Swift 2 - 合并两个数组

Question

我正在尝试合并两个数组：

数组 1 [["aaa","111"],["bbb","222"],["ccc","333"]]

数组 2 [["ddd","444"],["eee","555"],["fff","666"]]

我想要实现的是拥有一个数组，其值与数组位置相关，例如：

合并数组 [["aaa","111"],["ddd","444"],["bbb","222"],["eee","555"],["ccc","333"],["fff","666"]]

如何使用 Swift 2

Answer 1

let arr1 = [["aaa","111"],["bbb","222"],["ccc","333"]]
let arr2 = [["ddd","444"],["eee","555"],["fff","666"]]
let arr3 = arr1 + arr2
print(arr3) // [["aaa", "111"], ["bbb", "222"], ["ccc", "333"], ["ddd", "444"], ["eee", "555"], ["fff", "666"]]

在你的情况下，有特定的要求

let arr4 = zip(arr1, arr2).reduce([]) { (var arr, p:(Array<String>, Array<String>)) -> [[String]] in
    arr.append(p.0)
    arr.append(p.1)
    return arr
}
print(arr4) // [["aaa", "111"], ["ddd", "444"], ["bbb", "222"], ["eee", "555"], ["ccc", "333"], ["fff", "666"]]

更新根据您在注释中提到的需求，您可以通过这种方式添加其余值（请先将 let arr4 更改为 var arr4!!!）

var i = arr4.count / 2
while i < arr1.count {
    arr4.append(arr1[i++])
}

while i < arr2.count {
    arr4.append(arr2[i++])
}
print(arr4)

这给了你

[["aaa", "111"], ["ddd", "444"], ["bbb", "222"], ["eee", "555"], ["ccc", "333"], ["fff", "666"], ["zzz", "755"]]

它应该可以工作，即使其中一个数组是空的

Answer 2

使用zip函数

Array(zip(arr1, arr2))

@edit

正如@user3441734 提到的 zip returns 图。要解决这个问题，您可以使用 flatMap

var a = [["aaa","111"],["bbb","222"],["ccc","333"]] 
var b = [["ddd","444"],["eee","555"],["fff","666"]]
var cos = Array(zip(a, b))
var eee = cos.flatMap { [[=11=].0, [=11=].1] }

结果：

[["aaa", "111"], ["ddd", "444"], ["bbb", "222"], ["eee", "555"],["ccc", "333"], ["fff", "666"]]

简答：

var result = zip(arr1, arr2).flatMap { [[=13=].0, [=13=].1] }

Swift 2 - 合并两个数组

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