当 Child 节点实际上是 Parent 时如何使用 XSLT 重构 XML

Question

我的 ERP 系统中有一个结构非常糟糕的 XML 源，并且 Header 与 Detail 的 Parent/Child 关系是相反的，因为在运行时，parent（键）在处理第一个详细记录之前是未知的。这是由于旧 DB2 大型机应用程序的接口编写方式所致。不幸的是，我无权修改报告，也无权更改报告，因此我必须按原样处理源代码。

这是 XML 输出的样子：

<report>
    <detail>
        <header>
            <keyfield>1231</keyfield>
            <headerfield1>foo</headerfield>
            <headerfield2>bar</headerfield2>
        </header>
        <keymatch>1231</keymatch>
        <detailfield0>Line1</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1231</keymatch>
        <detailfield0>Line2</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1231</keymatch>
        <detailfield0>Line3</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1231</keymatch>
        <detailfield0>Line4</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1231</keymatch>
        <detailfield0>Line5</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <header>
            <keyfield>1232</keyfield>
            <headerfield1>boo</headerfield>
            <headerfield2>far</headerfield2>
        </header>
        <keymatch>1232</keymatch>
        <detailfield0>Line1</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1232</keymatch>
        <detailfield0>Line2</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1232</keymatch>
        <detailfield0>Line3</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1232</keymatch>
        <detailfield0>Line4</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
    <detail>
        <keymatch>1232</keymatch>
        <detailfield0>Line5</detailfield0>
        <detailfield1>this is bad structure</detailfield1>
        <detailfield2>and not my design</detailfield2>
    </detail>
</report>

最终，我需要它的格式类似于以下内容：

<report>
    <header>
        <keyfield>1231</keyfield>
        <headerfield1>foo</headerfield>
        <headerfield2>bar</headerfield2>
            <detail>
                <keymatch>1231</keymatch>
                <detailfield0>Line1</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1231</keymatch>
                <detailfield0>Line2</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1231</keymatch>
                <detailfield0>Line3</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1231</keymatch>
                <detailfield0>Line4</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1231</keymatch>
                <detailfield0>Line5</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
    </header>
    <header>
        <keyfield>1232</keyfield>
        <headerfield1>boo</headerfield>
        <headerfield2>far</headerfield2>
            <detail>
                <keymatch>1232</keymatch>
                <detailfield0>Line1</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1232</keymatch>
                <detailfield0>Line2</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1232</keymatch>
                <detailfield0>Line3</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1232</keymatch>
                <detailfield0>Line4</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
            <detail>
                <keymatch>1232</keymatch>
                <detailfield0>Line5</detailfield0>
                <detailfield1>this is bad structure</detailfield1>
                <detailfield2>and not my design</detailfield2>
            </detail>
    </header>
</report>

诚然，我对 XSLT 了解不多，但我学得很快，而且我发现这是我需要使用的工具。对于它的价值，这是 JD Edwards 9.1，我将使用 BI Publisher 通过 XSL 模板发送数据，以便进一步移交给 EDI 合作伙伴。

谢谢，

贾斯汀

Answer 1

这样试试：

XSLT 2.0

<xsl:stylesheet version="2.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>

<xsl:template match="/report">
    <xsl:copy>
        <xsl:for-each-group select="detail" group-starting-with="detail[header]">
            <header>
                <xsl:copy-of select="header/*"/>
                <xsl:apply-templates select="current-group()"/>
            </header>
        </xsl:for-each-group>
    </xsl:copy>
</xsl:template>

<xsl:template match="detail">
    <xsl:copy>
        <xsl:copy-of select="* except header"/>
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>

当 Child 节点实际上是 Parent 时如何使用 XSLT 重构 XML

How to Restructure XML using XSLT when the Child Node is actually the Parent

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