如何通过select的结果更新一列的每一行？

Question

我想用通过 select 语句获取的值更新列的值。但是通过执行 select 我得到了整套结果，我希望每个结果都被 czi_first_name_en （一种 foreach 循环）替换这是到目前为止的内容：

UPDATE citizen_info t
SET    t.czi_first_name_en=
       (
                  SELECT     per_username
                  FROM       person
                  INNER JOIN enrollment_office
                  ON         person.per_id=enrollment_office.eof_manager_id
                  INNER JOIN card_request
                  ON         enrollment_office.eof_id=card_request.crq_enroll_office_id
                  INNER JOIN citizen
                  ON         card_request.crq_citizen_id=citizen.ctz_id
                  INNER JOIN citizen_info
                  ON         citizen.ctz_id=citizen_info.czi_id
                  WHERE      person.per_dep_id=card_request.crq_enroll_office_id) AS person_username

我该如何进行？

Answer 1

1) 我认为您只需要一个带有 JOIN 的更新（Oracle 风格）。

UPDATE
(

select 

per_username as NEW, 
czi_first_name_en as OLD
from person 
inner join enrollment_office on person.per_id=enrollment_office.eof_manager_id
inner join card_request on enrollment_office.eof_id=card_request.crq_enroll_office_id 
inner join citizen on card_request.crq_citizen_id=citizen.ctz_id 
inner join citizen_info on citizen.ctz_id=citizen_info.czi_id 
where person.per_dep_id=card_request.crq_enroll_office_id
) t

SET t.OLD = t.NEW

另请参阅：

Update statement with inner join on Oracle

2）我想你也可以按照自己的方式去做。

 UPDATE citizen_info t
 SET t.czi_first_name_en=
 (
 SELECT 
 per_username
 FROM person
 inner join enrollment_office ON person.per_id=enrollment_office.eof_manager_id
 inner join card_request ON enrollment_office.eof_id=card_request.crq_enroll_office_id
 inner join citizen ON card_request.crq_citizen_id=citizen.ctz_id 
 inner join citizen_info x ON citizen.ctz_id=x.czi_id
 WHERE person.per_dep_id=card_request.crq_enroll_office_id and x.czi_id=t.czi_id
 ) as person_username

请注意这里唯一的区别：x.czi_id=t.czi_id。这会将 x record 链接到您要更新的 t record。

Answer 2

你必须 "connect" 更新行与 sub-select 行，可能使用一些 id，请参阅我在 sub-select 末尾的尝试：

update Citizen_Info t
      set t.czi_first_name_en =
         (select per_username
          from person inner join enrollment_office
              on person.per_id = enrollment_office.eof_manager_id
            inner join card_request on
              enrollment_office.eof_id = card_request.crq_enroll_office_id
            inner join citizen on card_request.crq_citizen_id = citizen.ctz_id
            inner join citizen_info on citizen.ctz_id = citizen_info.czi_id
          where person.per_dep_id = card_request.crq_enroll_office_id
            **and t.perid = person.per_id**)

Answer 3

了解 MERGE 函数 http://en.wikipedia.org/wiki/Merge_%28SQL%29 您指定目标和源，然后在满足匹配条件时执行特定操作，例如更新

Answer 4

您也可以使用仅包含 UPDATE 子句的 MERGE 语句 -

MERGE INTO citizen_info t 
USING (SELECT person.per_username per_username, 
              citizen.ctz_id      ctz_id 
       FROM   person 
              inner join enrollment_office 
                      ON person.per_id = enrollment_office.eof_manager_id 
              inner join card_request 
                      ON enrollment_office.eof_id = 
                         card_request.crq_enroll_office_id 
              inner join citizen 
                      ON card_request.crq_citizen_id = citizen.ctz_id 
       WHERE  person.per_dep_id = card_request.crq_enroll_office_id) s 
ON(s.ctz_id = t.czi_id) 
WHEN matched THEN 
  UPDATE SET t.czi_first_name_en = s.per_username 

/

如何通过select的结果更新一列的每一行？

How to update each row of a column by the results of a select?

sql

oracle

select

sql-update