随机数格子 4 x 6 Python 3

Question

我是 Python 3 的新手，想生成一个随机网格 4x6 数字。我尝试了各种方法，但最终还是在新行上打印，或者在每行上打印 4x6 相同的数字等。

一些代码示例（我尝试了很多不同的方法，但我必须重新输入它们，因为我使用的是 linux 到运行 Python 的虚拟框：

import random

def grid_maker(h,v):
 for y in range(1, 5):
  x = random.randint(1, 100)
  grid = [[str(x) for _ in range(v)] for _ in range (h)]
  grid[0][0] = "o"
  return grid
print ('\n'.join(''.join(row) for row in grid_maker(6,5)))

输出

期望的输出

82 2 30 9 
45 65 54 14
23 4 32 42 
8 84 40 80
43 23 5 62 
23 43 3 5

另一个例子

for t in range(1, 5)
 i = random.randint(1, 100)
 grid = [[i], [i], [i], [i]]
 from pprint import pprint
 pprint(grid)

输出

[[100], [100], [100], [100]]
[[1], [1], [1], [1]]
[[80], [80], [80], [80]]
[[12], [12], [12], [12]]

期望的输出

[[34], [12], [2], [15]]
[[64], [34], [53], [4]]
[[35], [34], [61], [33]]
[[34], [55], [64], [23]]

另一个例子

ar = []
    for t in range(1, 5):
     i = random.randint(1, 100)
     ar.append(i)
    for t in range(1, 7):
     for i in range(1, 5):
      print(ar[t-1], end='')

但这会打印出 585858585555555559595959343434342222222288888888root@root:/home/user#

谢谢

Answer 1

你每次在循环中只调用一次随机所以保持使用相同的值，在列表中调用它 comp:

def grid_maker(h,v):
   for y in range(1, 5):
      # add call to list comp to get a new number each iteration
      grid = [[str(random.randint(1,100)) for _ in range(v)] for _ in range (h)]
   grid[0][0] = "o"
   return grid
print ('\n'.join(' '.join(row) for row in grid_maker(6,4))

o 23 47 30 
25 21 32 28
26 76 71 14
54 15 94 77
50 50 29 62
59 92 60 57

如果您不想要 "o" 则不要添加它，只需删除 grid[0][0] = "o"

第一个循环也是多余的你不断创建新列表但只返回一个：

def grid_maker(h, v):
    return [[str(random.randint(1, 100)) for _ in range(v)] for _ in range(h)]

我们也可以只在函数中完成：

def grid_maker(h, v):
    return '\n'.join(' '.join(row) for row in  [[str(random.randint(1, 100)) for _ in range(v)] for _ in range(h)])

print(grid_maker(6, 4)) # 6,4 not 6,5

26 96 50 46
4 57 50 80
36 24 23 66
71 33 44 15
54 15 77 54
52 99 60 99

要打印适用相同逻辑的列表列表，您需要每次调用 randint：

for t in range(6):
    print([[random.randint(1,100)], [random.randint(1,100)], [random.randint(1,100)], [random.randint(1,100)]])

[[90], [57], [21], [11]]
[[84], [80], [100], [47]]
[[25], [37], [87], [97]]
[[78], [90], [100], [74]]
[[96], [83], [59], [2]]
[[83], [19], [90], [4]]

Answer 2

您在第一个例子中只生成了一个随机数：

import random
def grid_maker(h, v):
    return [
        [str(random.randint(1, 100)) for _ in range(v)]
        for _ in range(h)
    ]
print ('\n'.join(' '.join(row) for row in grid_maker(6, 5)))

第二个：

import random
ar = [
    [[random.randint(1, 100)] for t in range(1, 5)]
    for i in range(1, 5)
]
for row in ar:
    print(row)

随机数格子 4 x 6 Python 3

Random number grid 4 x 6 Python 3

python

random

numbers

python-3.x