Python: 运行 SimpleHTTPServer 并在脚本中向它发出请求

Question

我想编写 Python 脚本：

在某个端口上启动 SimpleHTTPServer
向服务器发出请求并通过POST
运行脚本通过 shell 交互模式并与之交互

现在代码如下所示：

import SimpleHTTPServer
import SocketServer
import urllib
import urllib2

# Variables
URL = 'localhost:8000'
PORT = 8000

# Setup simple sever
Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
httpd = SocketServer.TCPServer(("", PORT), Handler)
print "serving at port", PORT
httpd.serve_forever()

# Getting HTML from the target page
values = {
    'name': 'Thomas Anderson',
    'location': 'unknown'
}
data = urlilib.urlencode(values)
req = urllib2.Request(url, data)
response = urllib2.urlopen(req)
html = response.read()

问题是一旦我运行我的脚本

python -i foo.py

它打印 serving at port 8000 然后冻结。我敢打赌这对于这里的 Python 大师来说是微不足道的，但我们将不胜感激。

Answer 1

运行服务器作为 不同的进程 ，这将允许您运行脚本的其余部分。

我也宁愿使用 requests 而不是 urllib。

import SocketServer
import SimpleHTTPServer

import requests
import multiprocessing

# Variables
PORT = 8000
URL = 'localhost:{port}'.format(port=PORT)

# Setup simple sever
Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
httpd = SocketServer.TCPServer(("", PORT), Handler)
print "Serving at port", PORT

# start the server as a separate process
server_process = multiprocessing.Process(target=httpd.serve_forever)
server_process.daemon = True
server_process.start()

# Getting HTML from the target page
values = {
    'name': 'Thomas Anderson',
    'location': 'unknown'
}

r = requests.post(URL, data=values)
r.text

# stop the server
server_process.terminate()

Answer 2

或者运行它在单独的 thread:

import SimpleHTTPServer
import SocketServer
import urllib2
from threading import Thread
from datetime import time

# Variables
URL = 'localhost:8000'
PORT = 8000

# Setup simple sever
Handler = SimpleHTTPServer.SimpleHTTPRequestHandler
httpd = SocketServer.TCPServer(("", PORT), Handler)
print "serving at port", PORT
def simple_sever():
    httpd.serve_forever()

simple_sever_T = Thread(target=simple_sever, name='simple_sever')
simple_sever_T.daemon = True
simple_sever_T.start()

while not simple_sever_T.is_alive():
    time.sleep(1)

# Getting test file
req = urllib2.Request('http://localhost:%s/test_file' % PORT)
response = urllib2.urlopen(req)
print response.read()
httpd.shutdown()

Python: 运行 SimpleHTTPServer 并在脚本中向它发出请求

Python: run SimpleHTTPServer and make request to it in a script

python

simplehttpserver

python-2.7

server