在 ManyToMany Doctrine queryBuilder() 中 ForeignKey 为 NULL 的实体上 select 时查询异常

Query Exception when select on entity where ForeignKey is NULL in a ManyToMany Doctrine queryBuilder()

在我的 Symfony 项目中,我有两个实体 Product.phpConfiguration.php

这是一个ManyToMany关系。

这是 Product.php 中的关系:

/**
 * @var \Doctrine\Common\Collections\Collection
 *
 * @ORM\ManyToMany(targetEntity="Configuration", inversedBy="products")
 * @ORM\JoinTable(name="product_configuration",
 *     joinColumns={@ORM\JoinColumn(name="product_id", referencedColumnName="product_id", nullable=true)},
 *     inverseJoinColumns={@ORM\JoinColumn(name="configuration_id", referencedColumnName="configuration_id")}
 * )
 **/
protected $configurations;

这是Configuration.php:

/**
 * Describes the products using $this configuration
 *
 * @var \Doctrine\Common\Collections\Collection
 *
 * @ORM\ManyToMany(targetEntity="Product", mappedBy="configurations")
 **/
protected $products;

在一个页面中,我需要恢复产品,其中没有一些配置 , 例如 FK 配置NULL.

所以我在 Productrepository.php 中创建了这个 queryBuilder()/dql :

public function getProductForCurrentWorkType($slug)
  {
    // First we get all the product even with configurations
    $selectProduct = $this->getEntityManager()->createQueryBuilder();

    $selectProduct
      ->select('p, wt, c')
      ->from('MyBundle:Product', 'p')
      ->join('p.workType', 'wt', 'WITH', 'wt.id = p.workType')
      ->join('p.configurations', 'c')
      ->where('wt.slug = :slug')
      ->setParameters(array('slug' => $slug));

    // Then we apply a filter where configurations is null for product.
    // We get all products where product.id  are not in ids of the first request
    $nullConfiguration = $this->getEntityManager()->createQueryBuilder();

    $nullConfiguration
      ->select('pr.id')
      ->from('MyBundle:Product', 'pr')
      ->where($nullConfiguration->expr()->notIn('pr.id', $selectProduct->getDQL()));

    return $nullConfiguration->getQuery()->getResult();
  }

如果我 return 仅第一个查询 e-g $selectProduct,则第一个步骤效果很好。它 return 仅适用于具有 $slug 配置的产品。 但是如果我return第二个查询(下面的代码),就会出现错误:

2/2 [Syntax Error] line 0, col 69: Error: Expected Doctrine\ORM\Query\Lexer::T_FROM, got ','

1/2 QueryException: SELECT pr FROM MyBundle:Product pr WHERE pr.id NOT IN(SELECT p, wt, c FROM MyBundle:Product p INNER JOIN p.workType wt WITH wt.id = p.workType INNER JOIN p.configurations c WHERE wt.slug = :slug)

我该如何解决这个错误?

编辑

我在 ProductRepository.php 中尝试的另一种解决方案:

$selectProduct = $this->getEntityManager()->createQueryBuilder();

    $selectProduct
      ->select('p, wt, c')
      ->from('MyBundle:Product', 'p')
      ->join('p.workType', 'wt', 'WITH', 'wt.id = p.workType')
      ->join('p.configurations', 'c')
      ->having('COUNT(c.id) = 0') // check if the collection is empty
      ->where('wt.slug = :slug')
      ->setParameters(array('slug' => $slug));

      return $selectProduct
            ->getQuery()
            ->getResult();

现在我的控制器,如果它可以帮助你:

$em = $this->getDoctrine()->getManager();
$arrayProduct = $this->getDoctrine()->getRepository('MyBundle:Product')->getProductForCurrentWorkType($slug);

if (!$arrayProduct) {
    throw $this->createNotFoundException('Unable to find a Product !');
}

//return statement

下面的代码 return 告诉我 找不到产品!,如果我用抛出 $this->createNotFoundException 删除 if 条件,页面是显示正确但没有结果。

试试这个:

$qb->select('p')
   ->from('Product','p')
   ->leftJoin('p.configurations','c')
   ->having('COUNT(c.id) = 0') // check if the collection is empty
   ->groupBy('p.id');