使用 NetComm dll 发送屏幕截图到主机

Question

我正在使用 NetComm dll 来处理多用户。我的问题是当我发送文本时它工作正常但是当我截取屏幕截图时它不起作用。我的客户端代码是

ms = new MemoryStream();
            bmpScreenshot.Save(ms, ImageFormat.Png);
            byte[] buffer;
            buffer  =imageToByteArray(bmpScreenshot);
            client.SendData(buffer);

而将图像转换为字节数组的函数是：

 public byte[] imageToByteArray(System.Drawing.Image imageIn)
        {
            MemoryStream ms = new MemoryStream();
            imageIn.Save(ms, System.Drawing.Imaging.ImageFormat.Gif);
            return ms.ToArray();
        }

在接收端我是这样处理的：

    Stream stream = new MemoryStream(Data); // Data is byte array 
    pictureBox1.Image = Image.FromStream(stream);
    pictureBox1.Refresh();

收到后我在图片框中显示图像。

使用 NetComm dll 我只能发送和接收字节数组格式的数据。

NetComm dll 为我提供了使用它的 id 从一个客户端到另一个客户端进行通信的工具。当服务器启动时，它会等待客户端，一旦客户端建立连接，它就会开始以某种方式为它们提供 ID，例如 abc1、abc2、abc3。当 abc1 想要与 abc3 通信时，它只需输入 abc3 作为 id 而不是 IP 并发送消息，该消息应该传递给 abc3。

如您所见，有两个客户端连接到服务器，并且都获得了 jack1 和 jack2 之类的 ID。现在，如果他们想相互交流，只需输入各自的 ID 并发送消息即可。

Answer 1

我尝试制作一个简单的客户端-> 客户端消息发送，这将是一个位图。当我尝试将它与不同的端口一起使用时遇到问题，但端口被阻止，这就是问题所在。也检查一下。检查代码，看看是否有帮助：

namespace CommTest
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        NetComm.Host host = new NetComm.Host(10010);
        NetComm.Client client1 = new NetComm.Client();
        NetComm.Client client2 = new NetComm.Client();

        private void Form1_Load(object sender, EventArgs e)
        {
            host.StartConnection();
            client1.Connect("localhost", 10010, "Jack");
            client2.Connect("localhost", 10010, "Jack2");
            client2.DataReceived += client2_DataReceived;
            client1.SendData(imageToByteArray(Image.FromFile("Bitmap1.bmp")), "Jack2");
        }

        void client2_DataReceived(byte[] Data, string ID)
        {
            Stream stream = new MemoryStream(Data); // Data is byte array 
            pictureBox1.Image = Image.FromStream(stream);
            // pictureBox1.Refresh(); works without it
        }

        public byte[] imageToByteArray(Image imageIn)
        {
            MemoryStream ms = new MemoryStream();
            imageIn.Save(ms, ImageFormat.Gif);
            return ms.ToArray();
        }

        private void Form1_FormClosed(object sender, FormClosedEventArgs e)
        {
            host.CloseConnection();
        }
    }
}

Answer 2

完整的服务器/客户端实现可能是这样的。您不需要实现 2 个不同的客户端程序，但客户端和服务器应该不同。这是一个如何使用广播的例子>

Program.cs

static class Program
{
    /// <summary>
    /// The main entry point for the application.
    /// </summary>
    [STAThread]
    static void Main(string[] argv)
    {
        Application.EnableVisualStyles();
        Application.SetCompatibleTextRenderingDefault(false);
        // if You run the program like "CommTest.exe 10010", than it will be host.
        // if You run it like "CommTest.exe localhost 10010", than it will be client connecting to localhost.
        if (argv.Length == 1)
        {
            Application.Run(new Form2(new Host(int.Parse(argv[0]))));
        }
        else
        {
            Application.Run(new Form1(new Client(argv[0], int.Parse(argv[1]))));
        }
    }
}

Form1.cs

public partial class Form1 : Form
{
    public Form1(NetComm.Client client)
    {
        _client = client;
        InitializeComponent();
    }

    // there is a button to broadcast picture on the client.
    private void Button1_Click(object sender, EventArgs e)
    {
        // update the image that should be broadcasted as You like.
        _client.SendData(imageToByteArray(Image.FromFile("Bitmap1.bmp")));
    }

    NetComm.Client _client;

    private void Form1_Load(object sender, EventArgs e)
    {
        button1.Click += Button1_Click;
        _client.DataReceived += client_DataReceived;
    }

    void client_DataReceived(byte[] Data, string ID)
    {
        Stream stream = new MemoryStream(Data); // Data is byte array 
        pictureBox1.Image = Image.FromStream(stream);
    }

    public byte[] imageToByteArray(Image imageIn)
    {
        MemoryStream ms = new MemoryStream();
        imageIn.Save(ms, ImageFormat.Gif);
        return ms.ToArray();
    }

    private void Form1_FormClosed(object sender, FormClosedEventArgs e)
    {
        _client.Disconnect();
    }
}

Client.cs

class Client: NetComm.Client
{
    public Client(string ip, int port):base()
    {
        // in this example, the ids are not considered. In a real world situation Clients should send a first message to the host,
        // and host should reply with a free id. That id should be in the place of Guid.NewGuid().ToString()
        Connect(ip, port, Guid.NewGuid().ToString());
    }
}

Form2.cs

public partial class Form2 : Form
{
    public Form2(NetComm.Host host)
    {
        _host = host;
        InitializeComponent();
    }

    NetComm.Host _host;

    private void Form2_Load(object sender, EventArgs e)
    {
        button1.Click += Button1_Click;
    }

    // there is a button to close the connection on the host form.
    private void Button1_Click(object sender, EventArgs e)
    {
        _host.CloseConnection();
    }

    private void Form2_FormClosed(object sender, FormClosedEventArgs e)
    {
        _host.CloseConnection();
    }
}

Host.cs

class Host: NetComm.Host
{
    public Host(int port):base(port)
    {
        StartConnection();
        DataReceived += Host_DataReceived;
    }

    void Host_DataReceived(string ID, byte[] Data)
    {
        Brodcast(Data);
    }
}

使用 NetComm dll 发送屏幕截图到主机

Sending Screenshots using NetComm dll to Host

c#

.net

sockets

client-server