ASP.Net Web APi C# - GetAsync 不返回 XML 响应内容
ASP.Net Web APi C# - GetAsync not returning XML response content
我正在使用 GetAsync()
调用外部服务并在查询字符串中传递参数。当我检查响应中的内容时,我没有看到任何返回的内容,但是它 returns 200 OK
并且在 fiddler 中 returns 我 XML 响应正确。我需要 XML 响应以反序列化为 C# 对象,然后将其进一步保存到数据库。
尝试过的事情:
1) 通过在全局 app_start() 中添加此设置进行了尝试,但没有帮助
GlobalConfiguration.Configuration.Formatters.XmlFormatter.UseXmlSerializer = true;
2) 创建了一个对象并尝试通过 GetAysnc
发送它,这也没有帮助。
public class Request
{
[XmlElement]
public string XML { get; set; }
[XmlElement]
public List<string> ProNumber { get; set; }
}
2) 我应该尝试在查询字符串中传递参数并期望得到 json 结果吗?如果我将 mediatyperformatter 添加到 application/json
?
这是我的代码:
public async Task<HttpResponseMessage> GetData()
{
string requestString = "&xml=Y&PRONumber=82040X,03117X";
string result = "";
string url = @"http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController";
try
{
using (var client = new HttpClient())
{
client.BaseAddress = new Uri(url);
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/xml"));
HttpResponseMessage response = await client.GetAsync(url+requestString);
if (response.IsSuccessStatusCode)
{
return response;
}
}
}
catch (Exception ex)
{
result = ex.Message;
}
return null;
}
编辑:
Shipments scp = null;
XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "Shipment";
xRoot.IsNullable = true;
XmlSerializer serializer = new XmlSerializer(typeof(Shipment), xRoot);
using (Stream stream = response.Content.ReadAsStreamAsync().Result)
{
scp = (Shipments)serializer.Deserialize(stream);
}
型号:
public class Shipments
{
[XmlArrayItem(Type = typeof(Shipment))]
public Shipment[] Shipment;
}
public class Shipment
{
[XmlAttribute()]
public int returnCode { get; set; }
.................
..............
获取错误:<SHIPMENTS xmlns=''> was not expected.
非常感谢任何帮助。
谢谢,
白
这对我有用 -
var client = new HttpClient();
var data = client.GetStringAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(new StringReader(data));
public class Shipment
{
public string returnCode { get; set; }
public string returnMessage { get; set; }
public string freightBillNumber { get; set; }
//props
}
[XmlRoot(ElementName = "SHIPMENTS")]
public class Shipments
{
[XmlElement(ElementName = "SHIPMENT")]
public List<Shipment> SHIPMENT { get; set; }
}
编辑
这也行 -
var data = client.GetStreamAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
编辑
同样有效 -
var client = new HttpClient();
var data = client.GetAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(data.Content.ReadAsStreamAsync().Result);
我正在使用 GetAsync()
调用外部服务并在查询字符串中传递参数。当我检查响应中的内容时,我没有看到任何返回的内容,但是它 returns 200 OK
并且在 fiddler 中 returns 我 XML 响应正确。我需要 XML 响应以反序列化为 C# 对象,然后将其进一步保存到数据库。
尝试过的事情:
1) 通过在全局 app_start() 中添加此设置进行了尝试,但没有帮助
GlobalConfiguration.Configuration.Formatters.XmlFormatter.UseXmlSerializer = true;
2) 创建了一个对象并尝试通过 GetAysnc
发送它,这也没有帮助。
public class Request
{
[XmlElement]
public string XML { get; set; }
[XmlElement]
public List<string> ProNumber { get; set; }
}
2) 我应该尝试在查询字符串中传递参数并期望得到 json 结果吗?如果我将 mediatyperformatter 添加到 application/json
?
这是我的代码:
public async Task<HttpResponseMessage> GetData()
{
string requestString = "&xml=Y&PRONumber=82040X,03117X";
string result = "";
string url = @"http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController";
try
{
using (var client = new HttpClient())
{
client.BaseAddress = new Uri(url);
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/xml"));
HttpResponseMessage response = await client.GetAsync(url+requestString);
if (response.IsSuccessStatusCode)
{
return response;
}
}
}
catch (Exception ex)
{
result = ex.Message;
}
return null;
}
编辑:
Shipments scp = null;
XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "Shipment";
xRoot.IsNullable = true;
XmlSerializer serializer = new XmlSerializer(typeof(Shipment), xRoot);
using (Stream stream = response.Content.ReadAsStreamAsync().Result)
{
scp = (Shipments)serializer.Deserialize(stream);
}
型号:
public class Shipments
{
[XmlArrayItem(Type = typeof(Shipment))]
public Shipment[] Shipment;
}
public class Shipment
{
[XmlAttribute()]
public int returnCode { get; set; }
.................
..............
获取错误:<SHIPMENTS xmlns=''> was not expected.
非常感谢任何帮助。
谢谢, 白
这对我有用 -
var client = new HttpClient();
var data = client.GetStringAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(new StringReader(data));
public class Shipment
{
public string returnCode { get; set; }
public string returnMessage { get; set; }
public string freightBillNumber { get; set; }
//props
}
[XmlRoot(ElementName = "SHIPMENTS")]
public class Shipments
{
[XmlElement(ElementName = "SHIPMENT")]
public List<Shipment> SHIPMENT { get; set; }
}
编辑
这也行 -
var data = client.GetStreamAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
编辑
同样有效 -
var client = new HttpClient();
var data = client.GetAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(data.Content.ReadAsStreamAsync().Result);