String trim 从后面到具体的三个字符
String trim from back to specific three characters
如何 trim 一些字符串,直到我得到三个与 "xyz" 相同的特定字符。准确地说我举个例子:
Dim String1 as String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 as String = "DontCry"
Dim ResultString as String
我需要删除右边的所有内容,直到我在 String1
中得到 "moc" (reverse "com")
,然后添加 string2
得到 ResultString
。
ResultString 应该是:"GunsAndRosesWelDontCry"
你可以使用String.IndexOf
和String.Substring
从前面开始解决:
Dim String1 as String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 as String = "DontCry"
Dim index = String1.IndexOf("com")
Dim ResultString as String = String1.Substring(0, index) + String2
编辑:
如果子串输入和字符串由于某种原因都需要反转,我会引入这样的反转字符串函数
Private Function Reverse(Val As String) As String
Dim charArray As Char() = Val.ToCharArray()
Array.Reverse(charArray)
Return New String(charArray)
End Function
然后像这样使用
Dim String1 As String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 As String = "DontCry"
Dim index = String1.Length - Reverse(String1).IndexOf(Reverse("com")) - ("com").Length
Dim ResultString As String = String1.Substring(0, index) + String2
否则,我们可以使用String.LastIndexOf
Dim String1 as String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 as String = "DontCry"
Dim index = String1.LastIndexOf("com")
Dim ResultString as String = String1.Substring(0, index) + String2
你可以这样试试,
Dim String1 As String = "GunsAndRosesWelcomeTocomeThecomJunglecom"
Dim String2 As String = "DontCry"
Dim ResultString As String
Dim ar As String() = String1.Split("com")
ResultString = ar(0) & String2
如何 trim 一些字符串,直到我得到三个与 "xyz" 相同的特定字符。准确地说我举个例子:
Dim String1 as String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 as String = "DontCry"
Dim ResultString as String
我需要删除右边的所有内容,直到我在 String1
中得到 "moc" (reverse "com")
,然后添加 string2
得到 ResultString
。
ResultString 应该是:"GunsAndRosesWelDontCry"
你可以使用String.IndexOf
和String.Substring
从前面开始解决:
Dim String1 as String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 as String = "DontCry"
Dim index = String1.IndexOf("com")
Dim ResultString as String = String1.Substring(0, index) + String2
编辑:
如果子串输入和字符串由于某种原因都需要反转,我会引入这样的反转字符串函数
Private Function Reverse(Val As String) As String
Dim charArray As Char() = Val.ToCharArray()
Array.Reverse(charArray)
Return New String(charArray)
End Function
然后像这样使用
Dim String1 As String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 As String = "DontCry"
Dim index = String1.Length - Reverse(String1).IndexOf(Reverse("com")) - ("com").Length
Dim ResultString As String = String1.Substring(0, index) + String2
否则,我们可以使用String.LastIndexOf
Dim String1 as String = "GunsAndRosesWelcomeToTheJungle"
Dim String2 as String = "DontCry"
Dim index = String1.LastIndexOf("com")
Dim ResultString as String = String1.Substring(0, index) + String2
你可以这样试试,
Dim String1 As String = "GunsAndRosesWelcomeTocomeThecomJunglecom"
Dim String2 As String = "DontCry"
Dim ResultString As String
Dim ar As String() = String1.Split("com")
ResultString = ar(0) & String2