Laravel 5.2 - Eloquent 模型查询

Question

我在尝试使用 Eloquent 模型执行非常基本的查询时遇到问题，其中 create 和 find两者都工作正常，但 where returns nothing.

型号：

namespace App;
use Illuminate\Database\Eloquent\Model;

class Company extends Model
{
protected $table = 'companies';
protected $fillable = ['name', 'ticker', 'industry', 'sector', 'description'];
protected $visible = ['name', 'ticker', 'industry', 'sector', 'description'];
}

控制器：

创建工作正常：

\App\Company::create(['ticker'=>'AAPL', 'name' => 'Apple Inc']);

在数据库上创建一个新行：

(id, name, ticker)

1, Apple Inc, AAPL

Find 工作正常：

$company = \App\Company::find(1);
print_r($company);

returns

App\Company Object ( [table:protected] => companies [fillable:protected] => Array ( [0] => name [1] => ticker [2] => industry [3] => sector [4] => description ) [visible:protected] => Array ( [0] => name [1] => ticker [2] => industry [3] => sector [4] => description ) [connection:protected] => [primaryKey:protected] => id [perPage:protected] => 15 [incrementing] => 1 [timestamps] => 1 [attributes:protected] => Array ( [id] => 1 [name] => Apple Inc [ticker] => AAPL [industry] => [sector] => [description] => [created_at] => 2016-01-14 00:01:35 [updated_at] => 2016-01-14 00:01:35 ) [original:protected] => Array ( [id] => 1 [name] => Apple Inc [ticker] => AAPL [industry] => [sector] => [description] => [created_at] => 2016-01-14 00:01:35 [updated_at] => 2016-01-14 00:01:35 ) [relations:protected] => Array ( ) [hidden:protected] => Array ( ) [appends:protected] => Array ( ) [guarded:protected] => Array ( [0] => * ) [dates:protected] => Array ( ) [dateFormat:protected] => [casts:protected] => Array ( ) [touches:protected] => Array ( ) [observables:protected] => Array ( ) [with:protected] => Array ( ) [morphClass:protected] => [exists] => 1 [wasRecentlyCreated] => )

现在，当我尝试通过 id 以外的任何字段进行搜索时，它 return 什么都没有：

$company = \DB::table('companies')->select('ticker', 'name')->where('ticker', '=', 'AAPL')->get();
print_r($company);

returns 一个空数组：

Array ( )

并且两者：

$company = \App\Company::find(['ticker', 'AAPL'])->first();
print_r($company);

和：

$company = \App\Company::where('ticker', '=', 'AAPL')->first();
print_r($company);

他们只是return什么都没有。

---更新---

迁移：

use Illuminate\Database\Schema\Blueprint;
use Illuminate\Database\Migrations\Migration;

class CreateCompaniesTable extends Migration
{   
    public function up()
    {
        Schema::create('companies', function (Blueprint $table) {
            $table->increments('id');
            $table->string('name')->unique();
            $table->string('ticker');
            $table->string('industry')->nullable();
            $table->string('sector')->nullable();
            $table->text('description')->nullable();
            $table->timestamps();
        });
    }

    public function down()
    {
        Schema::drop('companies');
    }
}

Answer 1

固定：

我从其他网站读到的代码带有奇怪的特征（感谢@ceejayoz，感谢您的帮助）

手动创建 Company 效果很好，因为我是 'hard coding' 代码：

\App\Company::create(['ticker'=>'AAPL', 'name' => 'Apple Inc']);

至于我从其他网站上删除的公司，在存储之前这样做就可以了：

str_replace(array('.', ' ', "\n", "\t", "\r"), '', $ticker);

显然，如果自动收报机有一个进位 and/or zero-length 空格，并且我正在使用经过修剪的自动收报机查询结果为空。更新代码后，Model 适用于：

$company = \App\Company::where('ticker', '=', $ticker)->first();

Laravel 5.2 - Eloquent 模型查询

Laravel 5.2 - Eloquent Model Query

php

mysql

eloquent

laravel-5.2