获得 TOP 8 PERCENT 然后插入另一个 table

Question

我有一个场景，我需要根据每个 artist/record 的分数计算前 8% 的记录，这些分数由 3 个类别的 5 位不同评委确定。

为此，我在存储过程中使用了以下内容

SELECT TOP 8 PERCENT 
    *
FROM
    (SELECT 
         MEM.Id,
         EN.artistName, EN.dateAdded, EN.voteStatus, 
         ES.enterNextRound, ES.notified, ES.voted,
         GR.genre,
         ES.entrantId AS bandID,
         ES.rnd2Feedback AS feedback, ES.compositionVote,
         ES.vocalsVote, ES.originalityVote,
         (SELECT COUNT(Voted)
          FROM recEntrantStatus
          WHERE voted = 1
            AND roundId = 2
            AND entrantId = ES.entrantId) CountVoted,
         (SELECT (COUNT(Voted)/*-1*/)
          FROM recEntrantStatus
          WHERE roundId = 2
            AND entrantId = ES.entrantId) CountTotalVotes,
         (SELECT COUNT(Id)
          FROM recMembers) TotalJudges,
         (SELECT coalesce(SUM(compositionVote),0)
          FROM recEntrantStatus
          WHERE roundId = 2
            AND entrantId = ES.entrantId
            AND voted = 1) SumTotalComposition,
         (SELECT coalesce(SUM(vocalsVote),0)
          FROM recEntrantStatus
          WHERE roundId = 2
            AND entrantId = ES.entrantId
            AND voted = 1) SumTotalVocals,
         (SELECT coalesce(SUM(originalityVote),0)
          FROM recEntrantStatus
          WHERE roundId = 2
            AND entrantId = ES.entrantId
            AND voted = 1) SumTotalOrig,
         (SELECT SUM(compositionVote + vocalsVote + originalityVote)
          FROM recEntrantStatus
          WHERE roundId = 2
            AND entrantId = ES.entrantId) TotalVoteScore
     FROM 
         recMembers AS MEM
     LEFT JOIN 
         recEntrantStatus AS ES ON MEM.Id = ES.judgeId
     LEFT JOIN 
         recEntrants AS EN ON ES.entrantId = EN.Id
     LEFT JOIN 
         recGenre AS GR ON EN.genreId = GR.Id
     WHERE 
         MEM.Id = 4
         AND ES.roundId = @input) q
ORDER BY 
    TotalVoteScore DESC, compositionVote DESC, 
    originalityVote DESC, vocalsVote DESC

现在，为了准备下一轮的比赛，我需要获取此结果集并为每一行创建一个新记录，为所有评委（目前总共大约 20 名）中的每一个创建一次。因此，对于这个前 8% 的记录集（大约 12 个参赛者/记录）中的每一个，这将是 20 条记录。因此，这应该会导致插入大约 12*20 条记录。

在前几轮中，我只是选择了 'ALL' 个具有位字段用作标记的参赛者，以指示他们将进入下一轮。我用以下代码做到了这一点：

INSERT INTO recEntrantStatus (entrantId, roundId, judgeId, notified, voted, enterNextRound)
    SELECT 
        r.entrantId, (@input + 1), j.judgeId /*Now getting tblJudges Id*/, 0, 0, 0
    FROM 
        recEntrantStatus r
    -- Get all of the judges
    CROSS JOIN 
        (SELECT DISTINCT Id AS judgeId 
         FROM recMembers 
         WHERE Privilege >= 2) AS j
    WHERE 
        r.roundId = @input
        AND r.voted = 1
        AND r.enterNextround = 1

所以，我的问题本质上是如何将这两个查询结合起来，以便从当前轮次中获得前 8%，然后为前 8% 的参赛者中的每一位的 20 位评委添加一条新记录？

不幸的是，将 CROSS JOIN SELECT 替换为检索前 8% 的 CROSS JOIN 并不是一个简单的例子。

有什么建议吗？？

Answer 1

使用识别 TOP 8 PERCENT 成员和所有评委的 CTE 编写查询，然后交叉连接两者，以便插入多条记录。

这是查询的框架，您可以在其中填写所有属性和必要条件。

WITH Members AS
(
    --note, for a CTE, all columns in the select must have a name (or you must specify the column names above next to the CTE name)
    SELECT TOP 8 PERCENT mem.id, entrantId, ... FROM recMembers [mem] ... ORDER BY ...
),
Judges AS
(
    SELECT Id [judgeId] FROM recMembers WHERE Privilege >= 2
)
INSERT INTO recEntrantStatus (entrantId, roundId, judgeId, notified, voted, enterNextRound)
SELECT m.entrantId, ...
FROM Members m, Judges j --cross join of your top 8% members and all of your judges
WHERE ...

您可以通过其他方式执行此操作，例如在您的示例中使用派生的 table 表达式，但我认为 CTE 方法更具可读性。

获得 TOP 8 PERCENT 然后插入另一个 table

Get TOP 8 PERCENT then insert into another table

tsql

sql-server

select

stored-procedures

sql-insert