如何使用 moment.js 计算 Javascript 中两个日期之间的 'Working days' 数？

Question

如何使用 moment.js 计算 JavaScript 中两个日期之间的工作日数。我有一个计算这些天的工作公式，但该公式不满足所有条件：

这是我的代码：

var start= moment(data[x].start_date);
                var end= moment(data[x].est_end_date);
                var difference= end.diff(start, 'days');
                var workingDays= Math.round((difference/7)*5);
//data[x] is for iterating over a loop

这里我每 7 天得到 5 天，因为星期六和星期日被视为非工作日，但如果从星期日或星期六开始计算天数，此公式将失败。

请任何人在这方面提供帮助，必须进行哪些必要的更改才能避免此问题。

Answer 1

只需将其分为 3 个部分.. 第一周、上周和中间的部分，如下所示：

function workday_count(start,end) {
  var first = start.clone().endOf('week'); // end of first week
  var last = end.clone().startOf('week'); // start of last week
  var days = last.diff(first,'days') * 5 / 7; // this will always multiply of 7
  var wfirst = first.day() - start.day(); // check first week
  if(start.day() == 0) --wfirst; // -1 if start with sunday 
  var wlast = end.day() - last.day(); // check last week
  if(end.day() == 6) --wlast; // -1 if end with saturday
  return wfirst + Math.floor(days) + wlast; // get the total
} //              ^ EDIT: if days count less than 7 so no decimal point

测试代码

var ftest = {date:'2015-02-0',start:1,end:7};
var ltest = {date:'2015-02-2',start:2,end:8};
var f = 'YYYY-MM-DD';
for(var z=ftest.start; z<=ftest.end; ++z) {
  var start = moment(ftest.date + z);
  for(var y=ltest.start; y<=ltest.end; ++y) {
    var end = moment(ltest.date + y);
    var wd = workday_count(start,end);
    console.log('from: '+start.format(f),'to: '+end.format(f),'is '+wd+' workday(s)');
  }
}

测试代码输出：

from: 2015-02-01 to: 2015-02-22 is 15 workday(s)
from: 2015-02-01 to: 2015-02-23 is 16 workday(s)
from: 2015-02-01 to: 2015-02-24 is 17 workday(s)
from: 2015-02-01 to: 2015-02-25 is 18 workday(s)
from: 2015-02-01 to: 2015-02-26 is 19 workday(s)
from: 2015-02-01 to: 2015-02-27 is 20 workday(s)
from: 2015-02-01 to: 2015-02-28 is 20 workday(s)
from: 2015-02-02 to: 2015-02-22 is 15 workday(s)
from: 2015-02-02 to: 2015-02-23 is 16 workday(s)
from: 2015-02-02 to: 2015-02-24 is 17 workday(s)
from: 2015-02-02 to: 2015-02-25 is 18 workday(s)
from: 2015-02-02 to: 2015-02-26 is 19 workday(s)
from: 2015-02-02 to: 2015-02-27 is 20 workday(s)
from: 2015-02-02 to: 2015-02-28 is 20 workday(s)
from: 2015-02-03 to: 2015-02-22 is 14 workday(s)
from: 2015-02-03 to: 2015-02-23 is 15 workday(s)
from: 2015-02-03 to: 2015-02-24 is 16 workday(s)
from: 2015-02-03 to: 2015-02-25 is 17 workday(s)
from: 2015-02-03 to: 2015-02-26 is 18 workday(s)
from: 2015-02-03 to: 2015-02-27 is 19 workday(s)
from: 2015-02-03 to: 2015-02-28 is 19 workday(s)
from: 2015-02-04 to: 2015-02-22 is 13 workday(s)
from: 2015-02-04 to: 2015-02-23 is 14 workday(s)
from: 2015-02-04 to: 2015-02-24 is 15 workday(s)
from: 2015-02-04 to: 2015-02-25 is 16 workday(s)
from: 2015-02-04 to: 2015-02-26 is 17 workday(s)
from: 2015-02-04 to: 2015-02-27 is 18 workday(s)
from: 2015-02-04 to: 2015-02-28 is 18 workday(s)
from: 2015-02-05 to: 2015-02-22 is 12 workday(s)
from: 2015-02-05 to: 2015-02-23 is 13 workday(s)
from: 2015-02-05 to: 2015-02-24 is 14 workday(s)
from: 2015-02-05 to: 2015-02-25 is 15 workday(s)
from: 2015-02-05 to: 2015-02-26 is 16 workday(s)
from: 2015-02-05 to: 2015-02-27 is 17 workday(s)
from: 2015-02-05 to: 2015-02-28 is 17 workday(s)
from: 2015-02-06 to: 2015-02-22 is 11 workday(s)
from: 2015-02-06 to: 2015-02-23 is 12 workday(s)
from: 2015-02-06 to: 2015-02-24 is 13 workday(s)
from: 2015-02-06 to: 2015-02-25 is 14 workday(s)
from: 2015-02-06 to: 2015-02-26 is 15 workday(s)
from: 2015-02-06 to: 2015-02-27 is 16 workday(s)
from: 2015-02-06 to: 2015-02-28 is 16 workday(s)
from: 2015-02-07 to: 2015-02-22 is 10 workday(s)
from: 2015-02-07 to: 2015-02-23 is 11 workday(s)
from: 2015-02-07 to: 2015-02-24 is 12 workday(s)
from: 2015-02-07 to: 2015-02-25 is 13 workday(s)
from: 2015-02-07 to: 2015-02-26 is 14 workday(s)
from: 2015-02-07 to: 2015-02-27 is 15 workday(s)
from: 2015-02-07 to: 2015-02-28 is 15 workday(s)

