如何从 python 中的一个列表创建多个列表

Question

我想根据条件从一个列表中创建多个列表。

实际数据：

numbers = [1, 2, 3,4,5,6,7,8,9, 1, 11, 12, 13, 1, 21, 22, 25, 6, 1, 34 ,5 ,6 ,7,78]

预期结果：

[1, 2, 3,4,5,6,7,8,9]
[1, 11, 12, 13]
[1, 21, 22, 25, 6]
[1, 34 ,5 ,6 ,7,78]

这是我的尝试：

list_number=[]
numbers = [1, 2, 3,4,5,6,7,8,9, 1, 11, 12, 13, 1, 21, 22, 25, 6, 1, 34 ,5 ,6 ,7,78]
for x in numbers:
    if x==1:
        list_number.append(numbers)

print list_number[0]

Answer 1

与其将原始 numbers 的新 references/copies 添加到 list，不如在看到 1 时开始新的 list 或添加否则到最新的：

list_number = []
numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 11, 12, 13, 1, 21, 22, 25, 6, 1, 34, 5, 6, 7, 78]
for x in numbers:
    if x==1:
        list_number.append([1])
    else:
        list_number[-1].append(x)

print list_number

结果：

>>> for x in list_number:
...     print x
...
[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 11, 12, 13]
[1, 21, 22, 25, 6]
[1, 34, 5, 6, 7, 78]

Answer 2

我的建议是一个 2 步进器，首先找到一个的索引，然后从一个到另一个打印，从最后一个打印到最后：

 ones_index=[]
 numbers = [1, 2, 3,4,5,6,7,8,9, 1, 11, 12, 13, 1, 21, 22, 25, 6, 1, 34 ,5 ,6 ,7,78]
 for i,x in enumerate(numbers):
     if x==1:
         ones_index.append(i)

for i1,i in enumerate(ones_index):
     try:
         print numbers[i:ones_index[i1+1]]
    except:
         print numbers[i:]

如何从 python 中的一个列表创建多个列表

How to make multiple list from one list in python

python

python-2.7

list-manipulation