PHP URL 中的分页不同符号
PHP Pagination Different Symbols in URL
当用户搜索 A B
时,URL 在第一页显示 A+B
,但在第二页显示 A%20B
,
或者如果搜索 A&B
第一页有 A%26B
,但第二页有 A&B
。我该怎么做才能在接下来的每一页都保持相同的符号?
代码:
<?php
$total_pages = $query
$targetpage = "search.php";
$limit = 36; //Items per page
$page = $_GET['page'];
if($page)
$start = ($page - 1) * $limit;
else
$start = 0;
if ($page == 0) $page = 1;
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total_pages/$limit);
$lpm1 = $lastpage - 1;
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination\">";
//previous button
if ($page > 1)
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$prev\">prev</a>";
else
$pagination.= "<span class=\"disabled\">prev</span>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=2\">2</a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
}
}
//next button
if ($page < $counter - 1)
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$next\">next</a>";
else
$pagination.= "<span class=\"disabled\">next</span>";
$pagination.= "</div>\n";
}
?>
构建 URL 时,您必须手动对查询字符串进行编码。用PHP构造时用urlencode()
,用JS构造URL时用encodeURIComponent()
PHP 示例
$pagination.= "<a href=\"$targetpage?search=".urlencode($search)."&submit=submit&page=1\">1</a>";
JS 示例
var pagination += "<a href=\"$targetpage?search="+encodeURIComponent(search)+"&submit=submit&page=1\">1</a>";
当用户搜索 A B
时,URL 在第一页显示 A+B
,但在第二页显示 A%20B
,
或者如果搜索 A&B
第一页有 A%26B
,但第二页有 A&B
。我该怎么做才能在接下来的每一页都保持相同的符号?
代码:
<?php
$total_pages = $query
$targetpage = "search.php";
$limit = 36; //Items per page
$page = $_GET['page'];
if($page)
$start = ($page - 1) * $limit;
else
$start = 0;
if ($page == 0) $page = 1;
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total_pages/$limit);
$lpm1 = $lastpage - 1;
$pagination = "";
if($lastpage > 1)
{
$pagination .= "<div class=\"pagination\">";
//previous button
if ($page > 1)
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$prev\">prev</a>";
else
$pagination.= "<span class=\"disabled\">prev</span>";
//pages
if ($lastpage < 7 + ($adjacents * 2)) //not enough pages to bother breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
}
elseif($lastpage > 5 + ($adjacents * 2)) //enough pages to hide some
{
//close to beginning; only hide later pages
if($page < 1 + ($adjacents * 2))
{
for ($counter = 1; $counter < 4 + ($adjacents * 2); $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lastpage\">$lastpage</a>";
}
//in middle; hide some front and some back
elseif($lastpage - ($adjacents * 2) > $page && $page > ($adjacents * 2))
{
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=2\">2</a>";
$pagination.= "...";
for ($counter = $page - $adjacents; $counter <= $page + $adjacents; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
$pagination.= "...";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lpm1\">$lpm1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$lastpage\">$lastpage</a>";
}
//close to end; only hide early pages
else
{
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=1\">1</a>";
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=2\">2</a>";
$pagination.= "...";
for ($counter = $lastpage - (2 + ($adjacents * 2)); $counter <= $lastpage; $counter++)
{
if ($counter == $page)
$pagination.= "<span class=\"current\">$counter</span>";
else
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$counter\">$counter</a>";
}
}
}
//next button
if ($page < $counter - 1)
$pagination.= "<a href=\"$targetpage?search=$search&submit=submit&page=$next\">next</a>";
else
$pagination.= "<span class=\"disabled\">next</span>";
$pagination.= "</div>\n";
}
?>
构建 URL 时,您必须手动对查询字符串进行编码。用PHP构造时用urlencode()
,用JS构造URL时用encodeURIComponent()
PHP 示例
$pagination.= "<a href=\"$targetpage?search=".urlencode($search)."&submit=submit&page=1\">1</a>";
JS 示例
var pagination += "<a href=\"$targetpage?search="+encodeURIComponent(search)+"&submit=submit&page=1\">1</a>";