Answer 2

我发现 kokizzu 的回答在同一周内（例如太阳到坐着）不起作用，所以改为解决这个问题：

    function calcBusinessDays(startDate, endDate) { 
      var day = moment(startDate);
      var businessDays = 0;

      while (day.isSameOrBefore(endDate,'day')) {
        if (day.day()!=0 && day.day()!=6) businessDays++;
        day.add(1,'d');
      }
      return businessDays;
    }

Answer 3

我对 Kokizzu 的回答进行了改编，以解决夏令时问题。在巴西时区 (GMT -3) 中，17/10/2017 和 18/10/2017 之间的差异是 -2.71 而不是 2.

一周的开始时间是 15/10/2017 00:00 UTC 或 14/10/2017 21:00-03:00

周末是 22/10/2017 00:00 UTC 或 21/10/2017 22:00-02:00（夏令时）

因此，"first" 和 "last" 变量之间的天数差异不是 7 天，而是 6 天（或 8 天，具体取决于您所在的时区）。

修复的代码如下：

start = moment(start).utc().add(start.utcOffset(), 'm'); // Ignore timezones
end = moment(end).utc().add(end.utcOffset(), 'm'); // Ignore timezones

var first = start.clone().endOf('week'); // end of first week
var last = end.clone().startOf('week'); // start of last week

// Fixing Summer Time problems
firstCorrection = moment(first).utc().add(60, 'm').toDate(); //
var days = last.diff(firstCorrection,'days') * 5 / 7; // this will always multiply of 7

var wfirst = first.day() - start.day(); // check first week
if(start.day() == 0) --wfirst; // -1 if start with sunday
var wlast = end.day() - last.day(); // check last week
if(end.day() == 6) --wlast; // -1 if end with saturday
return wfirst + days + wlast; // get the total (subtract holidays if needed)

Answer 4

我使用一个简单的函数来完成它。也许不是最有效的，但它确实有效。它不需要 Moment.js。只是 Javascript.

function getNumWorkDays(startDate, endDate) {
    var numWorkDays = 0;
    var currentDate = new Date(startDate);
    while (currentDate <= endDate) {
        // Skips Sunday and Saturday
        if (currentDate.getDay() !== 0 && currentDate.getDay() !== 6) {
            numWorkDays++;
        }
        currentDate = currentDate.addDays(1);
    }
    return numWorkDays;
}

为了addDays，我使用了以下函数：

Date.prototype.addDays = function (days) {
    var date = new Date(this.valueOf());
    date.setDate(date.getDate() + days);
    return date;
};

Answer 5

你可以试试这个（没有循环）：

  function getBusinessDays(endDate, startDate) {
    var lastDay = moment(endDate);
    var firstDay = moment(startDate);
    let calcBusinessDays = 1 + (lastDay.diff(firstDay, 'days') * 5 -
      (firstDay.day() - lastDay.day()) * 2) / 7;

    if (lastDay.day() == 6) calcBusinessDays--;//SAT
    if (firstDay.day() == 0) calcBusinessDays--;//SUN

    return calcBusinessDays;
  }

Original Source

Answer 6

通过使用momentjs，可以这样：

private calculateWorkdays(startDate: Date, endDate: Date): number {
// + 1 cause diff returns the difference between two moments, in this case the day itself should be included.

const totalDays: number = moment(endDate).diff(moment(startDate), 'days') + 1;
const dayOfWeek = moment(startDate).isoWeekday();
let totalWorkdays = 0;

for (let i = dayOfWeek; i < totalDays + dayOfWeek; i++) {
    if (i % 7 !== 6 && i % 7 !== 0) {
      totalWorkdays++;
    }
  }
  return totalWorkdays;
}

Answer 7

我一直在使用一个有用的库moment-business-days加上moment

NPM Link of Moment-business-days

NPM Link of Moment

之间的工作日示例

const diff = moment('05-15-2017', 'MM-DD-YYYY').businessDiff(moment('05-08-2017','MM-DD-YYYY'));
// diff = 5

Answer 8

工作日应存储在数据库的 table 中并通过 API 提供，无法计算工作日。各国的假期不同，即使在美国每个州也可能有不同的假期，每个公司可能有不同的工作日

如何使用 moment.js 计算 Javascript 中两个日期之间的 'Working days' 数？

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