如何在 Python 中按顺序打印列表中的字符串？

Question

假设一个列表：s = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J"]

我了解如何打印列表中的每一项：

for i in s:
    print (i)

给出：

A
B
C
D
E
F
G
H
I
J

但假设我想根据 n 拆分打印。所以如果 n = 3:

A
B
C

D
E
F

G
H
I

J

这些是我的尝试：

k = 0
for i in s:
    while k < n:
        k += 1
        print (i)

和

k = 0
while k < n:
    for i in s:
        print (i)
    k += 1

我知道我的尝试还有很长的路要走，但我似乎做不到。我知道您可以根据 n 创建子列表并以这种方式解决它，但是有没有其他方法可以做到这一点？

Answer 1

k = 0
for i in s:
    if k == n-1:
       print i + '\n'
       k = 0
    else:
        print i
        k += 1

Answer 2

>>> s = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J"]
>>> n=3
>>> print('\n\n'.join(['\n'.join(s[i:i+n]) for i in range(0,len(s),n)]))
A
B
C

D
E
F

G
H
I

J

如何在 Python 中按顺序打印列表中的字符串？

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python-3.x