从工厂返回控制器中的 $http promise 时未定义
Undefined when returning $http promise in controller from factory
无论我做什么,我总是接到 $$state
或 undefined
工厂的 API 电话。我已经尝试过 promises 并简单地从 .then
返回 response.data
但我没有尝试任何工作。
我可以将正确的响应数据输入我的控制器,但是当我尝试将它分配给任何东西时,我只得到 undefined
或 $$state
,具体取决于我使用的方法。
我的工厂:
factory('forecastFactory', function ($http, $q, SundialConfig) {
var Forecast = {};
var weatherKey = SundialConfig.openWeatherKey;
Forecast.dayCnt = 1;
Forecast.prepareCity = function (city) {
city === undefined ? city = 'Chicago, IL' : city = city;
return city;
}
Forecast.getForecast = function (city) {
var preparedCity = Forecast.prepareCity(city);
var deferred = $q.defer();
$http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
params: {
appid: weatherKey,
q: preparedCity,
cnt: Forecast.dayCnt,
callback: 'JSON_CALLBACK'
}
})
.then(function (res) {
console.log("success");
deferred.resolve(res);
})
.catch(function (err) {
console.log('error');
});
return deferred.promise;
}
return Forecast;
});
我的控制器:
controller('ForecastController', function ($scope, $location, forecastFactory, locationService) {
vm = this;
forecastFactory.getForecast('Chicago, IL').then(function (res) {
console.log(res);
vm.forecast = res;
});
});
我认为你不需要使用 $q
因为 $http return 是一个承诺,
你可以做到
Forecast.getForecast = function(city) {
var preparedCity = Forecast.prepareCity(city);
return $http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
params: {
appid: weatherKey,
q: preparedCity,
cnt: Forecast.dayCnt,
callback: 'JSON_CALLBACK'
}
})
.then(function(res) {
console.log("success");
return res.data;
})
.catch(function(err) {
console.log('error')
return []; // or {} depending upon required data
});
}
然后在控制器中,执行与现在相同的操作
其他方法只是 return 承诺 return 由 $http
编辑
Forecast.getForecast = function(city) {
var preparedCity = Forecast.prepareCity(city);
return $http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
params: {
appid: weatherKey,
q: preparedCity,
cnt: Forecast.dayCnt,
callback: 'JSON_CALLBACK'
}
})
}
并在控制器中执行此操作
Sundial.Controllers.
controller('ForecastController', ['$scope', '$location', 'forecastFactory', 'locationService', function($scope, $location, forecastFactory, locationService) {
vm = this;
forecastFactory.getForecast('Chicago, IL').then(function(res) {
console.log(res)
vm.forecast = res.data;
}, function(err){
// do something
})
}]);
无论我做什么,我总是接到 $$state
或 undefined
工厂的 API 电话。我已经尝试过 promises 并简单地从 .then
返回 response.data
但我没有尝试任何工作。
我可以将正确的响应数据输入我的控制器,但是当我尝试将它分配给任何东西时,我只得到 undefined
或 $$state
,具体取决于我使用的方法。
我的工厂:
factory('forecastFactory', function ($http, $q, SundialConfig) {
var Forecast = {};
var weatherKey = SundialConfig.openWeatherKey;
Forecast.dayCnt = 1;
Forecast.prepareCity = function (city) {
city === undefined ? city = 'Chicago, IL' : city = city;
return city;
}
Forecast.getForecast = function (city) {
var preparedCity = Forecast.prepareCity(city);
var deferred = $q.defer();
$http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
params: {
appid: weatherKey,
q: preparedCity,
cnt: Forecast.dayCnt,
callback: 'JSON_CALLBACK'
}
})
.then(function (res) {
console.log("success");
deferred.resolve(res);
})
.catch(function (err) {
console.log('error');
});
return deferred.promise;
}
return Forecast;
});
我的控制器:
controller('ForecastController', function ($scope, $location, forecastFactory, locationService) {
vm = this;
forecastFactory.getForecast('Chicago, IL').then(function (res) {
console.log(res);
vm.forecast = res;
});
});
我认为你不需要使用 $q
因为 $http return 是一个承诺,
你可以做到
Forecast.getForecast = function(city) {
var preparedCity = Forecast.prepareCity(city);
return $http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
params: {
appid: weatherKey,
q: preparedCity,
cnt: Forecast.dayCnt,
callback: 'JSON_CALLBACK'
}
})
.then(function(res) {
console.log("success");
return res.data;
})
.catch(function(err) {
console.log('error')
return []; // or {} depending upon required data
});
}
然后在控制器中,执行与现在相同的操作
其他方法只是 return 承诺 return 由 $http
编辑Forecast.getForecast = function(city) {
var preparedCity = Forecast.prepareCity(city);
return $http.jsonp('http://api.openweathermap.org/data/2.5/forecast/daily?', {
params: {
appid: weatherKey,
q: preparedCity,
cnt: Forecast.dayCnt,
callback: 'JSON_CALLBACK'
}
})
}
并在控制器中执行此操作
Sundial.Controllers.
controller('ForecastController', ['$scope', '$location', 'forecastFactory', 'locationService', function($scope, $location, forecastFactory, locationService) {
vm = this;
forecastFactory.getForecast('Chicago, IL').then(function(res) {
console.log(res)
vm.forecast = res.data;
}, function(err){
// do something
})
}]);