VB.Net XmlDocument.SelectNodes(xPath): 无法查询 WSDL

Question

我正在尝试从 VB.Net 中的 Alfresco WSDL 读取 SOAP 地址。

XML 看起来像这样：

<?xml version="1.0" encoding="utf-8"?>
<definitions xmlns:cmis="http://docs.oasis-open.org/ns/cmis core/200908/" xmlns:cmism="http://docs.oasis-open.org/ns/cmis/messaging/200908/" xmlns:cmisw="http://docs.oasis-open.org/ns/cmis/ws/200908/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:ns="http://schemas.xmlsoap.org/soap/encoding/" targetNamespace="http://docs.oasis-open.org/ns/cmis/ws/200908/" xmlns:jaxws="http://java.sun.com/xml/ns/jaxws" name="CMISWebServices">
   ...
   <message name="cmisException">
       <part name="fault" element="cmism:cmisFault" />
   </message>
   ...
   <service name="ACLService">
       <port name="ACLServicePort" binding="cmisw:ACLServicePortBinding">
           <soap:address location="https://myserver:8443/alfresco/cmisws/ACLService" />
       </port>
   </service>
   ...

这是我的 VB.Net 代码。我正在尝试将 XmlDocument.SelectNodes() 与 XPath 查询一起使用......但我并不高兴。

    Dim xmlReader As System.Xml.XmlTextReader = New XmlTextReader(urlWsdl)
    Dim xmlWsdl As System.Xml.XmlDocument = New XmlDocument
    xmlWsdl.Load(xmlReader)
    ...
    Dim xPath As String = "/definitions/service[@name='" & sService & "']"
    Dim serviceNodes As XmlNodeList
    While True
        Try
            serviceNodes = xmlWsdl.SelectNodes(xPath)
            PrintMsg("Count=" & serviceNodes.Count)
        Catch ex As Exception
            Logger.LogMsg("ERROR: " & ex.Message)
        End Try
    End While
    ...

我需要从 WSDL 获取几个不同服务的地址位置："ACLService"、"DiscoveryService"、"MultiFilingService"、"NavigationService" 等

我尝试了许多不同的 XPath 表达式，但我总是得到 "serviceNodes.Count" of "0":

Dim serviceNodes As XmlNodeList = xmlWsdl.SelectNodes(xPath):

XPath:                                    Count:   ServicesNodes(0).OuterXml:
-----                                     -----    -------------------------
//service[@name='ACLService']             0
//service[@name=ACLService]               0
//service                                 0
*                                         1        OuterXml: "<definitions ...>...  // Entire XML document
/definitions//service[@name=ACLService]   0
/definitions/service[@name='ACLService']  0
/definitions/service                      0

问：我做错了什么？

问：我该如何解决？

============================================= ======

非常感谢 har07，他正确地指出我需要使用 XmlNamespaceManager。

这是更新后的代码：

Dim nsManager As New XmlNamespaceManager(New NameTable())
nsManager.AddNamespace("afws", xmlWsdl.DocumentElement.NamespaceURI)
Dim xPath As String = "/afws:definitions/afws:service[@name='" & sService & "']"
Dim serviceNodes As XmlNodeList = xmlWsdl.SelectNodes(xPath, nsManager) ' Now works perfectly!

Answer 1

"What am I doing wrong?"

您的 XPath 没有考虑 默认命名空间，这里声明的没有前缀：xmlns="http://schemas.xmlsoap.org/wsdl/"。（有关详细信息，请参阅 this MSDN article 中的 默认命名空间 部分）。

"What can I do to fix it?"

使用 XmlNamespaceManager 注册前缀到默认命名空间 URI 的映射，然后在您的 XPath 中正确使用注册的前缀，例如：

....
Dim nsManager As New XmlNamespaceManager(New NameTable())
nsManager.AddNamespace("d", xmlWsdl.DocumentElement.NamespaceURI)
Dim xPath As String = "/d:definitions/d:service[@name='" & sService & "']"
....
serviceNodes = xmlWsdl.SelectNodes(xPath, nsManager)

VB.Net XmlDocument.SelectNodes(xPath): 无法查询 WSDL

VB.Net XmlDocument.SelectNodes(xPath): unable to query WSDL

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