此原始查询的等效续集查询是什么？

Question

SELECT offers.id FROM offers WHERE offers.user_id != '2' and offers.id not in (select notified_offers.offer_id from notified_offers 其中 notified_offers.user_id = '2');

Answer 1

如果您关联了 Offers 和 NotifiedOffers 模型，并且它不是 many-to-many 关联，您可以这样做：

Offers.findAll({
    attributes: ['id'],
    where: {
        user_id: {
            not: 2
        }
    },
    include: {
        model: NotifiedOffers,
        where: {
            user_id: {
                not: 2
            }
        },
        required: true
    }
});