如何按月获得总工作时间组？

Question

我需要计算一些工人在 2014 年花费的时间，并且需要按月分组（和求和）。每行应该是这样的

Worker 1 | Tot Time HH:MM:SS (Jan) | Tot Time HH:MM:SS (Feb) | etc... | Tot Time Year
Worker 2 | Tot Time HH:MM:SS (Jan) | Tot Time HH:MM:SS (Feb) | etc... | Tot Time Year
Worker 3 | Tot Time HH:MM:SS (Jan) | Tot Time HH:MM:SS (Feb) | etc... | Tot Time Year

我的MySQL数据库是这样的：

id_worker (int, primary key), in_datetime (DATETIME), out_datetime (DATETIME)

有人可以帮助我吗？我只计算了一年的总时间。

非常感谢！

Answer 1

试试这个：

SELECT id_worker, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 1 THEN workingTime ELSE 0 END)) AS JanWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 2 THEN workingTime ELSE 0 END)) AS FebWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 3 THEN workingTime ELSE 0 END)) AS MarWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 4 THEN workingTime ELSE 0 END)) AS AprWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 5 THEN workingTime ELSE 0 END)) AS MayWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 6 THEN workingTime ELSE 0 END)) AS JunWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 7 THEN workingTime ELSE 0 END)) AS JulWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 8 THEN workingTime ELSE 0 END)) AS AugWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 9 THEN workingTime ELSE 0 END)) AS SepWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 10 THEN workingTime ELSE 0 END)) AS OctWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 11 THEN workingTime ELSE 0 END)) AS NovWorkingTime, 
       SEC_TO_TIME(SUM(CASE WHEN MonthNo = 12 THEN workingTime ELSE 0 END)) AS DecWorkingTime 
FROM (SELECT id_worker, MONTH(in_datetime) MonthNo, 
             SUM(TIMESTAMPDIFF(SECOND, in_datetime, out_datetime)) AS workingTime
      FROM tableA 
      WHERE YEAR(in_datetime) = 2014
      GROUP BY id_worker, MonthNo
    ) AS A
GROUP BY id_worker

如何按月获得总工作时间组？

How to get total working time group by month?

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