XML 验证不验证功能

Question

我想根据外部 XSD 描述验证 XML 文件。这是从我的 XSD

创建的 Schema 对象

       private static Schema xmlSchema; 
       try {
            SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
            String FEATURE= "";
           // forbid DOCTYPE
            FEATURE = "http://apache.org/xml/features/disallow-doctype-decl";
           factory.setFeature(FEATURE, true);
           xmlSchema = factory.newSchema(new File(XML_XSD_SCHEME));
        } catch (Exception e) {

        }

此外，我创建了 validateXMLSchema 静态方法，它负责验证 XML 个文件：

public static boolean validateXMLSchema(String xmlPath) {

    if (xmlSchema == null) {
        return false;
    }

    InputStream inputStream = null;
    try {
        URL xmlFileURL = new File(xmlPath).toURI().toURL();

        inputStream = xmlFileURL.openStream();
        SAXSource saxSource = new SAXSource(new InputSource(inputStream));

        Validator validator = xmlSchema.newValidator();

        String FEATURE ="";

        // disallow DOCTYPE
         FEATURE = "http://apache.org/xml/features/disallow-doctype-decl";
         validator.setFeature(FEATURE, true);

        //forbid external Entity 
        FEATURE ="http://xml.org/sax/features/external-general-entities";
        validator.setFeature(FEATURE, false);

        //forbid external parameters
        FEATURE ="http://xml.org/sax/features/external-parameter-entities";

        validator.setFeature(FEATURE, false);

        validator.validate(saxSource);

    } catch (Exception e) {
        return false;
    } finally {
        try {
            inputStream.close();
        } catch (IOException e) {
        }
    }
    return true;
}

问题是，即使我在 XML 文件 <!DOCTYPE foo [<!ELEMENT foo ANY ><!ENTITY...... 中添加了外部实体定义， validateXMLSchema 方法 returns true。谁能帮帮我？

Answer 1

我猜您希望将这些功能应用于读取 XML 文档的 SAX 解析器。尝试创建一个新的 XMLReader 并在将 SAXSource 传递给 Validator 之前显式配置它：

SAXParserFactory spf = SAXParserFactory.newInstance();
spf.setNamespaceAware(true);
XMLReader reader = spf.newSAXParser().getXMLReader();

String FEATURE ="";

// disallow DOCTYPE
FEATURE = "http://apache.org/xml/features/disallow-doctype-decl";
reader.setFeature(FEATURE, true);

//forbid external Entity 
FEATURE ="http://xml.org/sax/features/external-general-entities";
reader.setFeature(FEATURE, false);

//forbid external parameters
FEATURE ="http://xml.org/sax/features/external-parameter-entities";
reader.setFeature(FEATURE, false);

SAXSource saxSource = new SAXSource(reader, new InputSource(inputStream));

Validator validator = xmlSchema.newValidator();

validator.validate(saxSource);

XML 验证不验证功能

XML Validation does not validate features

java

xml

validation

xsd

jaxp