SQL 没有周末和 public 节假日的 DateDiff
SQL DateDiff without weekends and public holidays
我正在寻找如何 select 两个日期之间没有周末和 public 假期的天数的解决方案。
到目前为止我有这个：
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
--- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
FROM events AS evnt
一切正常，直到我取消注释部分：
- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
我想要实现的是获取日期范围内的工作日数。问题出在最后一步，我试图从这个范围中减去所有 public 假期。
有人可以帮忙完成最后一步吗？看来，我做错了什么，但我不知道是什么。
提前致谢
梶山，
试试这个：
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
-(SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
FROM events AS evnt
看起来您在 COUNT(*)
之前遗漏了 SELECT 语句
这里是 WITH common_table_expression (CTE)
的不同答案
;with t as
(
select COUNT(*) as cnt FROM public_holidays
WHERE date_from BETWEEN evnt.date_from AND evnt.date_to
)
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
- (select cnt from T)
FROM events AS evnt
试试这个：
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
- (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
FROM events AS evnt
取消注释应该是子查询
--- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
像这样：
- (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
（我看到这已经回答了，但我还是会把它扔掉...）
将日历 table 的每一天作为一行而不是单独的 public_holidays table 可能不是一个坏主意。查看文章 SQL Server Calendar Table 以获得演示和可下载的 T-SQL 代码。包括一些 follow-on 篇查询和会计年度文章。
我看到了一些示例 elsewhere，如下所示。
如果您正在寻找 'business day diff'，那么还请将其与正常日历日差异（即 DATEDIFF）进行比较。在这两种情况下，两个相邻工作日之间的差异应为 1 天。其他解决方案导致周二和周三之间的两个工作日。
DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '1/17/19'
SET @EndDate = '1/18/19'
-- CalendarDateDiff vs Business Date Diff
SELECT
DATEDIFF(d, @StartDate, @EndDate) AS CalendarDateDiff
, (DATEDIFF(dd, @StartDate, @EndDate) + 1)
-1
-(DATEDIFF(wk, @StartDate, @EndDate) * 2)
-(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END) AS CalendarDays
三个标量函数：ShiftHolidayToWorkday、GetHoliday 和 GetWorkDays
create FUNCTION [dbo].[ShiftHolidayToWorkday](@date date)
RETURNS date
AS
BEGIN
IF DATENAME( dw, @Date ) = 'Saturday'
SET @Date = DATEADD(day, - 1, @Date)
ELSE IF DATENAME( dw, @Date ) = 'Sunday'
SET @Date = DATEADD(day, 1, @Date)
RETURN @date
END
GO
create FUNCTION [dbo].[GetHoliday](@date date)
RETURNS varchar(50)
AS
BEGIN
declare @s varchar(50)
SELECT @s = CASE
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]+1) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-07-04') = @date THEN 'Independence Day'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-12-25') = @date THEN 'Christmas Day'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-12-31') = @date THEN 'New Years Eve'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-11-11') = @date THEN 'Veteran''s Day'
WHEN [Month] = 1 AND [DayOfMonth] BETWEEN 15 AND 21 AND [DayName] = 'Monday' THEN 'Martin Luther King Day'
WHEN [Month] = 5 AND [DayOfMonth] >= 25 AND [DayName] = 'Monday' THEN 'Memorial Day'
WHEN [Month] = 9 AND [DayOfMonth] <= 7 AND [DayName] = 'Monday' THEN 'Labor Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 22 AND 28 AND [DayName] = 'Thursday' THEN 'Thanksgiving Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 23 AND 29 AND [DayName] = 'Friday' THEN 'Day After Thanksgiving'
ELSE NULL END
FROM (
SELECT
[Year] = YEAR(@date),
[Month] = MONTH(@date),
[DayOfMonth] = DAY(@date),
[DayName] = DATENAME(weekday,@date)
) c
RETURN @s
END
GO
create FUNCTION [dbo].GetHolidays(@year int)
RETURNS TABLE
AS
RETURN (
select dt, dbo.GetHoliday(dt) as Holiday
from (
select dateadd(day, number, convert(varchar,@year) + '-01-01') dt
from master..spt_values
where type='p'
) d
where year(dt) = @year and dbo.GetHoliday(dt) is not null
)
create proc UpdateHolidaysTable
as
if not exists(select TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_NAME = 'Holidays')
create table Holidays(dt date primary key clustered, Holiday varchar(50))
declare @year int
set @year = 1990
while @year < year(GetDate()) + 20
begin
insert into Holidays(dt, Holiday)
select a.dt, a.Holiday
from dbo.GetHolidays(@year) a
left join Holidays b on b.dt = a.dt
where b.dt is null
set @year = @year + 1
end
create FUNCTION [dbo].[GetWorkDays](@StartDate DATE = NULL, @EndDate DATE = NULL)
RETURNS INT
AS
BEGIN
IF @StartDate IS NULL OR @EndDate IS NULL
RETURN 0
IF @StartDate >= @EndDate
RETURN 0
DECLARE @Days int
SET @Days = 0
IF year(@StartDate) * 100 + datepart(week, @StartDate) = year(@EndDate) * 100 + datepart(week, @EndDate)
--same week
select @Days = (DATEDIFF(dd, @StartDate, @EndDate))
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
ELSE
--diff weeks
select @Days = (DATEDIFF(dd, @StartDate, @EndDate) + 1)
- (DATEDIFF(wk, @StartDate, @EndDate) * 2)
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
RETURN @Days
END
我正在寻找如何 select 两个日期之间没有周末和 public 假期的天数的解决方案。
到目前为止我有这个：
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
--- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
