将 JSONObject 转换为 Java 对象
Converting JSONObject to Java Object
我对服务进行了休息调用,并将响应存储在 JSONObject
中。但是,我试图将其转换为 class 对象并出现错误。这是我的代码:
RestOperations operations = /*initalize*/;
String body = /*build request body*/;
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
UserIdentifier userIdentifier = (UserIdentifier) jsonResponse.get("userIdentifier");
响应如下所示:
{
"userIdentifier": {
"uid": "ee63a52cda7bf411dd8603ac196951aa77",
"code": "63a5297e7bf411dd8603ac196951aa77",
"retailId": "860658787",
"pointOfEntry": "RETAIL"
},
"resultCode": true
}
下面是 UserIdentifier
class 的样子:
public class UserIdentifier {
private String uid;
private String code;
private String retailId;
public UserIdentifier() {
}
public UserIdentifier(String uid, String code, String retailId) {
this.uid = uid;
this.code = code;
this.retailId = retailId;
}
public String getuid() {
return uid;
}
public void setuid(String uid) {
this.uid = uid;
}
public String getcode() {
return code;
}
public void setcode(String code) {
this.code = code;
}
public String getretailId() {
return retailId;
}
public void setretailId(String retailId) {
this.retailId = retailId;
}
}
但是我得到错误:
java.lang.ClassCastException: org.json.JSONObject cannot be cast to app.identity.UserIdentifier
我做错了什么?
编辑 1: 下面是尝试使用 gson 的答案:
Gson gson = new GsonBuilder().create();
String body = /*build request body*/;
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
UserIdentifier userIdentifier = gson.fromJson(jsonResponse.getString("userIdentifier"), UserIdentifier.class);
但是我得到错误:
org.json.JSONException: JSONObject["userIdentifier"] not a string.
at org.json.JSONObject.getString(JSONObject.java:658) ~[json-20140107.jar:na]
使用 Gson 库
Gson gson=new GsonBuilder().create();
UserIdentifier userIdentifier=gson.fromJson(jsonString,UserIdentifier.class);
在你的例子中,jsonString 是 resourceResponse
事情是你不能像这样在 get 方法中转换 return 的对象,一个解决方案可能是这样,使用 GSON
库:
RestOperations operations = /*initalize*/;
String body = /*build request body*/;
Gson gson = new Gson();
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
String jsonUserIdentifier = jsonResponse.getString("userIdentifier");
UserIdentifier userIdentifier = gson.fromJson(jsonUserIdentifier , UserIdentifier.class);
您可能需要使用 gson
class Name{
String resultCode;
UserIdentifier useridentifier;
//getters
}
Gson gson=new Gson();
Name name=gson.fromJson(jsonString,Name.class);
找出问题所在。需要提取 jsonobject 而不是获取字符串。这是解决问题的行:
UserIdentifier userIdentifier = gson.fromJson(jsonResponse.getJSONObject("userIdentifier").toString(), UserIdentifier.class);
我对服务进行了休息调用,并将响应存储在 JSONObject
中。但是,我试图将其转换为 class 对象并出现错误。这是我的代码:
RestOperations operations = /*initalize*/;
String body = /*build request body*/;
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
UserIdentifier userIdentifier = (UserIdentifier) jsonResponse.get("userIdentifier");
响应如下所示:
{
"userIdentifier": {
"uid": "ee63a52cda7bf411dd8603ac196951aa77",
"code": "63a5297e7bf411dd8603ac196951aa77",
"retailId": "860658787",
"pointOfEntry": "RETAIL"
},
"resultCode": true
}
下面是 UserIdentifier
class 的样子:
public class UserIdentifier {
private String uid;
private String code;
private String retailId;
public UserIdentifier() {
}
public UserIdentifier(String uid, String code, String retailId) {
this.uid = uid;
this.code = code;
this.retailId = retailId;
}
public String getuid() {
return uid;
}
public void setuid(String uid) {
this.uid = uid;
}
public String getcode() {
return code;
}
public void setcode(String code) {
this.code = code;
}
public String getretailId() {
return retailId;
}
public void setretailId(String retailId) {
this.retailId = retailId;
}
}
但是我得到错误:
java.lang.ClassCastException: org.json.JSONObject cannot be cast to app.identity.UserIdentifier
我做错了什么?
编辑 1: 下面是尝试使用 gson 的答案:
Gson gson = new GsonBuilder().create();
String body = /*build request body*/;
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
UserIdentifier userIdentifier = gson.fromJson(jsonResponse.getString("userIdentifier"), UserIdentifier.class);
但是我得到错误:
org.json.JSONException: JSONObject["userIdentifier"] not a string.
at org.json.JSONObject.getString(JSONObject.java:658) ~[json-20140107.jar:na]
使用 Gson 库
Gson gson=new GsonBuilder().create();
UserIdentifier userIdentifier=gson.fromJson(jsonString,UserIdentifier.class);
在你的例子中,jsonString 是 resourceResponse
事情是你不能像这样在 get 方法中转换 return 的对象,一个解决方案可能是这样,使用 GSON
库:
RestOperations operations = /*initalize*/;
String body = /*build request body*/;
Gson gson = new Gson();
String resourceResponse = operations.postForObject(/* url */, body, String.class);
JSONObject jsonResponse = new JSONObject(resourceResponse);
String jsonUserIdentifier = jsonResponse.getString("userIdentifier");
UserIdentifier userIdentifier = gson.fromJson(jsonUserIdentifier , UserIdentifier.class);
您可能需要使用 gson
class Name{
String resultCode;
UserIdentifier useridentifier;
//getters
}
Gson gson=new Gson();
Name name=gson.fromJson(jsonString,Name.class);
找出问题所在。需要提取 jsonobject 而不是获取字符串。这是解决问题的行:
UserIdentifier userIdentifier = gson.fromJson(jsonResponse.getJSONObject("userIdentifier").toString(), UserIdentifier.class);