用不同的颜色给树视图的节点上色
Color a node of treeview with different color
我有一个带有一些节点的 treeview
。在某些情况下,我想为每个节点及其子节点着色不同的颜色。我写了一个给节点及其子节点上色的函数。
任何人都可以让我知道我是否有可能将 Color.Green
作为变量,这样我就不会为每种颜色编写整个函数?我的意思是作为函数中的输入参数。
函数如下:
public void ColorChild(TreeNode nodes, int indx)
{
foreach (TreeNode node_tmp in nodes.Nodes[indx].Nodes)
{
System.Drawing.Color = Green;
node_tmp.ForeColor = color;
foreach (TreeNode node_tmp2 in node_tmp.Nodes)
{
node_tmp2.ForeColor = Color.Green;
foreach (TreeNode node_tmp3 in node_tmp2.Nodes)
{
node_tmp3.ForeColor = Color.Green;
foreach (TreeNode node_tmp4 in node_tmp3.Nodes)
{
node_tmp4.ForeColor = Color.Green;
foreach (TreeNode node_tmp5 in node_tmp4.Nodes)
{
node_tmp5.ForeColor = Color.Green;
}
}
}
}
}
}
您可以使用递归遍历所有节点。
类似于:
void ColorNode(TreeNodeCollection nodes, System.Drawing.Color Color)
{
foreach (TreeNode child in nodes)
{
child.ForeColor= Color;
if(child.Nodes != null && child.Nodes.Count>0)
ColorNode(child.Nodes, Color);
}
}
然后用你的方法调用它:
public void ColorChild(TreeNode nodes, int indx)
{
ColorNode(nodes.Nodes, Color.Green);
}
好吧,如果您想将颜色作为函数的参数,没有什么能阻止您。
public void ColorChild(TreeNode nodes, int indx, Color color)
{
foreach (TreeNode node_tmp in nodes.Nodes[indx].Nodes)
{
node_tmp.ForeColor = color;
foreach (TreeNode node_tmp2 in node_tmp.Nodes)
{
node_tmp2.ForeColor = color;
foreach (TreeNode node_tmp3 in node_tmp2.Nodes)
{
node_tmp3.ForeColor = color;
foreach (TreeNode node_tmp4 in node_tmp3.Nodes)
{
node_tmp4.ForeColor = color;
foreach (TreeNode node_tmp5 in node_tmp4.Nodes)
{
node_tmp5.ForeColor = color;
}
}
}
}
}
}
那就这样称呼吧
ColorChild(nodes, indx, Color.Green);
如果树很大,您的解决方案会非常慢。只需在绘制节点时按需为节点着色即可。为此,您需要设置绘图模式:
treeView1.DrawMode = TreeViewDrawMode.OwnerDrawText;
然后在要绘制节点时,按需询问其颜色:
private void tree_DrawNode(object sender, DrawTreeNodeEventArgs e)
{
TreeNodeStates state = e.State;
Font font = e.Node.NodeFont ?? e.Node.TreeView.Font;
Color foreColor;
Color backColor;
// node is selected
// if you want to see the color of a selected node, too,
// you can use inverted fore/back colors instead of system selection colors
if ((state & TreeNodeStates.Selected) == TreeNodeStates.Selected)
{
bool isFocused = (state & TreeNodeStates.Focused) == TreeNodeStates.Focused;
backColor = SystemColors.Highlight;
foreColor = isFocused ? SystemColors.HighlightText : SystemColors.InactiveCaptionText;
e.Graphics.FillRectangle(SystemBrushes.Highlight, e.Bounds);
if (isFocused)
ControlPaint.DrawFocusRectangle(e.Graphics, e.Bounds, foreColor, backColor);
TextRenderer.DrawText(e.Graphics, e.Node.Text, font, e.Bounds, foreColor, TextFormatFlags.GlyphOverhangPadding | TextFormatFlags.SingleLine | TextFormatFlags.EndEllipsis | TextFormatFlags.NoPrefix);
}
// node is not selected
else
{
backColor = GetBackColor(e.Node); // GetBackColor: return some color by condition
foreColor = GetForeColor(e.Node); // GetForeColor: return some color by condition
using (Brush background = new SolidBrush(backColor))
{
e.Graphics.FillRectangle(background, e.Bounds);
TextRenderer.DrawText(e.Graphics, e.Node.Text, font, e.Bounds, foreColor, TextFormatFlags.GlyphOverhangPadding | TextFormatFlags.SingleLine | TextFormatFlags.EndEllipsis);
}
}
}
如果条件发生变化,只需使树无效:
