Select2 ajax 未显示结果

Question

我正在使用 select2 和 ajax 在我的数据库中查询特定分类下的术语，但是当我搜索搜索框时，搜索框只是停留在 "searching" 而没有检索到任何结果。

这是我的html

<select multiple="" name="regions1[]" id="regions1" class="job-manager-multiselect select2-hidden-accessible" required="" tabindex="-1" aria-hidden="true"></select>

我的jquery:

<script>
jQuery(function($) {
$(document).ready(function() {
$( "#regions1" ).select2({        
ajax: {
    url: "/ajax/connect.php",
    dataType: 'json',
    delay: 250,
    data: function (params) {
        return {
            q: params.term // search term
        };
    },
    processResults: function (data) {
        // parse the results into the format expected by Select2.
        // since we are using custom formatting functions we do not need to
        // alter the remote JSON data
        return {
            results: data
        };
    },
    cache: true
},
minimumInputLength: 2
  });
  });
   });
 </script>

和我的 php 查询数据库的代码，我希望获得分类法下的所有术语名称 "job_listing_region"

<?php

  $servername = "localhost";
  $username = "myusername";
  $password = "mypassword";

   try {
$conn = new PDO("mysql:host=$servername;dbname=mydatabase", $username, $password);
// set the PDO error mode to exception
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
   }
    catch(PDOException $e)
   {
   echo "Connection failed: " . $e->getMessage();
   }



  // strip tags may not be the best method for your project to apply extra 
   layer of security but fits needs for this tutorial 
   $search = strip_tags(trim($_GET['q'])); 

 // Do Prepared Query
   $query = $conn->prepare("
   SELECT * FROM (
    SELECT wp_terms.name
   FROM wp_terms
   JOIN wp_term_taxonomy
    ON wp_term_taxonomy.term_id = wp_terms.term_id
    WHERE taxonomy = 'job_listing_region'
    AND count = 0
    ) as T"
     );

    // Add a wildcard search to the search variable
     $query->execute(array(':search'=>"%".$search."%"));


   // Do a quick fetchall on the results
    $list = $query->fetchall(PDO::FETCH_ASSOC);

   // Make sure we have a result
   if(count($list) > 0){
    foreach ($list as $key => $value) {
    $data[] = array('id' => $value['name'], 'text' => $value['name']);              
   } 
    } else {
   $data[] = array('id' => '0', 'text' => 'No Products Found');
   }


// return the result in json
echo json_encode($data);

如您所见，我正在检索我的数据，但搜索只是挂起。

提前致谢。

Answer 1

因此您需要将 processResults 更改为 success 并将以下内容放入该函数中：

for(i=0;1<data.length;++i){
   var currentObject = data[i];
   var id = currentObject.id;
   var text = currentObject.text;
   //do what you need to here (Put things in a div, etc)
}

然后，您可以执行以下操作：

document.getElementById("search").innerHTML = document.getElementById("search").innerHTML+"<br />"+id+text;

Answer 2

在这里找到解决方案

需要像这样重新创建我的结果

processResults: function (data) {
return {
    results: $.map(data, function(obj) {
        return { id: obj.id, text: obj.text };
    })
};
}

Select2 ajax 未显示结果

Select2 ajax not showing results

php

jquery

mysql

ajax

jquery-select2