hasMany 关系没有 table 有 id 列

hasMany relation without table having id column

我正在使用 CakePHP 2.5。我正在关注 table


公司主管:


CompanySignatoryDe​​tails:(单个公司有多个所有者)

现在,我想获得该公司所有所有者的公司详细信息。这是我尝试过的。

$this->CompanyMaster->bindModel(
    array(
        'hasMany' => array(
            'CompanySignatoryDetails' => array(
                'className' => 'CompanySignatoryDetails',
                'foreignKey' => false,
                'conditions' => array(
                    'CompanySignatoryDetails.company_master_id = CompanyMaster.company_master_id'
                ),
            ),
        )
    )
);


$this->CompanyMaster->recursive = 2;

$company = $this->CompanyMaster->find('first', array(
    'fields' => array('CompanyMaster.*'),
    'conditions' => $conditions,  //company id in condition
));

我收到以下错误:

Database Error 
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'CompanyMaster.id' in 'field list' 

SQL Query:
SELECT `CompanyMaster`.*, `CompanyMaster`.`id` FROM      `crawler_output`.`company_master` AS `CompanyMaster` WHERE `CompanyMaster`.`company_master_id` = 1 LIMIT 1

请告诉我如何在没有 id 作为列名的情况下绑定模型。

好吧,例如,让您的查询看起来像这样:

select CompanyMaster.*,CompanySignatoryDetails.* from
CompanyMaster as cm inner join CompanySignatoryDetails as cd on  
    cm.company_master_id=cd.company_master_id  
      order by cm.company_master_id; 

You will get all fields from two tables, ordered by company_master_id field. You may reduce number of fields, displayed by this query, by explicitly designate them like this:

select cm.company_master_id, cd.name from....

HNY!(新年快乐!!)

CakePHP 在处理 hasMany 关系时将生成单独的查询,因此您将无法从另一个 table 引用字段。只有 belongsTohasOne 关系会产生 JOIN

但是,您不需要为关系添加条件。以下应该可以正常工作:

$this->CompanyMaster->bindModel(array(
    'hasMany' => array(
        'CompanySignatoryDetails' => array(
            'className' => 'CompanySignatoryDetails',
            'foreignKey' => 'company_master_id',
        ),
    )
));

不要忘记为 CompanyMaster:

定义主键
class CompanyMaster extends AppModel 
{
    public $primaryKey = 'company_master_id';
}

CompanySignatoryDetails

class CompanySignatoryDetails extends AppModel 
{
    public $primaryKey = 'company_signatory_details_id';
}