treeView1.Invalidate(); // this will re-draw the visible nodes
我有一个带有一些节点的 treeview
。在某些情况下,我想为每个节点及其子节点着色不同的颜色。我写了一个给节点及其子节点上色的函数。
任何人都可以让我知道我是否有可能将 Color.Green
作为变量,这样我就不会为每种颜色编写整个函数?我的意思是作为函数中的输入参数。
函数如下:
public void ColorChild(TreeNode nodes, int indx)
{
foreach (TreeNode node_tmp in nodes.Nodes[indx].Nodes)
{
System.Drawing.Color = Green;
node_tmp.ForeColor = color;
foreach (TreeNode node_tmp2 in node_tmp.Nodes)
{
node_tmp2.ForeColor = Color.Green;
foreach (TreeNode node_tmp3 in node_tmp2.Nodes)
{
node_tmp3.ForeColor = Color.Green;
foreach (TreeNode node_tmp4 in node_tmp3.Nodes)
{
node_tmp4.ForeColor = Color.Green;
foreach (TreeNode node_tmp5 in node_tmp4.Nodes)
{
node_tmp5.ForeColor = Color.Green;
}
}
}
}
}
}
您可以使用递归遍历所有节点。
类似于:
void ColorNode(TreeNodeCollection nodes, System.Drawing.Color Color)
{
foreach (TreeNode child in nodes)
{
child.ForeColor= Color;
if(child.Nodes != null && child.Nodes.Count>0)
ColorNode(child.Nodes, Color);
}
}
然后用你的方法调用它:
public void ColorChild(TreeNode nodes, int indx)
{
ColorNode(nodes.Nodes, Color.Green);
}
好吧,如果您想将颜色作为函数的参数,没有什么能阻止您。
public void ColorChild(TreeNode nodes, int indx, Color color)
{
foreach (TreeNode node_tmp in nodes.Nodes[indx].Nodes)
{
node_tmp.ForeColor = color;
foreach (TreeNode node_tmp2 in node_tmp.Nodes)
{
node_tmp2.ForeColor = color;
foreach (TreeNode node_tmp3 in node_tmp2.Nodes)
{
node_tmp3.ForeColor = color;
foreach (TreeNode node_tmp4 in node_tmp3.Nodes)
{
node_tmp4.ForeColor = color;
foreach (TreeNode node_tmp5 in node_tmp4.Nodes)
{
node_tmp5.ForeColor = color;
}
}
}
}
}
}
那就这样称呼吧
ColorChild(nodes, indx, Color.Green);
如果树很大,您的解决方案会非常慢。只需在绘制节点时按需为节点着色即可。为此,您需要设置绘图模式:
treeView1.DrawMode = TreeViewDrawMode.OwnerDrawText;
然后在要绘制节点时,按需询问其颜色:
private void tree_DrawNode(object sender, DrawTreeNodeEventArgs e)
{
TreeNodeStates state = e.State;
Font font = e.Node.NodeFont ?? e.Node.TreeView.Font;
Color foreColor;
Color backColor;
// node is selected
// if you want to see the color of a selected node, too,
// you can use inverted fore/back colors instead of system selection colors
if ((state & TreeNodeStates.Selected) == TreeNodeStates.Selected)
{
bool isFocused = (state & TreeNodeStates.Focused) == TreeNodeStates.Focused;
backColor = SystemColors.Highlight;
foreColor = isFocused ? SystemColors.HighlightText : SystemColors.InactiveCaptionText;
e.Graphics.FillRectangle(SystemBrushes.Highlight, e.Bounds);
if (isFocused)
ControlPaint.DrawFocusRectangle(e.Graphics, e.Bounds, foreColor, backColor);
TextRenderer.DrawText(e.Graphics, e.Node.Text, font, e.Bounds, foreColor, TextFormatFlags.GlyphOverhangPadding | TextFormatFlags.SingleLine | TextFormatFlags.EndEllipsis | TextFormatFlags.NoPrefix);
}
// node is not selected
else
{
backColor = GetBackColor(e.Node); // GetBackColor: return some color by condition
foreColor = GetForeColor(e.Node); // GetForeColor: return some color by condition
using (Brush background = new SolidBrush(backColor))
{
e.Graphics.FillRectangle(background, e.Bounds);
TextRenderer.DrawText(e.Graphics, e.Node.Text, font, e.Bounds, foreColor, TextFormatFlags.GlyphOverhangPadding | TextFormatFlags.SingleLine | TextFormatFlags.EndEllipsis);
}
}
}
如果条件发生变化,只需使树无效:
treeView1.Invalidate(); // this will re-draw the visible nodes