AngularJS 将表达式用作函数的参数时抛出语法分析错误

AngularJS throwing syntax parse error when using expression as a parameter of a function

我在尝试解析此标记时遇到错误,基本上我需要使用表达式作为 ng-click 中函数的参数,但它不允许。如果我不使用表达式,那么在单击相册 imgimg src="{{image.media.m}}" ng-model="image.media.m" 中的 src 将被清除,导致图像消失。这个错误导致我的 saveToAlbum 功能无法正常工作..

我想知道正确的写法是什么?为什么不允许这样做?

<ul class="images-list">
    <li ng-repeat="image in imageGroup" ng-controller="albumsCtrl">
        <img src="{{image.media.m}}" ng-model="image.media.m">
        <div class="topDiv">
            <img src="img/album.png" ng-click="saveToAlbum({{image.media.m}}, undefined)">
        </div>
        <div class="bottomDiv" ng-controller="favoritesCtrl">
            <img src="img/favorites.png" ng-click="addToFavorites(image.media.m)">
        </div>
    </li>
</ul>

错误:

Error: [$parse:syntax] http://errors.angularjs.org/1.3.10/$parse/syntax?p0=%7B&p1=invalid%20key&p2=14&p3=saveToAlbum(%7B%7Bimage.media.m%7D%7D%2C%20undefined)&p4=%7Bimage.media.m%7D%7D%2C%20undefined)
at Error (native)
at https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:6:417
at hb.throwError (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:190:254)
at hb.object (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:199:435)
at hb.primary (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:189:308)
at hb.unary (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:197:82)
at hb.multiplicative (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:196:324)
at hb.additive (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:196:182)
at hb.relational (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:196:48)
at hb.equality (https://ajax.googleapis.com/ajax/libs/angularjs/1.3.10/angular.min.js:195:418) <img src="img/album.png" ng-click="saveToAlbum({{image.media.m}}, undefined)">

对 src='' 使用 ng-src 并在 saveToAlbum 函数中松开 {{}}