我可以使用关键字 "in" 以某种方式分隔方法声明中的参数吗?
Can I use the keyword "in" to separate parameters in a method declaration somehow?
我想创建一个方法,它使用关键字 in
而不是逗号来分隔方法声明中的参数;类似于 foreach(a in b)
方法。
例子
Class结构
public class Length
{
public double Inches;
public double Feet;
public double Yards;
public enum Unit { Inch, Foot, Yard }
Dictionary<Unit, double> inchFactor = new Dictionary<Unit, double>()
{
{ Unit.Inch, 1 },
{ Unit.Foot, 12 },
{ Unit.Yard, 36 }
};
public Length(double value, Unit unit)
{
this.Inches = value * inchFactor[unit];
this.Feet = this.Inches / inchFactor[Unit.Foot];
this.Yards = this.Inches / inchFactor[Unit.Yard];
}
}
Class
中的方法定义
// I'd like to know how to use "in" like this ↓
public List<Length> MultiplesOf(Length divisor in Length dividend)
{
double inchEnumeration = divisor.Inches;
List<Length> multiples = new List<Length>();
while (inchEnumeration <= dividend.Inches)
{
multiples.Add(new Length(inchEnumeration, Length.Unit.Inch));
inchEnumeration += divisor.Inches;
}
return multiples;
}
理想实现
private void DrawRuler()
{
Length eighthInch = new Length(0.125, Length.Unit.Inch);
Length oneFoot = new Length(1, Length.Unit.Foot);
// Awesome.
List<Length> tickGroup = Length.MultiplesOf(eighthInch in oneFoot);
double inchPixels = 10;
foreach (Length tick in tickGroup)
{
// Draw ruler.
}
}
我研究过创建新关键字,但 C# 似乎不支持定义关键字。
如评论中所述,您不能在 C# 中定义自定义关键字(除非您扩展编译器,这是一项高级任务)。但是,如果您的目标是阐明两个参数的含义,那么我建议您改用 named arguments:
// Define the method as usual:
public List<Length> MultiplesOf(Length divisor, Length dividend)
{
// ...
}
// Then call it like so, explicitly showing what is the divisor and the dividend:
List<Length> tickGroup = Length.MultiplesOf(divisor: eighthInch, dividend: oneFoot);
虽然您无法重新定义现有关键字,但还有其他方法可以使用 Fluent Interface 以稍微不同的方式完成您的任务:
public class Length
{
// ...
public static IFluentSyntaxProvider MultiplesOf(Length divisor)
{
return new FluentSyntaxProvider(divisor);
}
public interface IFluentSyntaxProvider
{
List<Length> In(Length dividend);
}
private class FluentSyntaxProvider : IFluentSyntaxProvider
{
private Length divisor;
public FluentSyntaxProvider(Length divisor)
{
this.divisor = divisor;
}
public List<Length> In(Length dividend)
{
double inchEnumeration = divisor.Inches;
List<Length> multiples = new List<Length>();
while (inchEnumeration <= dividend.Inches)
{
multiples.Add(new Length(inchEnumeration, Length.Unit.Inch));
inchEnumeration += divisor.Inches;
}
return multiples;
}
}
}
用法示例:
// Awesome.
List<Length> tickGroup = Length.MultiplesOf(eighthInch).In(oneFoot);
我想创建一个方法,它使用关键字 in
而不是逗号来分隔方法声明中的参数;类似于 foreach(a in b)
方法。
例子
Class结构
public class Length
{
public double Inches;
public double Feet;
public double Yards;
public enum Unit { Inch, Foot, Yard }
Dictionary<Unit, double> inchFactor = new Dictionary<Unit, double>()
{
{ Unit.Inch, 1 },
{ Unit.Foot, 12 },
{ Unit.Yard, 36 }
};
public Length(double value, Unit unit)
{
this.Inches = value * inchFactor[unit];
this.Feet = this.Inches / inchFactor[Unit.Foot];
this.Yards = this.Inches / inchFactor[Unit.Yard];
}
}
Class
中的方法定义// I'd like to know how to use "in" like this ↓
public List<Length> MultiplesOf(Length divisor in Length dividend)
{
double inchEnumeration = divisor.Inches;
List<Length> multiples = new List<Length>();
while (inchEnumeration <= dividend.Inches)
{
multiples.Add(new Length(inchEnumeration, Length.Unit.Inch));
inchEnumeration += divisor.Inches;
}
return multiples;
}
理想实现
private void DrawRuler()
{
Length eighthInch = new Length(0.125, Length.Unit.Inch);
Length oneFoot = new Length(1, Length.Unit.Foot);
// Awesome.
List<Length> tickGroup = Length.MultiplesOf(eighthInch in oneFoot);
double inchPixels = 10;
foreach (Length tick in tickGroup)
{
// Draw ruler.
}
}
我研究过创建新关键字,但 C# 似乎不支持定义关键字。
如评论中所述,您不能在 C# 中定义自定义关键字(除非您扩展编译器,这是一项高级任务)。但是,如果您的目标是阐明两个参数的含义,那么我建议您改用 named arguments:
// Define the method as usual:
public List<Length> MultiplesOf(Length divisor, Length dividend)
{
// ...
}
// Then call it like so, explicitly showing what is the divisor and the dividend:
List<Length> tickGroup = Length.MultiplesOf(divisor: eighthInch, dividend: oneFoot);
虽然您无法重新定义现有关键字,但还有其他方法可以使用 Fluent Interface 以稍微不同的方式完成您的任务:
public class Length
{
// ...
public static IFluentSyntaxProvider MultiplesOf(Length divisor)
{
return new FluentSyntaxProvider(divisor);
}
public interface IFluentSyntaxProvider
{
List<Length> In(Length dividend);
}
private class FluentSyntaxProvider : IFluentSyntaxProvider
{
private Length divisor;
public FluentSyntaxProvider(Length divisor)
{
this.divisor = divisor;
}
public List<Length> In(Length dividend)
{
double inchEnumeration = divisor.Inches;
List<Length> multiples = new List<Length>();
while (inchEnumeration <= dividend.Inches)
{
multiples.Add(new Length(inchEnumeration, Length.Unit.Inch));
inchEnumeration += divisor.Inches;
}
return multiples;
}
}
}
用法示例:
// Awesome.
List<Length> tickGroup = Length.MultiplesOf(eighthInch).In(oneFoot);