Gulp 正在还原我的所有更改？

Question

我分叉了这个存储库：https://github.com/angular-ui/ui-select and made my changes here: https://github.com/zhen-w/ui-select。问题是，我对 angular-ui/ui-select 的源代码做了一些更改，但是当我运行命令 gulp 尝试生成文件的缩小版本时，我的所有更改似乎都得到了还原并且我生成的缩小文件没有我想要的新更改。这是gulpfile.js的内容：

var fs = require('fs');
var gulp = require('gulp');
var karma = require('karma').server;
var concat = require('gulp-concat');
var jshint = require('gulp-jshint');
var header = require('gulp-header');
var footer = require('gulp-footer');
var rename = require('gulp-rename');
var es = require('event-stream');
var del = require('del');
var uglify = require('gulp-uglify');
var minifyHtml = require('gulp-minify-html');
var minifyCSS = require('gulp-minify-css');
var templateCache = require('gulp-angular-templatecache');
var gutil = require('gulp-util');
var plumber = require('gulp-plumber');//To prevent pipe breaking caused by errors at 'watch'

var config = {
  pkg : JSON.parse(fs.readFileSync('./package.json')),
  banner:
      '/*!\n' +
      ' * <%= pkg.name %>\n' +
      ' * <%= pkg.homepage %>\n' +
      ' * Version: <%= pkg.version %> - <%= timestamp %>\n' +
      ' * License: <%= pkg.license %>\n' +
      ' */\n\n\n'
};

gulp.task('default', ['build','test']);
gulp.task('build', ['scripts', 'styles']);
gulp.task('test', ['build', 'karma']);

gulp.task('watch', ['build','karma-watch'], function() {
  gulp.watch(['src/**/*.{js,html}'], ['build']);
});

gulp.task('clean', function(cb) {
  del(['dist'], cb);
});

gulp.task('scripts', ['clean'], function() {

  var buildTemplates = function () {
    return gulp.src('src/**/*.html')
      .pipe(minifyHtml({
             empty: true,
             spare: true,
             quotes: true
            }))
      .pipe(templateCache({module: 'ui.select'}));
  };

  var buildLib = function(){
    return gulp.src(['src/common.js','src/*.js'])
      .pipe(plumber({
        errorHandler: handleError
      }))
      .pipe(concat('select_without_templates.js'))
      .pipe(header('(function () { \n"use strict";\n'))
      .pipe(footer('\n}());'))
      .pipe(jshint())
      .pipe(jshint.reporter('jshint-stylish'))
      .pipe(jshint.reporter('fail'));
  };

  return es.merge(buildLib(), buildTemplates())
    .pipe(plumber({
      errorHandler: handleError
    }))
    .pipe(concat('select.js'))
    .pipe(header(config.banner, {
      timestamp: (new Date()).toISOString(), pkg: config.pkg
    }))
    .pipe(gulp.dest('dist'))
    .pipe(uglify({preserveComments: 'some'}))
    .pipe(rename({ext:'.min.js'}))
    .pipe(gulp.dest('dist'));

});

gulp.task('styles', ['clean'], function() {

  return gulp.src('src/common.css')
    .pipe(header(config.banner, {
      timestamp: (new Date()).toISOString(), pkg: config.pkg
    }))
    .pipe(rename('select.css'))
    .pipe(gulp.dest('dist'))
    .pipe(minifyCSS())
    .pipe(rename({ext:'.min.css'}))
    .pipe(gulp.dest('dist'));

});

gulp.task('karma', ['build'], function() {
  karma.start({configFile : __dirname +'/karma.conf.js', singleRun: true});
});

gulp.task('karma-watch', ['build'], function() {
  karma.start({configFile :  __dirname +'/karma.conf.js', singleRun: false});
});

var handleError = function (err) {
  console.log(err.toString());
  this.emit('end');
};

我不明白为什么我的更改会被还原，因为这是我自己的分叉存储库。任何帮助，将不胜感激。谢谢！

Answer 1

dist 目录中的所有内容都是由 gulp 创建的 - 不仅仅是缩小的文件。如果要进行更改，请编辑 src 目录下的相应文件。

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