如何从 return 数组的模型中获取 id 并将其作为参数传递给控制器函数

Question

当我将 id 从模型传递到控制器时，它说数组无法转换为字符串。但我的问题是我想要所有 post 并根据 post 获取评论。 . 我做不到

                       public function getPosts()
                           {
                                   $sql="SELECT d.*,u.username,u.image FROM tbl_discussion as d join user as u
                                   on d.user_id=u.user_id order by date desc";
                                   $query=$this->db->query($sql);
                                   return $query->result();
                           }

                           public function getReplies($post_id=NULL)
                           {

                                   //$sql="SELECT r.*,u.username FROM tbl_replies as r 
                                   //join user as u on r.user_id=u.user_id 

                                   //join tbl_discussion as d on d.discussion_id=r.discussion_id  where r.discussion_id='$post_id' order by date desc";
                                 $sql="SELECT r.*,u.username FROM tbl_replies as r 
    join user as u on r.user_id=u.user_id 
    join tbl_discussion as d on d.discussion_id=r.discussion_id  where r.discussion_id='$post_id'order by date desc";


                              $query=$this->db->query($sql);
                                     if($query->num_rows()>0){
                                           foreach ($query->result() as $data){
                                               $row[]=$data;
                                           }
                                           return $row;
                                       }
                           }
public function getId(){
        $sql="select discussion_id from tbl_discussion";
        $query=  $this->db->query($sql);
        return $query->result_array();
    }

在控制器中

 public function index()
{



    $id=$this->kishan->getid();
    $data1['agros']=$this->kishan->getNoticAgros();
    $data2['farms']=$this->kishan->getNoticFarmers();
    $data3['members']=$this->kishan->getNoticMembers();
    $data4['ngoss']=$this->kishan->getNoticNgos();
    $data5['followups']=$this->kishan->getNoticFollowUp();
    $data6['all']=$this->kishan->getNoticAll();
    $data7['posts']=$this->kishan->getPosts();
    $data8['replies']=$this->kishan->getReplies($id);
    $data9['page']='discussion';
    $this->load->view('admin/home',array_merge($data1,$data2,$data3,$data4,$data5,$data6,$data7,$data8,$data9));
}

Answer 1

按如下方式编写您的查询：-

$sql="SELECT r.*,u.*,d.* from tbl_replies as r
      LEFT JOIN user as u ON r.user_id=u.user_id 
      LEFT JOIN tbl_discussion as d ON r.discussion_id = d.discussion_id";

希望对您有所帮助:)

Answer 2

在评论中添加 WHERE 语句。

$sql="SELECT * from tbl_replies as r
    LEFT JOIN user as u ON r.user_id=u.user_id 
    LEFT JOIN tbl_discussion as d ON r.discussion_id = d.discussion_id
    WHERE r.discussion_id='" . $post_id . "'";

我不确定我是否完全理解您的问题，但让我们假设 $aPostIds 是一个包含所需 ID 的数组：

// Escape all values
$aPostIdsEscaped=array()
foreach($aPostIds as $postId) 
    $aPostIdsEscaped[]=mysqli_real_escape_string($dblink, $postId);

// Turn array into IN clause
$sql="SELECT * from tbl_replies as r
    LEFT JOIN user as u ON r.user_id=u.user_id 
    LEFT JOIN tbl_discussion as d ON r.discussion_id = d.discussion_id
    WHERE r.discussion_id IN ('" . implode("', '", $aPostIdsEscaped) . "'";

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