退出蚂蚁目标而不失败构建

Question

我正在寻找一种方法来退出目标并继续运行蚂蚁代码而不退出整个过程。类似下面的内容，但我收到错误。

<target name="foo">
<some-task/>
<another-task/>

<condition property="should.exit">
(condition check here....)
</condition>

<exit if="should.exit" message="some message"/>

(skipped tasks if "should.exit" is true)

</target>

我得到的错误：

Problem: failed to create task or type exit   
[sshexec]      [echo] Cause: The name is undefined.   
[sshexec]    
[sshexec]      [echo] Action: Check the spelling.   
[sshexec]    
[sshexec]      [echo] Action: Check that any custom tasks/types have been declared.   
[sshexec]      [echo] Action: Check that any <presetdef>/<macrodef> declarations have taken place.   
[sshexec]    
[sshexec]      [echo]    [sshexec]    
[sshexec]      [echo]                    ERROR Error error

Answer 1

<target name="foo">
<some-task/>
<another-task/>

<condition property="should.exit">
(condition check here....)
</condition>

<fail message="failing">
    <condition>
        <equals arg1="${should.exit}" arg2="true"/>
    </condition>
</fail>

(skipped tasks if "should.exit" is true)

</target>

退出蚂蚁目标而不失败构建

Exiting ant target without failing build

ant

exit