使用 SQL Server 2008 中所有重复行的列的总和显示 table 的不同行

Question

有两个table：

Tasks table :

    TaskName (PK)

TaskAllocation table :

     AllocationID(PK),
     TaskName(F.K to TaskName in 'Tasks' Table),
     UserID( F.K to ID in 'Users' Table),
     EngineerType( F.K to ID in 'EngineerType' Table),         
     Start Date,
     End Date, 
     Hours,
     Location

'Users' Table :

     ID,
     FirstName,
     LastName

'EngineerTypes' Table :

     ID,
     Type

每个任务可以有多个allocations.Hence，任务名称可以在任务分配中出现多次table。同一个任务可以映射到多个用户（UserID）

我需要显示所选任务（作为 U.I 的输入给出）、分配给该任务的用户 ID、开始日期的第一次出现、结束日期的第一次出现以及每个用户的总和（小时）所选任务的数量。

示例：TaskAllocation 数据：

     TaskName  UserID   TypeId StartDate EndDate Hours Location
      Task1    1          11    Feb 5     Feb 7   1     NULL
      Task1    1          11    Feb 6     Feb 7   2     NULL
      Task1    1          11    Feb 7     Feb 7   3     Onsite
      Task1    2          12    Feb 8     Feb 10  4     Offshore
      Task1    2          12    Feb 9     Feb 10  5     NULL
      Task1    2          12    Feb 10    Feb 10  6     NULL

     'EngineerTypes' data :
      ID   Type
      11   Type1
      12   Type2

     'Users' Data :
      ID     FirstName 
      1      Name1
      2      Name2

我执行的查询是：

                                                                                              Select TaskAllocation.UserId as UserId,Users.FirstName as Name,
                                                                    TaskAllocation.EngineerType as TypeId,EngineerTypes.Type as Type,
                                                       min(TaskAllocation.StartDate) as AllocationStartDate,
                                                                       max(TaskAllocation.EndDate) as AllocationEndDate,
                                                         sum(TaskAllocation.Hours) as Hours, TaskAllocation.Location
                                                                            from TaskAllocation join Users on TaskAllocation.UserId=Users.ID 
                                                                          join EngineerTypes on EngineerTypes.ID = TaskAllocation.EngineerType
                                                                         where TaskAllocation.TaskName = Task1' group by                               
     FirstName,UserId,EngineerType,Type,AllocationStartDate,AllocationEndDate,Hours,                                                                                      
                                                                                    Location,TaskName order by TaskName, UserId

输出：UserId 名称 TypeId 类型 AllocationStartDate AllocationEndDate 小时位置

    1. 126   Name1  11   Type1  2015-11-23      2015-11-25         0.1  NULL
    2. 126   Name1  11   Type1  2015-11-24      2015-11-25         0.2  NULL
    3. 126   Name1  11   Type1  2015-11-25      2015-11-25         0.3  NULL
    4. 127   Name2  12   Type2  2015-11-23      2015-11-25         0.2  NULL
    5. 127   Name2  12   Type2  2015-11-24      2015-11-25         0.3  NULL
    6. 127   Name2  12   Type2  2015-11-25      2015-11-25         0.4  NULL

Answer 1

您可以尝试以下方法

方法一：

select taskname,
userid,
min(startdate) as'first occurence',
max(enddate) as'last occurence'
,sum(hours)
 from t1
 group by taskname,userid

方法二：交叉应用

 select 
 distinct taskname,userid,b.*
 from t1
 cross apply
 (select min(startdate) as Firstoccur,max(startdate) as secondocc,sum(hours) as hrs
 from t1 t2 where t1.taskname =t2.taskname and t1.userid=t2.userid
 group by t2.taskname,t2.userid) b

方法三： Window 函数

 with cte
 as
 (
 select taskname,userid,
 min(startdate) over (partition by taskname,userid) as 'first',
 max(enddate) over (partition by taskname,userid) as 'second',
 sum(hours) over (partition by taskname,userid) as 'hrs',
 ROW_NUMBER() over (partition by taskname,userid order by taskname,userid) as rn
   from t1
   )
   select *from cte where rn=1

使用 SQL Server 2008 中所有重复行的列的总和显示 table 的不同行

Display distinct rows of a table with the sum of a column of all duplicate rows in SQL Server 2008

sql-server-2008

sum

distinct-values