每个 TcpClients 发送和接收位图

Question

所以，我目前正在制作一个 LAN-Streaming-Program，它应该记录流媒体的屏幕并将其显示在观众的屏幕上。我的问题是，当我尝试将接收到的 ByteArray-Image 转换为图像时，它给了我 System.ArgumentException.

发送代码如下：

Private Sub SendFrame(ByRef IP As String, ByRef Frame As Bitmap)

    FrameClient = New TcpClient(IP, 7009)

    Dim FrameStream As New MemoryStream
    Dim FrameBytes() As Byte

    Frame.Save(FrameStream, ImageFormat.Bmp)
    FrameBytes = FrameStream.GetBuffer()

    SendMessage(IP, "NextFrameSize;" & LocalIP & ";" & FrameBytes.Length)

    Using NS As NetworkStream = FrameClient.GetStream
        NS.Write(FrameBytes, 0, FrameBytes.Length)
        NS.Close()
    End Using

End Sub

在这里接收：

Private Sub CheckForFrames() 'This Sub is called everytime the viewer receives the size of the next Bitmap.

    If FrameListener.Pending = True Then

        FrameClient = FrameListener.AcceptTcpClient
        Dim ImageBytes(NextFrameSize) As Byte

        FrameClient.GetStream.Read(ImageBytes, 0, NextFrameSize)

        Dim MS As New MemoryStream(ImageBytes)
        StreamBox.Image = Image.FromStream(MS, False)
        MS.Close()

        FlushMemory()

    End If

End Sub

如有任何答案，我将不胜感激！

Answer 1

Dim ImageBytes(FrameClient.ReceiveBufferSize) As Byte

这returns缓冲区的大小，而不是位图的实际大小：

The size of the receive buffer, in bytes. The default value is 8192 bytes.

所以，ImageBytes 可能是 8192 字节，而不是位图的大小。

您可能希望在发送位图数据之前发送尺寸，并在接收端先读取尺寸以初始化您的 MemoryStream。

每个 TcpClients 发送和接收位图

Sending and Receiving Bitmaps per TcpClients

vb.net

client

tcp

bitmap