排序和匹配 Python 列表

Question

我最近问了一个类似的问题，但需要更深入一点。

本质上，我正在读取文件目录并将所有内容附加到名为 filelistname

的列表中

我正在尝试按 diskcount (-#disk-) 对这个列表进行排序，运行一个针对该排序列表的函数。

感谢您的帮助。

这是一个例子-

 In []: filelistname
Out []: ['C:\Test3\ARRAY05-2NODE-RAID1-12disk-128k-0-segmented.xlsx'
         'C:\Test1\ARRAY05-2NODE-RAID1-17disk-128k-0-segmented.xlsx',
         'C:\Test4\ARRAY05-2NODE-RAID1-25disk-128k-0-segmented.xlsx',
         'C:\Test2\ARRAY05-2NODE-RAID1-18disk-128k-0-segmented.xlsx',
         'C:\Test1\ARRAY05-2NODE-RAID1-12disk-32k-0-segmented.xlsx',
         'C:\Test6\ARRAY05-2NODE-RAID1-25disk-32k-0-segmented.xlsx',
         'C:\Test2\ARRAY05-2NODE-RAID1-12disk-64k-0-segmented.xlsx',
         'C:\Test5\ARRAY05-2NODE-RAID1-12disk-64k-100-segmented.xlsx']

它的输出看起来像这样。

一组

  C:\Test3\ARRAY05-2NODE-RAID1-12disk-128k-0-segmented.xlsx
  C:\Test1\ARRAY05-2NODE-RAID1-17disk-128k-0-segmented.xlsx
  C:\Test2\ARRAY05-2NODE-RAID1-18disk-128k-0-segmented.xlsx

另一个组

  C:\Test4\ARRAY05-4NODE-RAID1-25disk-128k-0-segmented.xlsx

另一组

  C:\Test1\ARRAY05-2NODE-RAID1-12disk-32k-0-segmented.xlsx
  C:\Test6\ARRAY05-2NODE-RAID1-25disk-32k-0-segmented.xlsx

另一组

  C:\Test2\ARRAY05-2NODE-RAID1-12disk-64k-0-segmented.xlsx

另一组

  C:\Test5\ARRAY05-2NODE-RAID1-12disk-64k-100-segmented.xlsx

我目前正在玩这个，但无法识别正确的密钥。

import os
from itertools import groupby
from collections import defaultdict

key_fn = lambda s: s.rsplit('-',4)[0]

filelistname = sorted(filelistname, key=key_fn)
print(key)

for key, grouped_file_names in groupby(filelistname, key=key_fn):
    print('\n'.join(list(grouped_file_names)))
    print("")

Answer 1

您似乎按 d+k-d+ 分组，因此拆分基本名称并将其用作键：

from collections import defaultdict
d = defaultdict(list)

for sub in l:
    spl = sub.rsplit("-", 3)
    k = spl[-3],spl[-2]
    d[k].append(sub)

输出：

from pprint import pprint as pp

pp(d)

{ ('128k', '0'): [ 'C:\Test3\ARRAY05-2NODE-RAID1-12disk-128k-0-segmented.xlsxC:\Test1\ARRAY05-2NODE-RAID1-17disk-128k-0-segmented.xlsx',
                   'C:\Test4\ARRAY05-2NODE-RAID1-25disk-128k-0-segmented.xlsx',
                   'C:\Test2\ARRAY05-2NODE-RAID1-18disk-128k-0-segmented.xlsx'],
  ('32k', '0'): [ 'C:\Test1\ARRAY05-2NODE-RAID1-12disk-32k-0-segmented.xlsx',
                  'C:\Test6\ARRAY05-2NODE-RAID1-25disk-32k-0-segmented.xlsx'],
  ('64k', '0'): ['C:\Test2\ARRAY05-2NODE-RAID1-12disk-64k-0-segmented.xlsx'],
  ('64k', '100'): [ 'C:\Test5\ARRAY05-2NODE-RAID1-12disk-64k-100-segmented.xlsx']}

如果你想要除磁盘部分以外的所有部分：

from collections import defaultdict
from os import path
from ntpath import basename
d = defaultdict(list)

for sub in l:
    spl = basename(sub).rsplit("-", 5)
    k = spl[0]+"-" + "-".join(spl[3:5])
    d[k].append(sub)

输出：

{'ARRAY05-2NODE-128k-0': ['C:\Test3\ARRAY05-2NODE-RAID1-12disk-128k-0-segmented.xlsx',
                          'C:\Test1\ARRAY05-2NODE-RAID1-17disk-128k-0-segmented.xlsx',
                          'C:\Test4\ARRAY05-2NODE-RAID1-25disk-128k-0-segmented.xlsx',
                          'C:\Test2\ARRAY05-2NODE-RAID1-18disk-128k-0-segmented.xlsx'],
 'ARRAY05-2NODE-32k-0': ['C:\Test1\ARRAY05-2NODE-RAID1-12disk-32k-0-segmented.xlsx',
                         'C:\Test6\ARRAY05-2NODE-RAID1-25disk-32k-0-segmented.xlsx'],
 'ARRAY05-2NODE-64k-0': ['C:\Test2\ARRAY05-2NODE-RAID1-12disk-64k-0-segmented.xlsx'],
 'ARRAY05-2NODE-64k-100': ['C:\Test5\ARRAY05-2NODE-RAID1-12disk-64k-100-segmented.xlsx']}

排序和匹配 Python 列表

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