Symfony 表单（作为带有 Doctrine 的独立组件）EntityType 不工作

Question

我使用的是没有 Symfony 框架其余部分的 Symfony 表单 (v3.0)。使用 Doctrine v2.5.

我创建了一个表单，这里是表单类型 class:

class CreateMyEntityForm extends BaseFormType {

    public function buildForm(FormBuilderInterface $builder, array $options){
        $builder->add('myEntity', EntityType::class);
    }
}

加载页面时，出现以下错误。

Argument 1 passed to Symfony\Bridge\Doctrine\Form\Type\DoctrineType::__construct() must be an instance of Doctrine\Common\Persistence\ManagerRegistry, none given, called in /var/www/dev3/Vendor/symfony/form/FormRegistry.php on line 85

我认为这里需要进行一些配置，但我不知道如何创建一个 class 来实现 ManagerRegistryInterface - 如果这是正确的做法。

有什么指点吗？

编辑 - 这是我设置 Doctrine 的代码

use Doctrine\ORM\EntityManager;
use Doctrine\ORM\Tools\Setup;

class Bootstrap {

    //...some other methods, including getCredentials() which returns DB credentials for Doctrine

    public function getEntityManager($env){

        $isDevMode = $env == 'dev';

        $paths = [ROOT_DIR . '/src'];

        $config = Setup::createAnnotationMetadataConfiguration($paths, $isDevMode, null, null, false);

        $dbParams = $this->getCredentials($env);

        $em = EntityManager::create($dbParams, $config);

        return $em;
    }
}

Answer 1

相信我，你是在自找麻烦！

当

EntityType::class 无缝集成到 "Symfony" 框架时可以工作（引擎盖下有魔法 - 通过 DoctrineBundle）。否则，您需要编写大量代码才能使其正常工作。
不值得努力！

如果您创建实体存储库并将其注入表单构造函数，然后在 ChoiceType::class 字段中使用，就会容易得多。像这样思考：

<?php
# you form class
namespace Application\Form\Type;

use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\Extension\Core\Type\ChoiceType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;

class InvoiceItemtType extends AbstractType
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
        $builder->add('product', ChoiceType::class, [
            'choices' => $this->loadProducts($options['products'])
        ]);
    }

    public function configureOptions(OptionsResolver $resolver)
    {
        $resolver->setDefaults(['products' => [],]); # custom form option
    }

    private function loadProducts($productsCollection)
    {
        # custom logic here (if any)
    }
}

在应用程序的某处：

$repo = $entityManager->getRepository(Product::class);
$formOptions = ['products' => $repo->findAll()];
$formFactory = Forms::createFormFactory();
$formFactory->create(InvoiceItemtType::class, new InvoiceItem, $formOptions);

这就是重点！

Answer 2

解决您的问题的最简单方法是从 Doctrine 桥中注册 DoctrineOrmExtension，以确保实体类型已注册到所需的依赖项。

基本上，引导 Form 组件的过程如下所示：

// a Doctrine ManagerRegistry instance (you will probably already build this somewhere else)
$managerRegistry = ...;

$doctrineOrmExtension = new DoctrineOrmExtension($managerRegistry);

// the list of form extensions
$extensions = array();

// register other extensions
// ...

// add the DoctrineOrmExtension
$extensions[] = $doctrineOrmExtension;

// a ResolvedFormTypeFactoryInterface instance
$resolvedTypeFactory = ...;

$formRegistry = new FormRegistry($extensions, $resolvedTypeFactory);

Answer 3

扩展 xabbuh 的答案。

我能够在 FormBuilder 中实现 EntityType，而无需太多额外的工作。但是，它不适用于注释，以便直接在实体内部使用 Constraints，这需要做更多的工作。

您可以轻松满足 Doctrine ORM Forms Extension 的 ManagerRegistry 要求，方法是扩展现有 AbstractManagerRegistry 并在自定义 ManagerRegistry 中创建您自己的容器属性 .

那么只需像注册任何其他扩展一样注册表单扩展（ValidatorExtension、HttpFoundationExtension 等）。

ManagerRegistry

use \Doctrine\Common\Persistence\AbstractManagerRegistry;

class ManagerRegistry extends AbstractManagerRegistry
{

    /**
     * @var array
     */
    protected $container = [];

    public function __construct($name, array $connections, array $managers, $defaultConnection, $defaultManager, $proxyInterfaceName)
    {
        $this->container = $managers;
        parent::__construct($name, $connections, array_keys($managers), $defaultConnection, $defaultManager, $proxyInterfaceName);
    }

    protected function getService($name)
    {   
        return $this->container[$name];
       //alternatively supply the entity manager here instead
    }

    protected function resetService($name)
    {
        //unset($this->container[$name]);
        return; //don't want to lose the manager
    }


    public function getAliasNamespace($alias)
    {
        throw new \BadMethodCallException('Namespace aliases not supported');
    }

}

创建表单

use Symfony\Bridge\Doctrine\Form\Type\EntityType;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;

class UserType extends AbstractType 
{
    public function buildForm(FormBuilderInterface $builder, array $options)
    {
       $builder->add('field_name', EntityType::class, [
           'class' => YourEntity::class,
           'choice_label' => 'id'
       ]);
    }

    public function configureOptions(OptionsResolver $resolver)
    {
       $resolver->setDefaults(['data_class' => YourAssociatedEntity::class]);
    }
}

配置表单生成器以使用扩展并使用表单

$managerRegistry = new \ManagerRegistry('default', [], ['default' => $entityManager], null, 'default', 'Doctrine\ORM\Proxy\Proxy');

$extension = new \Symfony\Bridge\Doctrine\Form\DoctrineOrmExtension($managerRegistry);

$formBuilder = \Symfony\Component\Form\FormFactoryBuilder::createFormFactoryBuilder();
$formBuilder->addExtension($extension);

$formFactory = $formBuilder->getFormFactory();

$form = $formFactory->create(new \UserType, $data, $options);

以上仅供演示！虽然它确实功能，它被认为是最好的练习 avoid using Doctrine Entities inside of Forms。使用 DTO（数据 Transfer Object) 而不是。

ENTITIES SHOULD ALWAYS BE VALID

INVALID STATE SHOULD BE IN A DIFFERENT OBJECT
(You may need a DTO)
(Also applies to Temporary State)

AVOID SETTERS

AVOID COUPLING WITH THE APPLICATION LAYER

FORM COMPONENTS BREAK ENTITY VALIDITY
BOTH SYMFONY\FORM AND ZEND\FORM ARE TERRIBLE
(For this use-case)
Use a DTO instead

学说 2.5+ "NEW" Operator Syntax

class CustomerDTO
{
    public function __construct($name, $email, $city, $value = null)
    {
        // Bind values to the object properties.
    }
}

$query = $em->createQuery('SELECT NEW CustomerDTO(c.name, e.email, a.city) FROM Customer c JOIN c.email e JOIN c.address a');
$users = $query->getResult(); // array of CustomerDTO

Symfony 表单（作为带有 Doctrine 的独立组件）EntityType 不工作

Symfony forms (as standalone component with Doctrine) EntityType not working

php

symfony-forms

symfony

doctrine-orm