具有不同用户输入的多个对象 java

Question

所以我试图在我的主驱动程序 class 中创建的不同对象中获取多个用户输入，我似乎无法弄清楚如何做到这一点。网络上的其他教程只展示了如何针对一个对象执行此操作，但我有多个。

public class roulettedriver {

public static void main(String[] args) {

    Scanner keyin = new Scanner(System.in);

        // initializing the six players of the game

        Player player1 = new Player(0, 0, 0, 0, 0);
        Player player2 = new Player(0, 0, 0, 0, 0);
        Player player3 = new Player(0, 0, 0, 0, 0);
        Player player4 = new Player(0, 0, 0, 0, 0);
        Player player5 = new Player(0, 0, 0, 0, 0);
        Player player6 = new Player(0, 0, 0, 0, 0);

在我的另一个 class 播放器中

public class Player {

int number1;
int number2;
int number3;
int number4;
int number5;
// constructor for each player at the table
public Player(int number1, int number2, int number3, int number4, int number5) {

    this.number1 = number1;
    this.number2 = number2;
    this.number3 = number3;
    this.number4 = number4;
    this.number5 = number5;

所以我试图通过 keyin.nextInt() 让用户输入每个玩家的数字 1、数字 2、数字 3、数字 4、数字 5，但我不知道该怎么做！

Answer 1

您将看到在这种情况下使用的标准 'patterns' 之一是 'factory'。这本质上是专家 class，唯一的工作就是制作另一个 class 的对象。在您的情况下，'factory' 将是 PlayerFactory，它有一个方法可以采用 Scanner 并从中创建一个 Player。它可以有多种创建可用玩家的方法。下面是一些帮助您入门的示例代码：

class PlayerFactory {
    public Player makeFromScanner(Scanner scannerIn) {
        int number1 = scannerIn.nextInt();
        int number2 = scannerIn.nextInt();
        ...
        return new Player(number1, number2, ...);
    }

    public Player makeRandom() {
        Random rand = new Random();
        int number1 = rand.nextInt();
        ...
        return new Player(number1, number2, ...);
    }
}

然后您可以按如下方式使用它：

PlayerFactory factory = new PlayerFactory();
Player player1 = factory.makeFromScanner(scannerIn);
Player player2 = factory.makeRandom();

其他选项是使它成为 Player 构造函数之一：

class Player {
    public Player(Scanner scannerIn) {
        number1 = scannerIn.nextInt();
        number2 = scannerIn.nextInt();
        ...
    }
}

用作：

Player player1 = new Player(scannerIn);

或者您可以将构建方法设为 Player:

的静态方法

class Player {
    public static Player makeFromScanner(Scanner scannerIn) {
        ...
    }

    public static Player makeRandom() {
        ...
    }
}

然后用作：

Player player1 = Player.makeFromScanner(scannerIn);

Answer 2

你可以试试这个：

public static void main(String[] s) throws NoSuchFieldException, SecurityException{
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));   
    try   
    {   
        String numbers = null;
        while(true){
            System.out.println("Enter a five numbers (only numbers) or type kill, plis:");   
            numbers = br.readLine();//read a console value typed for user
            if(numbers!=null && numbers.equals("kill")){//verify to continue running or exit
                System.out.println("Exit");
                break;
            }
            int[] numbersToParam = new int[5]; //array for the five parameters to your Player object
            for(int i=0; i<numbers.length(); i++){
                numbersToParam[i] = Integer.parseInt(numbers.substring(i, i+1));//parse 5 values to array
            }
            //create a new playes with parameters
            new Player(numbersToParam[0],numbersToParam[1],numbersToParam[2],numbersToParam[3],numbersToParam[4]);
        }

    }   
    catch (IOException io)   
    {   
        System.err.println(io.toString()); 

    }



}

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