在 python 中连接一个字符串

Question

这是我的文件

2015125_0r89_PEO.txt 
2015125_0r89_PED.txt
2015125_0r89_PEN.txt

2015126_0r89_PEO.txt 
2015126_0r89_PED.txt
2015126_0r89_PEN.txt

2015127_0r89_PEO.txt 
2015127_0r89_PED.txt
2015127_0r89_PEN.txt

我想改成这样：

US.CAR.PEO.D.2015.125.txt
US.CAR.PED.D.2015.125.txt
US.CAR.PEN.D.2015.125.txt

US.CAR.PEO.D.2015.126.txt
US.CAR.PED.D.2015.126.txt
US.CAR.PEN.D.2015.126.txt

US.CAR.PEO.D.2015.127.txt
US.CAR.PED.D.2015.127.txt
US.CAR.PEN.D.2015.127.txt

到目前为止，这是我的代码，

import os

paths = (os.path.join(root, filename)
        for root, _, filenames in os.walk('C:\data\MAX\') #location files
        for filename in filenames)

for path in paths:
    a = path.split("_") 
    b = a[2].split(".") 
    c = "US.CAR."+ b[0] + ".D." + a[0]
    print c

当我运行脚本时它不会出错，但不会更改文件的名称 .txt 这是它应该做的

有什么帮助吗？

Answer 1

首先获取路径然后对其进行操作的方式会得到不好的结果，在这种情况下最好先获取文件名，对其进行更改，然后再更改文件名本身，像这样

for root,_,filenames in os.walk('C:\data\MAX\'):
    for name in filenames:
        print "original:", name
        a = name.split("_")
        b = a[2].split(".")
        new = "US.CAR.{}.D.{}.{}".format(b[0],a[0],b[1]) #don't forget the file extention 
        print "new",new
        os.rename( os.path.join(root,name), os.path.join(root,new) )

字符串拼接效率较低，最好的方法是使用字符串formating.

在 python 中连接一个字符串

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python-2.7