SQLAlchemy 关系错误
SQLAlchemy relationship error
我确实有这 2 个 calsses als DB 模型试图建立一对多关系:
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(255), index=True) #, unique=True)
firstname = db.Column(db.String(50))
lastname = db.Column(db.String(50))
bt_ids = db.relationship("BT", order_by="BT.id", backref="user")
class BT(db.Model):
__tablename__ = 'bt'
id = db.Column(db.Integer, primary_key=True)
bt_id = db.Column(db.String(255), unique=True)
user_id = db.Column(db.Integer, db.ForeignKey('users.id'))
user = db.relationship("User", backref=db.backref('bt', order_by=id))
但我想我不太了解建立关系的方式:
ArgumentError: Error creating backref 'user' on relationship 'User.bt_ids': property of that name exists on mapper 'Mapper|BT|bt'
有什么想法吗?
编辑
我实际上想要实现类似 SQLAlchemy
的示例
class User(Base):
__tablename__ = 'users'
id = Column(Integer, Sequence('user_id_seq'), primary_key=True)
name = Column(String(50))
fullname = Column(String(50))
password = Column(String(12))
**addresses = relationship("Address", order_by="Address.id", backref="user")**
def __repr__(self):
return "<User(name='%s', fullname='%s', password='%s')>" % (
self.name, self.fullname, self.password)
class Address(Base):
__tablename__ = 'addresses'
id = Column(Integer, primary_key=True)
email_address = Column(String, nullable=False)
user_id = Column(Integer, ForeignKey('users.id'))
**user = relationship("User", backref=backref('addresses', order_by=id))**
def __repr__(self):
return "<Address(email_address='%s')>" % self.email_address
User
和 BT
到 user_id
属性 之间已经存在 FK
关系,因此您不能创建另一个名为 [=15 的关系=] 在 BT.
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(255), index=True) #, unique=True)
firstname = db.Column(db.String(50))
lastname = db.Column(db.String(50))
bts = db.relationship("BT", order_by="BT.id", backref="user")
class BT(db.Model):
__tablename__ = 'bt'
id = db.Column(db.Integer, primary_key=True)
bt_id = db.Column(db.String(255), unique=True)
user_id = db.Column(db.Integer, db.ForeignKey('users.id'))
现在我明白了...
这是错误的:
user = db.relationship("User", backref=db.backref('bt_ids', order_by =id))
现在可以使用了!
我确实有这 2 个 calsses als DB 模型试图建立一对多关系:
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(255), index=True) #, unique=True)
firstname = db.Column(db.String(50))
lastname = db.Column(db.String(50))
bt_ids = db.relationship("BT", order_by="BT.id", backref="user")
class BT(db.Model):
__tablename__ = 'bt'
id = db.Column(db.Integer, primary_key=True)
bt_id = db.Column(db.String(255), unique=True)
user_id = db.Column(db.Integer, db.ForeignKey('users.id'))
user = db.relationship("User", backref=db.backref('bt', order_by=id))
但我想我不太了解建立关系的方式:
ArgumentError: Error creating backref 'user' on relationship 'User.bt_ids': property of that name exists on mapper 'Mapper|BT|bt'
有什么想法吗?
编辑我实际上想要实现类似 SQLAlchemy
的示例class User(Base):
__tablename__ = 'users'
id = Column(Integer, Sequence('user_id_seq'), primary_key=True)
name = Column(String(50))
fullname = Column(String(50))
password = Column(String(12))
**addresses = relationship("Address", order_by="Address.id", backref="user")**
def __repr__(self):
return "<User(name='%s', fullname='%s', password='%s')>" % (
self.name, self.fullname, self.password)
class Address(Base):
__tablename__ = 'addresses'
id = Column(Integer, primary_key=True)
email_address = Column(String, nullable=False)
user_id = Column(Integer, ForeignKey('users.id'))
**user = relationship("User", backref=backref('addresses', order_by=id))**
def __repr__(self):
return "<Address(email_address='%s')>" % self.email_address
User
和 BT
到 user_id
属性 之间已经存在 FK
关系,因此您不能创建另一个名为 [=15 的关系=] 在 BT.
class User(db.Model):
__tablename__ = 'users'
id = db.Column(db.Integer, primary_key=True)
email = db.Column(db.String(255), index=True) #, unique=True)
firstname = db.Column(db.String(50))
lastname = db.Column(db.String(50))
bts = db.relationship("BT", order_by="BT.id", backref="user")
class BT(db.Model):
__tablename__ = 'bt'
id = db.Column(db.Integer, primary_key=True)
bt_id = db.Column(db.String(255), unique=True)
user_id = db.Column(db.Integer, db.ForeignKey('users.id'))
现在我明白了...
这是错误的:
user = db.relationship("User", backref=db.backref('bt_ids', order_by =id))
现在可以使用了!