获取数组查询的最大值mysql,php

Get the highest value of array query mysql, php

非常感谢这里的其他人,我现在得到了这个查询。它工作正常,但我只需要获得 post_id (how_many) 的最高值。似乎无法在其上设置 MAX(count(*)) 。那么我该如何更改它以仅获得每个 ID 的最高计数呢?我只需要计数 == 最高的每个 id 的值。我怎么能这样做?感谢您的帮助。

$test = $wpdb->get_results('select 
    posts_id, value,count(*) as how_many
From wp_mrp_rating_item_entry_value
group by
    posts_id, value
order by count(*) desc');
echo '<pre>';
print_r($test);
echo '</pre>';

我需要像 order by MAX((count(*)) or MAX((count(how_many))

我已经读过这篇文章,但我不知道如何将其用于我的目的Filtering log file using COUNT, GROUP BY, ORDER BY MAX

这是我现在得到的输出示例。所以数字 1 不应出现,因为数字 [0] 已被投票 2 次。 (how_many)。我只需要输出中的每个 id 1x。没有 ID 应该出现两次或更多次。因为只需要最高计数。谢谢,抱歉英语不好。

Array
(
    [0] => stdClass Object
        (
            [posts_id] => 336
            [value] => 8
            [how_many] => 2
        )

    [1] => stdClass Object
        (
            [posts_id] => 336
            [value] => 7
            [how_many] => 1
        )

    [2] => stdClass Object
        (
            [posts_id] => 380
            [value] => 5
            [how_many] => 1
        )

    [3] => stdClass Object
        (
            [posts_id] => 378
            [value] => 7
            [how_many] => 1
        )

    [4] => stdClass Object
        (
            [posts_id] => 329
            [value] => 2
            [how_many] => 1
        )

    [5] => stdClass Object
        (
            [posts_id] => 327
            [value] => 3
            [how_many] => 1
        )

)

您可以在 HAVING 子句中根据与最大计数的子查询的匹配来过滤结果组:

SELECT   posts_id, value, COUNT(*) AS how_many
FROM     wp_mrp_rating_item_entry_value t1
GROUP BY posts_id, value
HAVING   how_many = (
           SELECT   COUNT(*)
           FROM     wp_mrp_rating_item_entry_value t2
           WHERE    t2.posts_id = t1.posts_id
           GROUP BY t2.value
           ORDER BY COUNT(*) DESC
           LIMIT    1
         )