUM(pick_count) * 3600 / SUM(duration) FOR days IN (monday, tuesday, wednesday, thursday, friday, saturday, sunday)
) AS pvt
我得到 Incorrect syntax near '*'
。
PIVOT
不是很灵活。
您可以只使用旧式交叉表方法。
SELECT week_no,
username,
SUM(CASE WHEN days = 'monday' then pick_count end) * 3600
/ SUM(CASE WHEN days = 'monday' then duration end) as monday,
SUM(CASE WHEN days = 'tuesday' then pick_count end) * 3600
/ SUM(CASE WHEN days = 'tuesday' then duration end) as tuesday
/*TODO: Add other five days*/
FROM YourTable
GROUP BY week_no,
username
我终于找到了我要找的东西。事实上,我需要做的就是计算 SELECT
而不是 PIVOT
.
SELECT
*
FROM
(
SELECT
week_no,
username,
days,
SUM(pick_count) * 3600 / SUM(duration) AS pick_rate
FROM
table
GROUP BY
week_no,
username,
days
) AS src
PIVOT
(
MAX(pick_rate) FOR days IN (monday, tuesday, wednesday, thursday, friday, saturday, sunday)
) AS pvt