Java 基于用户输入的嵌套 for 循环的贷款计算器
Java Loan Calculator nested for loop based on user input
任务是根据用户输入的最小和最大贷款支付年限、贷款金额、最小和最大百分比利率以及用户给出的增量值以及利率和年数来创建一个贷款计算器.
所需的输出应如下所示:
本金:$275000.0
偿还年限:10
每月利息
费率支付
6.25 3087.7
6.75 3157.66
7.25 3228.53
本金:$275000.0
还款年限:15
每月利息
费率支付
6.25 2357.91
6.75 2433.5
7.25 2510.37
本金:$275000.0
偿还年限:20
每月利息
费率支付
6.25 2010.05
6.75 2091.0
7.25 2173.53
请帮我修正错误。谢谢!
public static void main(String[] args){
Scanner console = new Scanner (System.in);
System.out.println("This program computes monthly " + "mortgage payments.");
System.out.print("Enter the loan amount: ");
double loan = console.nextDouble();
System.out.print("Enter the starting number of years to repay the loan: ");
int startingYears = console.nextInt();
System.out.print("Enter the ending number of years to repay the loan: ");
int endingYears = console.nextInt();
System.out.print("Enter the years increment between tables: ");
int incrementYears = console.nextInt();
System.out.print("Enter the starting loan yearly interest rate, %: ");
double startingRate = console.nextDouble();
System.out.print("Enter the ending loan yearly interest rate, %: ");
double endingRate = console.nextDouble();
System.out.print("Enter the increment interest rate, %: ");
double incrementRate = console.nextDouble();
System.out.println();
System.out.println("Principle: $" + (double) loan);
System.out.printf("Years to repay: %d\n", startingYears);
System.out.println("-------- -------");
double payment;
System.out.println("Rate\tPayment");
for (int j = startingYears; j <= endingYears; incrementYears++) {
for (double i = startingRate; i <= endingRate; incrementRate++){
int n = 12 * startingYears;
double c = startingRate / 12.0 / 100.0;
payment = loan * c * Math.pow(1 + c, n) / (Math.pow(1 +c, n) - 1);
System.out.println(i + " " + payment);
// System.out.println(round2(startingRate) + "\t" + round2(payment));
startingYears += incrementYears;
}
}
}
}
for (int j = startingYears; j <= endingYears; incrementYears++) {
for (double i = startingRate; i <= endingRate; incrementRate++) {
您永远不会增加计数器的值,即 i
和 j
,因此 i
和 j
的值将始终等于初始化值这些循环将 运行 无限次。
增加两个计数器以达到终止条件,即分别为 j <= endingYears
和 i <= endingRate
。
这是代码片段:
System.out.println("Principle: $" + (double) loan);
for (int j = startingYears; j <= endingYears; j+=incrementYears) {
System.out.printf("Years to repay: %d\n", j);
System.out.println("-------- -------");
System.out.println("Rate\tPayment");
for (double i = startingRate; i <= endingRate; i+=incrementRate){
int n = 12 * j;
double c = i / 12.0 / 100.0;
double payment = loan * c * Math.pow(1 + c, n) / (Math.pow(1 + c, n) - 1);
System.out.println(i + "\t" + payment);
}
System.out.println();
}
任务是根据用户输入的最小和最大贷款支付年限、贷款金额、最小和最大百分比利率以及用户给出的增量值以及利率和年数来创建一个贷款计算器. 所需的输出应如下所示:
本金:$275000.0 偿还年限:10 每月利息 费率支付
6.25 3087.7 6.75 3157.66 7.25 3228.53
本金:$275000.0 还款年限:15 每月利息 费率支付
6.25 2357.91 6.75 2433.5 7.25 2510.37
本金:$275000.0 偿还年限:20 每月利息 费率支付
6.25 2010.05 6.75 2091.0 7.25 2173.53
请帮我修正错误。谢谢!
public static void main(String[] args){
Scanner console = new Scanner (System.in);
System.out.println("This program computes monthly " + "mortgage payments.");
System.out.print("Enter the loan amount: ");
double loan = console.nextDouble();
System.out.print("Enter the starting number of years to repay the loan: ");
int startingYears = console.nextInt();
System.out.print("Enter the ending number of years to repay the loan: ");
int endingYears = console.nextInt();
System.out.print("Enter the years increment between tables: ");
int incrementYears = console.nextInt();
System.out.print("Enter the starting loan yearly interest rate, %: ");
double startingRate = console.nextDouble();
System.out.print("Enter the ending loan yearly interest rate, %: ");
double endingRate = console.nextDouble();
System.out.print("Enter the increment interest rate, %: ");
double incrementRate = console.nextDouble();
System.out.println();
System.out.println("Principle: $" + (double) loan);
System.out.printf("Years to repay: %d\n", startingYears);
System.out.println("-------- -------");
double payment;
System.out.println("Rate\tPayment");
for (int j = startingYears; j <= endingYears; incrementYears++) {
for (double i = startingRate; i <= endingRate; incrementRate++){
int n = 12 * startingYears;
double c = startingRate / 12.0 / 100.0;
payment = loan * c * Math.pow(1 + c, n) / (Math.pow(1 +c, n) - 1);
System.out.println(i + " " + payment);
// System.out.println(round2(startingRate) + "\t" + round2(payment));
startingYears += incrementYears;
}
}
}
}
for (int j = startingYears; j <= endingYears; incrementYears++) {
for (double i = startingRate; i <= endingRate; incrementRate++) {
您永远不会增加计数器的值,即 i
和 j
,因此 i
和 j
的值将始终等于初始化值这些循环将 运行 无限次。
增加两个计数器以达到终止条件,即分别为 j <= endingYears
和 i <= endingRate
。
这是代码片段:
System.out.println("Principle: $" + (double) loan);
for (int j = startingYears; j <= endingYears; j+=incrementYears) {
System.out.printf("Years to repay: %d\n", j);
System.out.println("-------- -------");
System.out.println("Rate\tPayment");
for (double i = startingRate; i <= endingRate; i+=incrementRate){
int n = 12 * j;
double c = i / 12.0 / 100.0;
double payment = loan * c * Math.pow(1 + c, n) / (Math.pow(1 + c, n) - 1);
System.out.println(i + "\t" + payment);
}
System.out.println();
}