不同 Delphi / PHP 使用 Rijndael 的加密-解密

Question

我正在尝试使用 Rijndael 加密/解密字符串，从 php 到 Delphi 并返回。

如果我从 Delphi 解密一个 PHP 字符串...工作正常。

如果我用 Delphi 加密字符串，结果字符串可以但更短

为了测试，我使用了一个包含 62 个字符的字符串。 delphi 的加密字符串比 PHP

少 4 个字符

这些字符串...最后一个字符：

PHP: GyLWj1anBJRmE8mBsaO5cvTrcbvvA==

Delphi: GyLWj1anBJRmE8mBsaO5cvTrcbv

感谢任何建议

我使用这个源代码示例：

PHP:

function encrypt ($key, $value)
{
  $padSize = 16 - (strlen ($value) % 16) ;
  $value = $value . str_repeat (chr ($padSize), $padSize) ;
  $output = mcrypt_encrypt (MCRYPT_RIJNDAEL_128, $key, $value, MCRYPT_MODE_CBC, 'xxxxxxx') ;
  return base64_encode ($output) ;
}

Delphi加密：

function EncryptData3(Data: string; AKey: AnsiString; AIv: AnsiString): string;
var
  cipher: TDCP_rijndael;
  key, iv, src, dest, b64: TBytes;
  index, slen, bsize, pad: integer;
begin
  //key := Base64DecodeBytes(TEncoding.UTF8.GetBytes(AKey));
  //iv := Base64DecodeBytes(TEncoding.UTF8.GetBytes(AIv));
  key := TEncoding.ASCII.GetBytes(AKey);
  iv := TEncoding.ASCII.GetBytes(AIv);

  src := TEncoding.ascii.GetBytes(Data);

  cipher := TDCP_rijndael.Create(nil);
  try
    cipher.CipherMode := cmCBC;
    // Add padding.
    // Resize the Value array to make it a multiple of the block length.
    // If it's already an exact multiple then add a full block of padding.
    slen := Length(src);
    bsize := (cipher.BlockSize div 8);
    pad := bsize - (slen mod bsize);
    Inc(slen, pad);
    SetLength(src, slen);

    for index := pad downto 1 do
    begin
      src[slen - index] := pad;
    end;

    SetLength(dest, slen);
    cipher.Init(key[0], 256, @iv[0]); // DCP uses key size in BITS not BYTES
    cipher.Encrypt(src[0], dest[0], slen);

    b64 := Base64EncodeBytes(dest);
    result := TEncoding.Default.GetString(b64);
  finally
    cipher.Free;
  end;
end;

Delphi 解密 ... 无效：

function DecryptData3(Data: string; AKey: AnsiString; AIv: AnsiString): string;
var
  key, iv, src, dest: TBytes;
  cipher: TDCP_rijndael;
  slen, pad: integer;
begin
  //key := Base64DecodeBytes(TEncoding.UTF8.GetBytes(AKey));
  //iv := Base64DecodeBytes(TEncoding.UTF8.GetBytes(AIv));
  key := TEncoding.ASCII.GetBytes(AKey);
  iv := TEncoding.ASCII.GetBytes(AIv);

  src := Base64DecodeBytes(TEncoding.UTF8.GetBytes(Data));

  cipher := TDCP_rijndael.Create(nil);
  try
    cipher.CipherMode := cmCBC;
    slen := Length(src);
    SetLength(dest, slen);
    cipher.Init(key[0], 256, @iv[0]); // DCP uses key size in BITS not BYTES
    cipher.Decrypt(src[0], dest[0], slen);
    // Remove the padding. Get the numerical value of the last byte and remove
    // that number of bytes
    pad := dest[slen - 1];
    SetLength(dest, slen - pad);

    // Base64 encode it
    result := TEncoding.Default.GetString(dest);
  finally
    cipher.Free;
  end;
end;

Answer 1

我不知道我是否使用了正确的方法...但是如果我转换字符串中的字节值并在此 link:

中使用此 Base64Encode

Simple code to encrypt an .INI file string using a password

现在我正确加密了。这是示例：

SetString(stringValue, PAnsiChar(@dest[0]), slen); 
result := Base64Encode2(stringValue);

不同 Delphi / PHP 使用 Rijndael 的加密-解密

different Delphi / PHP Encryption-Decryption using Rijndael

php

delphi

encryption

cryptography

rijndael