FROM events AS evnt
一切正常，直到我取消注释部分：
- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
我想要实现的是获取日期范围内的工作日数。问题出在最后一步，我试图从这个范围中减去所有 public 假期。
有人可以帮忙完成最后一步吗？看来，我做错了什么，但我不知道是什么。
提前致谢
梶山，
试试这个：
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
-(SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
FROM events AS evnt
看起来您在 COUNT(*)
SELECT 语句
这里是 WITH common_table_expression (CTE)
的不同答案;with t as
(
select COUNT(*) as cnt FROM public_holidays
WHERE date_from BETWEEN evnt.date_from AND evnt.date_to
)
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
- (select cnt from T)
FROM events AS evnt
试试这个：
SELECT evnt.event_id,
evnt.date_from,
evnt.date_to,
DATEDIFF(DD, evnt.date_from, evnt.date_to)
- (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2)
- CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END
+ CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
- (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
FROM events AS evnt
取消注释应该是子查询
--- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
像这样：
- (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
（我看到这已经回答了，但我还是会把它扔掉...）
将日历 table 的每一天作为一行而不是单独的 public_holidays table 可能不是一个坏主意。查看文章 SQL Server Calendar Table 以获得演示和可下载的 T-SQL 代码。包括一些 follow-on 篇查询和会计年度文章。
我看到了一些示例 elsewhere，如下所示。
如果您正在寻找 'business day diff'，那么还请将其与正常日历日差异（即 DATEDIFF）进行比较。在这两种情况下，两个相邻工作日之间的差异应为 1 天。其他解决方案导致周二和周三之间的两个工作日。
DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '1/17/19'
SET @EndDate = '1/18/19'
-- CalendarDateDiff vs Business Date Diff
SELECT
DATEDIFF(d, @StartDate, @EndDate) AS CalendarDateDiff
, (DATEDIFF(dd, @StartDate, @EndDate) + 1)
-1
-(DATEDIFF(wk, @StartDate, @EndDate) * 2)
-(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END) AS CalendarDays
三个标量函数：ShiftHolidayToWorkday、GetHoliday 和 GetWorkDays
create FUNCTION [dbo].[ShiftHolidayToWorkday](@date date)
RETURNS date
AS
BEGIN
IF DATENAME( dw, @Date ) = 'Saturday'
SET @Date = DATEADD(day, - 1, @Date)
ELSE IF DATENAME( dw, @Date ) = 'Sunday'
SET @Date = DATEADD(day, 1, @Date)
RETURN @date
END
GO
create FUNCTION [dbo].[GetHoliday](@date date)
RETURNS varchar(50)
AS
BEGIN
declare @s varchar(50)
SELECT @s = CASE
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]+1) + '-01-01') = @date THEN 'New Year'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-07-04') = @date THEN 'Independence Day'
WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year] ) + '-12-25') = @date THEN 'Christmas Day'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-12-31') = @date THEN 'New Years Eve'
--WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-11-11') = @date THEN 'Veteran''s Day'
WHEN [Month] = 1 AND [DayOfMonth] BETWEEN 15 AND 21 AND [DayName] = 'Monday' THEN 'Martin Luther King Day'
WHEN [Month] = 5 AND [DayOfMonth] >= 25 AND [DayName] = 'Monday' THEN 'Memorial Day'
WHEN [Month] = 9 AND [DayOfMonth] <= 7 AND [DayName] = 'Monday' THEN 'Labor Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 22 AND 28 AND [DayName] = 'Thursday' THEN 'Thanksgiving Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 23 AND 29 AND [DayName] = 'Friday' THEN 'Day After Thanksgiving'
ELSE NULL END
FROM (
SELECT
[Year] = YEAR(@date),
[Month] = MONTH(@date),
[DayOfMonth] = DAY(@date),
[DayName] = DATENAME(weekday,@date)
) c
RETURN @s
END
GO
create FUNCTION [dbo].GetHolidays(@year int)
RETURNS TABLE
AS
RETURN (
select dt, dbo.GetHoliday(dt) as Holiday
from (
select dateadd(day, number, convert(varchar,@year) + '-01-01') dt
from master..spt_values
where type='p'
) d
where year(dt) = @year and dbo.GetHoliday(dt) is not null
)
create proc UpdateHolidaysTable
as
if not exists(select TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_NAME = 'Holidays')
create table Holidays(dt date primary key clustered, Holiday varchar(50))
declare @year int
set @year = 1990
while @year < year(GetDate()) + 20
begin
insert into Holidays(dt, Holiday)
select a.dt, a.Holiday
from dbo.GetHolidays(@year) a
left join Holidays b on b.dt = a.dt
where b.dt is null
set @year = @year + 1
end
create FUNCTION [dbo].[GetWorkDays](@StartDate DATE = NULL, @EndDate DATE = NULL)
RETURNS INT
AS
BEGIN
IF @StartDate IS NULL OR @EndDate IS NULL
RETURN 0
IF @StartDate >= @EndDate
RETURN 0
DECLARE @Days int
SET @Days = 0
IF year(@StartDate) * 100 + datepart(week, @StartDate) = year(@EndDate) * 100 + datepart(week, @EndDate)
--same week
select @Days = (DATEDIFF(dd, @StartDate, @EndDate))
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
ELSE
--diff weeks
select @Days = (DATEDIFF(dd, @StartDate, @EndDate) + 1)
- (DATEDIFF(wk, @StartDate, @EndDate) * 2)
- (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
- (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
- (select count(*) from Holidays where dt between @StartDate and @EndDate)
RETURN @Days
END