系统在没有用户操作的情况下授予权限

System grants the permission by no user action

我遇到了一个奇怪的问题。我遵循了 this 教程,以便在运行时为我构建的应用程序请求权限。问题是,即使我检查设备是否正在使用 Android M 并且我在运行时请求权限,它也不会显示对话框。

代码:

@Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_configuration);
        spinner = (Spinner)findViewById(R.id.database_selection_spinner);
        button = (Button)findViewById(R.id.proceedBtn);
        if (Build.VERSION.SDK_INT == Build.VERSION_CODES.M) {
           if (ContextCompat.checkSelfPermission(ConfigurationActivity.this, Manifest.permission.INTERNET) == PackageManager.PERMISSION_GRANTED){
               accessWebService();
           }else {
               if (shouldShowRequestPermissionRationale(Manifest.permission.INTERNET)){
                   StringGenerator.showToast(ConfigurationActivity.this, "Internet Permission needs to be granted");
               }

               requestPermissions(new String[]{Manifest.permission.INTERNET}, AppConstants.PERMISSION_REQ_CODE);

           }
        }else {
            accessWebService();
        }
    }

    @Override
    public void onRequestPermissionsResult(int requestCode, String[] permissions, int[] grantResults) {
        super.onRequestPermissionsResult(requestCode, permissions, grantResults);
        if (requestCode == AppConstants.PERMISSION_REQ_CODE){
            if (grantResults[0] == PackageManager.PERMISSION_GRANTED){
                accessWebService();
            }else {
                StringGenerator.showToast(ConfigurationActivity.this, "LOL");
            }
        }else {
            super.onRequestPermissionsResult(requestCode, permissions, grantResults);
        }
    }

accessWebService:

private void accessWebService(){
        FetchDataTask task = new FetchDataTask();
        task.execute(AppConstants.DATABASE_INFO_URL);
    }

清单:

<uses-permission-sdk-23 android:name="android.permission.INTERNET"/>

结果如下:

并且没有请求权限:

有什么建议吗?

互联网是一个"normal permission",它是系统授予的,无需询问用户。在 documentation.

中查看更多信息

用户将仅被询问 dangerous permissions