为 ImageView src 分配可绘制名称

Question

为简单起见：我从 JSON 文件中获得了可绘制对象的名称，现在它位于一个变量中，我如何才能将正确的可绘制对象分配给名称为 ImageView 的 String?我们可以假设具有该名称的可绘制对象始终存在。

String image_name = "image1.png";

ImageView imageView = (ImageView)view.findViewById(R.id.myImageView);
imageView.setImageResource(image_name); // FAIL since is expecting the drawable and not the name as a String.

Answer 1

imageView.setImageResource(getDrawableFromName(context,"image1.png""));

public static int getDrawableFromName(Context context, String drawableName) {
    return context.getResources().getIdentifier(drawableName, "drawable",
            context.getPackageName());
}

Answer 2

通过 String source 并获取 drawable。

private Drawable getImage(String source){
        File imgFile = new File(source);//Absolute path
        Bitmap myBitmap = null;
        Drawable drawable = null;
        if(imgFile.exists()) {
            myBitmap= BitmapFactory.decodeFile(imgFile.getAbsolutePath());
            drawable = new BitmapDrawable(mContext.getResources(),myBitmap);
        }
        return  drawable;
    }

为 ImageView src 分配可绘制名称

Assign ImageView src with drawable name

java

android

android-drawable