MySQL 如何显示也不匹配 where 子句的行

Question

我有这个查询：

SELECT `y78f2_students`.`firstname` , `y78f2_students`.`lastName` , `y78f2_students`.`student_id`,`y78f2_attendance`.`is_present`, `y78f2_attendance`.`note`, `y78f2_attendance`.`thedate`  
FROM `y78f2_students`
INNER JOIN `y78f2_enrolls` ON `y78f2_enrolls`.`student_id` = `y78f2_students`.`student_id` 
INNER JOIN `y78f2_attendance` ON `y78f2_attendance`.`student_id` = `y78f2_students`.`student_id` 
WHERE `y78f2_enrolls`.`term` = 'Term 2 2016' 
AND `y78f2_enrolls`.`crn_class` = 'Math1R1' 
and `y78f2_attendance`.`thedate` = '2016-01-24'
ORDER BY thedate desc

此查询 returns 仅查询日期为“2016-01-24”的行。目前只有一行：http://i.imgur.com/jRTBqQ0.png

我需要显示 term = 'Term 2 2016' 和 crn_class` = 'Math1R1' 以及尚未设置日期的所有行。换句话说，我想显示 class 中的所有学生，如果尚未为这些学生设置日期，它将显示为空。这就是我想要的：http://i.imgur.com/jmsuSF5.png

所以总而言之，我需要显示满足子句的行以及日期为空或尚不存在的行。我该如何编写此查询？

Answer 1

尝试将与联接的 table 相关的条件从查询末尾移动到每个联接的 table 各自的 ON 子句。此外，如果您想要 return y78f2_attendance table 中尚无行的记录，则 table 应该 LEFT OUTER 加入，而不是 INNER加入。

SELECT `y78f2_students`.`firstname` , `y78f2_students`.`lastName`,
    `y78f2_students`.`student_id`,`y78f2_attendance`.`is_present`, 
    `y78f2_attendance`.`note`, `y78f2_attendance`.`thedate`  
FROM `y78f2_students`
INNER JOIN `y78f2_enrolls` ON
    `y78f2_enrolls`.`student_id` = `y78f2_students`.`student_id`
    AND `y78f2_enrolls`.`crn_class` = 'Math1R1'
LEFT OUTER JOIN `y78f2_attendance` ON
    `y78f2_attendance`.`student_id` = `y78f2_students`.`student_id`
    AND (`y78f2_attendance`.`thedate` IS NULL OR `y78f2_attendance`.`thedate` = '2016-01-24')
WHERE `y78f2_enrolls`.`term` = 'Term 2 2016' 
ORDER BY thedate desc

MySQL 如何显示也不匹配 where 子句的行

MySQL how to show rows that also does not match where clause

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